515+[72+(-515)+(-32)]
K
Khách
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7 tháng 4 2020
Bài 1 : Tính :
\(a)49-\left(-54\right)-23=103-23\)
\(=80\)
\(b)\left(-25\right).68+\left(-34\right).\left(-250\right)=-1700+8500\)
\(=6800\)
\(c)1999+\left(-2000\right)+2001+\left(-2002\right)=\left(-1\right)+\left(-1\right)\)
\(=-2\)
\(d)515+\left[72+\left(-515\right)+\left(-32\right)\right]=515+\left(-475\right)\)
\(=40\)
\(e)\left(2736-75\right)-2736+175=2661-2736+175\)
\(=100\)
\(g)-2020-\left(157-2020\right)-\left(-257\right)=-2020-\left(-1863\right)-\left(-257\right)\)
\(=100\)
LV
3
11 tháng 9 2018
936 - ( x + 24 ) = 72
936 - x - 24 = 72
912 - x=72
x=840
5 . (x + 35 ) = 515
x+35=515:5
x+35=103
x=68
(158 - x ) :7 = 20
158 - x=20x7
158 - x=140
x=18
11 tháng 9 2018
936-(x+24)=72
X+24=936-72
X+24=864
X=864-24
X=840
5.(x+35)=515
X+35=515:5
X+35=103
X=103-35
X=68
(158-x):7=20
158-x=20.7
158-x=140
X=158-140=18
K biết đúng hay sai hì hì, mong thông cảm ạ*cúi đầu*
14 tháng 4 2020
Bài 1: Tính
a) Ta có: \(\left(-25\right)\cdot68+\left(-34\right)\cdot\left(-250\right)\)
\(=-25\cdot68+\left(-340\right)\cdot\left(-25\right)\)
\(=-25\cdot\left(68-340\right)\)
\(=-25\cdot\left(-272\right)\)
\(=6800\)
b) Ta có: \(1999+\left(-2000\right)+2001+\left(-2002\right)\)
\(=1999-2000+2001-2002\)
\(=-1-1=-2\)
c) Ta có: \(515+\left[72+\left(-515\right)+\left(-32\right)\right]\)
\(=515+72-515-32\)
\(=40\)
d) Ta có: \(\left(2736-75\right)-2736+175\)
\(=2736-75-2736+175\)
\(=100\)
e) Ta có: \(-2020-\left(157-2020\right)-\left(-257\right)\)
\(=-2020-157+2020+257\)
\(=100\)
Bài 2: Tìm x
a) Ta có: \(x-\left|-2\right|=\left|-18\right|\)
\(\Leftrightarrow x-2=18\)
hay x=20
Vậy: x=20
b) Ta có: \(2x-\left|+14\right|=\left|-14\right|\)
\(\Leftrightarrow2x-14=14\)
\(\Leftrightarrow2x=28\)
hay x=14
Vậy: x=14
c) Ta có: \(\left|x+4\right|+5=20-\left(-12-7\right)\)
\(\Leftrightarrow\left|x+4\right|+5=20+12+7\)
\(\Leftrightarrow\left|x+4\right|=39-5=34\)
\(\Leftrightarrow\left[{}\begin{matrix}x+4=34\\x+4=-34\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=30\\x=-38\end{matrix}\right.\)
Vậy: x∈{30;-38}
d) Ta có: \(15-\left|2-x\right|=\left(-2\right)^2\)
\(\Leftrightarrow15-\left|2-x\right|=4\)
\(\Leftrightarrow\left|2-x\right|=11\)
\(\Leftrightarrow\left[{}\begin{matrix}2-x=11\\2-x=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=13\end{matrix}\right.\)
Vậy: x∈{-9;13}
e) Ta có: \(\left|15-x\right|+\left|-25\right|=\left|-55\right|\)
\(\Leftrightarrow\left|15-x\right|+25=55\)
\(\Leftrightarrow\left|15-x\right|=30\)
\(\Leftrightarrow\left[{}\begin{matrix}15-x=30\\15-x=-30\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-15\\x=45\end{matrix}\right.\)
Vậy: x∈{-15;45}
g) Ta có: \(\left|17-\left(-4\right)\right|+\left|-24-\left(-5\right)\right|=\left|-x+3\right|\)
\(\Leftrightarrow\left|17+4\right|+\left|-24+5\right|=\left|3-x\right|\)
\(\Leftrightarrow\left|3-x\right|=40\)
\(\Leftrightarrow\left[{}\begin{matrix}3-x=40\\3-x=-40\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-37\\x=43\end{matrix}\right.\)
Vậy: x∈{-37;43}
8 tháng 2 2017
\(515.\left(2-128.128\right).\left(-515\right)\)
\(=515.\left(2-16384\right).\left(-515\right)\)
\(=515.\left(-16382\right).\left(-515\right)\)
\(=\left(-8436730\right).\left(-515\right)\)
\(=4344915950\)
HV
1
3 tháng 8 2023
a) \(\dfrac{11}{2}=\dfrac{10+1}{2}=5+\dfrac{1}{2}\)
\(\dfrac{32}{9}=\dfrac{27+5}{9}=3+\dfrac{5}{9}< 5+\dfrac{1}{2}\)
Vậy \(\dfrac{11}{2}>\dfrac{32}{9}\)
b)\(\dfrac{100}{23}=\dfrac{92+8}{23}=4+\dfrac{8}{23}\)
\(\dfrac{302}{123}=\dfrac{246+56}{123}=2+\dfrac{56}{123}< 4+\dfrac{8}{23}\)
Vậy \(\dfrac{100}{23}>\dfrac{302}{123}\)
c) \(\dfrac{515}{605}< \dfrac{515+1}{605+1}=\dfrac{516}{606}\Rightarrow\dfrac{515}{605}< \dfrac{516}{606}\)
NT
1
515+[72+(-515)+(-32)]
=[515+(-515)]+[72+(-32)]
=0+40
=40