140/x - 150/x+5 = 1
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`(a+5)xx[(140/a)-1]=150`
`<=>(a+5).((140-a)/a)=150`
`<=>(a+5)(140-a)=150a`
`<=>140a-a^2+700-5a=150`
`<=>700+135a-a^2=150`
`<=>a^2-15a-700=0`
`Delta=225+2800=3025`
`<=>a_1=35,a_2=-20`
Vậy `S={35,-20}`.
\(\frac{150}{x-1}-\frac{140}{x}=5\)
\(ĐKXĐ:x\ne1;x\ne0\)
\(MTC:x\left(x-1\right)\)
\(\Leftrightarrow\frac{150x}{x\left(x-1\right)}-\frac{140\left(x-1\right)}{x\left(x-1\right)}=\frac{5x\left(x-1\right)}{x\left(x-1\right)}\)
\(\Rightarrow150x-140\left(x-1\right)=5x\left(x-1\right)\)
\(\Leftrightarrow150x-140x+140=5x^2-5x\)
\(\Leftrightarrow150x-140x+140-5x^2+5x=0\)
\(\Leftrightarrow-5x^2+15x+140=0\)
\(\Leftrightarrow-5x^2-20x+35x+140=0\)
\(\Leftrightarrow\left(-5x^2+35x\right)+\left(-20x+140\right)=0\)
\(\Leftrightarrow-5x\left(x-7\right)-20\left(x-7\right)=0\)
\(\Leftrightarrow\left(x-7\right)\left(-5x-20\right)=0\)
HOẶC \(x-7=0\Leftrightarrow x=7\)(nhận)
HOẶC\(-5x-20=0\Leftrightarrow x=-4\)(nhận)
VẬY TẬP NGHIỆM CỦA PT LÀ \(S=\left\{7;-4\right\}\)
\(\frac{150}{x-1}-\frac{140}{x}=5\)
\(\Leftrightarrow\frac{150x}{x\left(x-1\right)}-\frac{140\left(x-1\right)}{x\left(x-1\right)}=5\)
\(\Leftrightarrow\frac{150x-140\left(x-1\right)}{x\left(x-1\right)}=5\)
\(\Leftrightarrow\frac{150x-140x+140}{x\left(x-1\right)}=5\)
\(\Leftrightarrow\frac{10x+140}{x\left(x-1\right)}=5\)
\(\Leftrightarrow10x+140=5x\left(x-1\right)\)
\(\Leftrightarrow5\left(2x+28\right)=5x\left(x-1\right)\)
\(\Leftrightarrow2x+28=x\left(x-1\right)\)
\(\Leftrightarrow28=x\left(x-1\right)-2x\)
\(\Leftrightarrow28=x\left(x-1-2\right)\)
\(\Leftrightarrow28=x\left(x-3\right)\)
\(\Leftrightarrow x\left(x-3\right)=7.4=\left(-4\right)\left(-7\right)\)
\(\Leftrightarrow x\in\left\{7;-4\right\}\)
\(\frac{150}{x-1}-\frac{140}{x}=5\left(ĐKXĐ:x\ne1,x\ne0\right)\\ \Leftrightarrow\frac{150x-140\left(x-1\right)}{x\left(x-1\right)}=\frac{5x\left(x-1\right)}{x\left(x-1\right)}\\ \Leftrightarrow150x-140x+140=5x^2-5x\\5x^2-5x-10x-140=0\\ \Leftrightarrow5x^2-15x-140=0\\ \Leftrightarrow5\left(x^2-3x-28\right)=0\\ \Leftrightarrow5\left[\left(x^2-3x+\frac{9}{4}\right)-28-\frac{9}{4}\right]=0\\ \Leftrightarrow5\left[\left(x-\frac{1}{2}\right)^2-\frac{121}{4}\right]=0\\ \Leftrightarrow5\left(x-\frac{1}{2}-\frac{11}{2}\right)\left(x-\frac{1}{2}+\frac{11}{2}\right)=0\\ \Leftrightarrow5\left(x-6\right)\left(x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-6=0\\x+5=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=6\\x=-5\end{matrix}\right.\\ Vậy...\)
\(\frac{150}{x-1}-\frac{140}{x}=5\)
\(\Leftrightarrow\frac{150}{x-1}.x\left(x-1\right)-\frac{140}{x}.x\left(x-1\right)=5.x\left(x-1\right)\)
\(\Leftrightarrow150x-140\left(x-1\right)=5x\left(x-1\right)\)
\(\Leftrightarrow10x+140=5x^2-5x\)
\(\Leftrightarrow5x^2-5x=10x+140\)
\(\Leftrightarrow5x^2-5x-140=10x+140-140\)
\(\Leftrightarrow5x^2-5x-140=10x\)
\(\Leftrightarrow5x^2-5x-140=10x-10\)
\(\Leftrightarrow5x^2-5x-140=0\)
\(\Rightarrow\hept{\begin{cases}x=7\\x=-4\end{cases}}\)
Không chắc nha
\(\frac{150}{x-1}-\frac{140}{x-1}=5\left(ĐK:x\ne1\right)\)
\(\Leftrightarrow\frac{10}{x-1}=5\)
\(\Leftrightarrow x-1=2\)
\(\Leftrightarrow x=3\)
ĐKXĐ: x-1\(\ne\)0=> x\(\ne\)1
=> \(\frac{150-140}{x-1}\)=5
=> \(\frac{10}{x-1}\)=5
=> 10= 5(x-1)=> x-1=2=> x=1(ko thỏa mã ĐKXĐ x\(\ne\)1)
phương trình này vô nghiệm.
\(a,3\left(x+1\right)-2=4\)
\(\Leftrightarrow3\left(x+1\right)=6\)
\(\Leftrightarrow x+1=2\)
\(\Leftrightarrow x=1\)
Vậy x=1
Các câu còn lại lm tương tự nhé
\(3\left(x+1\right)-2=4\)
<=> \(3x+3-2=4\)
<=> \(3x=3\)
<=> \(x=1\)
\(5\left(x-2\right)+20=45\)
<=> \(5x-10=25\)
<=> \(x=7\)
\(700-7\left(x+2\right)=140\)
<=> \(7x+14=560\)
<=> \(7x=546\)
<=> \(x=78\)
\(200-5\left(2x+4\right)=100\)
<=> \(10x+20=100\)
<=> \(x=8\)
\(5\left(2x-4\right)+150=250\)
<=> \(10x-20=100\)
<=> \(x=12\)
học tốt
(1225 + 625) - 4x = 1000 - 150
=> 1850 - 4x = 950
=> 4x = 1850 - 950
=> 4x = 900
=> x = 900 : 4
=> x = 225
b) 43 - (24 - x) = 20
=> 24 - x = 43 - 20
=> 24 - x = 23
=> x = 24 - 23
=> x = 1
c) 245 - 5(16 + x) = 140
=> 5(16 + x) = 245 - 140
=> 5(16 + x) = 105
=> 16 + x = 105 : 5
=> 16 + x = 21
=> x = 21 - 16
=> x = 5
=>\(\dfrac{140x+700-150x}{x\left(x+5\right)}=1\)
=>x^2+5x=-10x+700
=>x^2+15x-700=0
=>(x+35)(x-20)=0
=>x=20 hoặc x=-35