(-3)-|-450|+(-7)+450
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1)\(\frac{450}{7}x\frac{2}{5}\)
=\(\frac{900}{35}\)=\(\frac{900:5}{35:5}=\frac{180}{7}\)
2)
\(\frac{450}{7}x\frac{1}{3}=\frac{450}{21}=\frac{450:3}{21:3}=\frac{150}{7}\)
\(\frac{450}{7}\)\(x\)\(\frac{2}{5}\)= \(\frac{180}{7}\)
\(\frac{450}{7}x\frac{1}{3}=\frac{150}{7}\)
Chúc bạn học tốt .k cho mk nhé
7 x 450 - 900 + 450 x 5
= 7 x 450 - 450 x 2 + 450 x 5
= 450 x (7 - 2 + 5)
= 450 x 10
= 4500
7 x 450 - 900 + 450 x 5
= 450 x 7 + 450 x 5 - 450 x 2
= 450 x (7 + 5 - 2)
= 450 x (12 - 2)
= 450 x 10
= 4500
Bài 1.
\(a,\left(2^4\cdot3\cdot5^2\right):\left\{450:\left[450-\left(4\cdot5^3-2^3\cdot5^2\right)\right]\right\}\)
\(=\left(16\cdot3\cdot25\right):\left\{450:\left[450- \left(4\cdot125-8\cdot25\right)\right]\right\}\)
\(=\left(48\cdot25\right):\left\{450:\left[450-\left(500-200\right)\right]\right\}\)
\(=1200:\left[450:\left(450-300\right)\right]\)
\(=1200:\left(450:150\right)\)
\(=1200:3\)
\(=400\)
\(---\)
\(b,3^3\cdot5^2-20\left\{90-\left[164-2\cdot\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=27\cdot25-20\left\{90-\left[164-2\cdot\left(7^2+1\right)\right]\right\}\)
\(=675-20\left\{90-\left[164-2\cdot\left(49+1\right)\right]\right\}\)
\(=675-20\left[90-\left(164-2\cdot50\right)\right]\)
\(=675-20\left[90-\left(164-100\right)\right]\)
\(=675-20\left(90-64\right)\)
\(=675-20\cdot26\)
\(=675-520\)
\(=155\)
\(---\)
\(c,\left[\left(18^7:18^6-17\right)\cdot2022-1986\right]\cdot5\cdot1^{2022}-13^2\cdot2020^0\)
\(=\left[\left(18-17\right)\cdot2022-1986\right]\cdot5\cdot1-169\cdot1\)
\(=\left(1\cdot2022-1986\right)\cdot5-169\)
\(=\left(2022-1986\right)\cdot5-169\)
\(=36\cdot5-169\)
\(=180-169\)
\(=11\)
Bài 2.
\(a) (2^x+1)^2+3\cdot(2^2+1)=2^2\cdot10\\\Rightarrow (2^x+1)^2+3\cdot(4+1)=4\cdot10\\\Rightarrow (2^x+1)^2+3\cdot5=40\\\Rightarrow (2^x+1)^2+15=40\\\Rightarrow (2^x+1)^2=40-15\\\Rightarrow (2^x+1)^2=25\\\Rightarrow (2^x+1)^2= (\pm 5)^2\\\Rightarrow \left[\begin{array}{} 2^x+1=5\\ 2^x+1=-5 \end{array} \right.\\ \Rightarrow \left[\begin{array}{} 2^x=4\\ 2^x=-6 (vô.lí) \end{array} \right. \\ \Rightarrow 2^x=2^2\\\Rightarrow x=2\)
Vậy \(x=2\).
\(---\)
\(b)3\cdot(x-7)+2\cdot(x+5)=41\\\Rightarrow 3\cdot x+3\cdot(-7)+2\cdot x+2\cdot5=41\\\Rightarrow 3x-21+2x+10=41\\\Rightarrow (3x+2x)+(-21+10)=41\\\Rightarrow 5x-11=41\\\Rightarrow 5x=41+11\\\Rightarrow 5x=52\\\Rightarrow x=\dfrac{52}{5}\)
Vậy \(x=\dfrac{52}{5}\).
\(Toru\)
312 + (146 -X ) =401
11- (15 + 21 ) + X- (25-9)
2- X +177 - (-5)
X -12 = (-9) - 15
Chọn C. (D ) = 45o
Ta có : hình thang ABCD CÓ BC//AD
=> ∠ (C )+ ∠ (D )= 180 0 ( hai góc trong cùng phía bù nhau)
mà ∠ C = 3 ∠ D nên 3 ∠ D+ ∠ D= 180 0 => ∠ D= 45 0
(-3) - |-450| + (-7) + 450
= -3 - 450 + (-7) + 450
= -3 - 7
= -10
k mik nha bn
(-3) - l-450l + (-7) + 450
= [450 - l-450l] + [(-7) + (-3)]
= 0 + (-10)
= -10