2x+6=4x-8
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: \(=20x^2-25x-20x^2+24x-30=-x-30\)
b: \(\Leftrightarrow12x-6x^2+6x^2-15x=12\)
=>-3x=12
hay x=-4
\(\left(4x-8\right)\left(3x-6\right)>\left(4x-8\right)\left(2x+2\right)\)
\(\Leftrightarrow\)\(\left(4x-8\right)\left(3x-6\right)-\left(4x-8\right)\left(2x+2\right)>0\)
\(\Leftrightarrow\)\(\left(4x-8\right)\left(3x-6-2x-2\right)>0\)
\(\Leftrightarrow\)\(4\left(x-2\right)\left(x-8\right)>0\)
\(\Leftrightarrow\)\(\hept{\begin{cases}x-2>0\\x-8>0\end{cases}}\)hoặc \(\hept{\begin{cases}x-2< 0\\x-8< 0\end{cases}}\)
\(\Leftrightarrow\)\(\hept{\begin{cases}x>2\\x>8\end{cases}}\)hoặc \(\hept{\begin{cases}x< 2\\x< 8\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x>8\\x< 2\end{cases}}\)
Vậy...
a )
\(5x\left(4x-5\right)-4x\left(5x-6\right)=30\)
\(\Rightarrow20x^2-25x-20x^2+24x=30\)
\(\Rightarrow-x=30\)
\(\Rightarrow x=-30\)
Vậy ...
b )
\(2x\left(6-3x\right)+3x\left(2x-5\right)=12\)
\(\Rightarrow12x-6x^2+6x^2-15x=12\)
\(\Rightarrow-3x=12\)
\(\Rightarrow x=-4\)
Vậy ...
a) \(5x\left(4x-5\right)-4x\left(5x-6\right)-30\)
\(\Rightarrow20x^2-25x-20x^2+24x=30\)
\(\Rightarrow-1x=30\)
\(\Rightarrow x=-30\)
Vậy x = -30
b) \(2x\left(6-3x\right)+3x\left(2x-5\right)=12\)
\(\Rightarrow12x-6x^2+6x^2-15x=12\)
\(\Rightarrow-3x=12\)
\(\Rightarrow x=-4\)
Vậy x = -4
|\(x-\dfrac{1}{2}\)| + 2\(x\) = 6
|\(x-\dfrac{1}{2}\)| = 6 - 2\(x\); 6 - 2\(x\) > 0 ⇒ 6 > 2\(x\) ⇒ \(x\) < 3
\(\left[{}\begin{matrix}x-\dfrac{1}{2}=6-2x\\x-\dfrac{1}{2}=-6+2x\end{matrix}\right.\)
\(\left[{}\begin{matrix}x+2x=6+\dfrac{1}{2}\\2x-x=6-\dfrac{1}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}3x=\dfrac{13}{2}\\x=\dfrac{11}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{13}{6}\\x=\dfrac{11}{2}\end{matrix}\right.\)
\(x=\dfrac{11}{2}\) > 3 (loại)
Vậy \(x\) = \(\dfrac{13}{6}\)
19 22 25 28 5(3x + 2) – 4(2x +3) x*(1 + 2x) 4(1 + x) – 3(2x-5) 4x–8(6) - X) 23/ ... 2x” – 4x + 3x – 6 = 2x” – X-6 (b) (x-3) = (x-3)(x-3) (c) (2x+y)(2x–y) = x* = x* – 3x ... (x - 6)” 7 (3x + 5)(x-6) 8 (8x + 2)(3x + 4) (4x – 1)(2x – 3) 10 (2x +5)* 11 (8x – 3)(2x + ... 27 (4x + 3y)(x + y) 28 (2x + 5)(5x – 2) (4x – 3y)(4x + y) 30 (7x + 2y)(3x + 4y) 24/ ...
\(a)=3x\cdot\left(2x-7-4x+5\right)=3x\cdot\left(-2x-2\right)=3x\cdot\left[-2\cdot\left(x+1\right)\right]\)
=>4x-2x=6+8
=>2x =14
=>x=7
**** cho mk nha...Thanks bạn nhìu...:))
2x+6=4x-8
suy ra 6+8=4x-2x
suy ra 14=2x
suy ra x=7
k tớ nha