7×X-12=
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\(x-\dfrac{x}{12}+\dfrac{x}{\dfrac{18}{7}}-\dfrac{7}{12}+\dfrac{7}{18}=-\dfrac{4}{7}\)
\(\Rightarrow x\left(1-\dfrac{1}{12}+\dfrac{1}{\dfrac{18}{7}}\right)=-\dfrac{4}{7}+\dfrac{7}{12}-\dfrac{7}{18}\)
\(\Rightarrow x\left(\dfrac{216-18+7}{12.18}\right)=\dfrac{-864+882-588}{7.12.18}\)
\(\Rightarrow x\left(\dfrac{205}{12.18}\right)=\dfrac{-570}{7.12.18}\)
\(\Rightarrow x=\dfrac{-570}{7.12.18}.\dfrac{12.18}{205}\)
\(\Rightarrow x=\dfrac{-114}{287}\)
\(-\dfrac{7}{12}\cdot\dfrac{3}{8}+-\dfrac{7}{12}\cdot\dfrac{5}{8}+1\dfrac{7}{12}\)
\(=-\dfrac{7}{12}\cdot\left(\dfrac{3}{8}+\dfrac{5}{8}-1\right)\)
\(=-\dfrac{7}{12}\cdot\left(\dfrac{8}{8}-1\right)\)
\(=-\dfrac{7}{12}\cdot\left(1-1\right)\)
\(=-\dfrac{7}{12}\cdot0\)
\(=0\)
\(=\dfrac{11}{12}\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right)=\dfrac{11}{12}\cdot1=\dfrac{11}{12}\)
x : 7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144
\(d,=24x^2-38x+3\\ e,=x^2-12x+35\\ f,=\left(x^2-144\right)\left(4x-1\right)=4x^3-x^2-576x+144\)
(\(x\) - 12) : 4 = 7
\(x\) - 12 = 7 \(\times\) 4
\(x\) - 12 = 28
\(x\) = 28 + 12
\(x\) = 40
\(x\) - 12 : 4 = 7
\(x\) - 3 = 7
\(x\) = 7 + 3
\(x\) = 10
\(\left(x-12\right)\) : 4 = 7
<=> \(x-12\) = 7 x 4
<=> \(x-12\) = 28
<=> \(x\) = 40