tìm x : 2.(3/4 -5.x)=4/5-3.x
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1 tháng 10 2021
\(a,\Leftrightarrow\left|x+\dfrac{2}{5}\right|=\dfrac{7}{4}\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{2}{5}=\dfrac{7}{4}\left(x\ge-\dfrac{2}{5}\right)\\x+\dfrac{2}{5}=-\dfrac{7}{4}\left(x< -\dfrac{2}{5}\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{27}{20}\left(tm\right)\\x=-\dfrac{43}{20}\left(tm\right)\end{matrix}\right.\)
\(b,\Leftrightarrow\left|x-\dfrac{13}{10}\right|=\dfrac{13}{10}\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{13}{10}=\dfrac{13}{10}\left(x\ge\dfrac{13}{10}\right)\\x-\dfrac{13}{10}=-\dfrac{13}{10}\left(x< \dfrac{13}{10}\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{13}{5}\left(tm\right)\\x=0\left(tm\right)\end{matrix}\right.\)
\(c,\Leftrightarrow\left|\dfrac{3}{4}-\dfrac{1}{2}x\right|=\dfrac{1}{2}\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{4}-\dfrac{1}{2}x=\dfrac{1}{2}\left(x\le\dfrac{3}{2}\right)\\\dfrac{1}{2}x-\dfrac{3}{4}=\dfrac{1}{2}\left(x>\dfrac{3}{2}\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\left(tm\right)\\x=\dfrac{5}{2}\left(tm\right)\end{matrix}\right.\)
\(d,\Leftrightarrow\left|5-2x\right|=4\Leftrightarrow\left[{}\begin{matrix}5-2x=4\left(x\le\dfrac{5}{2}\right)\\2x-5=4\left(x>\dfrac{5}{2}\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\left(tm\right)\\x=\dfrac{9}{2}\left(tm\right)\end{matrix}\right.\)
\(đ,\Leftrightarrow\left\{{}\begin{matrix}x-3,5=0\\x-1,3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3,5\\x=1,3\end{matrix}\right.\left(vô.lí\right)\Leftrightarrow x\in\varnothing\)
\(e,\Leftrightarrow\left\{{}\begin{matrix}x-2021=0\\x-2022=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2021\\x=2022\end{matrix}\right.\left(vô.lí\right)\Leftrightarrow x\in\varnothing\)
\(f,\Leftrightarrow\left|x\right|=\dfrac{1}{3}-x\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}-x\left(x\ge0\right)\\x=x-\dfrac{1}{3}\left(x< 0\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{6}\left(tm\right)\\0x=-\dfrac{1}{3}\left(vô.lí\right)\end{matrix}\right.\Leftrightarrow x=\dfrac{1}{6}\)
\(g,\Leftrightarrow\left[{}\begin{matrix}x-2=x\left(x\ge2\right)\\2-x=x\left(x< 2\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}0x=2\left(vô.lí\right)\\x=1\left(tm\right)\end{matrix}\right.\Leftrightarrow x=1\)
2
23 tháng 5 2023
Đề trước đó:
(x-7)(x+1)-(x-3)^2=(3x-5)(3x+5)-(3x+1)^2+(x-2)^2-x
<=>x^2+x-7x-7-x^2+6x-9=9x^2-25-9x^2-6x-1+x^2-4x+4-x
<=>x^2-11x-6=0
<=>x^2-2x. 11/2 + 121/4-145/4=0
<=>(x-11/2)^2=145/4
<=>|x-11/2|=căn(145)/2
<=>x=[11+-căn(145)]/2
TL
2 tháng 1 2023
a. \(NT_x=2NT_O=2.16=32\left(đvC\right)\)
\(\Rightarrow NT_x\) là lưu huỳnh S
b. \(3NT_x=4NT_{Mg}=4.24=96\left(đvC\right)\Rightarrow NT_x=96:3=32\left(đvC\right)\)
\(\Rightarrow NT_x\) là lưu huỳnh S
TN
2 tháng 1 2023
A)
x =2.16 =) x = 32
Vậy nguyên tố x là : Supfur
Kí hiệu : S
B)
4. 24 = 3x =) x = 96:3 =) x=32
Vậy nguyên tố x là : Supfur
Kí hiệu : S
7 tháng 12 2021
d: \(\dfrac{x}{x+3}=\dfrac{x^2-3x}{\left(x+3\right)\left(x-3\right)}\)
\(\dfrac{1}{3-x}=\dfrac{-1}{x-3}=\dfrac{-x-3}{\left(x-3\right)\left(x+3\right)}\)
\(\dfrac{1}{x^2-9}=\dfrac{1}{\left(x+3\right)\left(x-3\right)}\)
7 tháng 10 2021
\(x:\left[\dfrac{8}{5}\cdot\left(\dfrac{2}{3}\right)^2-\dfrac{2}{5}\right]=\dfrac{15}{7}+\dfrac{6}{5}\left[\left(2\dfrac{1}{7}\right)^2-\dfrac{50}{49}\right]\)
\(\Leftrightarrow x:\left[\dfrac{32}{45}-\dfrac{18}{45}\right]=\dfrac{15}{7}+\dfrac{6}{5}\cdot\left(\dfrac{225}{49}-\dfrac{50}{49}\right)\)
\(\Leftrightarrow x:\dfrac{14}{45}=\dfrac{15}{7}+\dfrac{6}{5}\cdot\dfrac{25}{7}\)
\(\Leftrightarrow x:\dfrac{14}{45}=\dfrac{45}{7}\)
\(\Leftrightarrow x=2\)
NQ
4
21 tháng 2 2018
\(\frac{3}{x-5}=-\frac{4}{x+2}\)
=> 3 ( x + 2 ) = 4 ( x - 5 )
=> 3x + 6 = 4x - 20
=> 3x - 4x = - 6 - 20
=> - 1x = - 26
=> x = 26
21 tháng 2 2018
1) 3/x-5=-4/x+2
3x+6=-4x+20
7x . =14
x . =2
2) x+3/-4=-9/x+3
(x+3)^2=36
Ta có hai trường hợp:
*x+3=6=)x=3
*x+3=-6=)x=-9
18 tháng 8 2021
Ta có: \(\left(2x+3\right)\left(x-4\right)+\left(x+5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
\(\Leftrightarrow2x^2-8x+3x-12+x^2-2x+5x-10=3x^2-12x-5x+20\)
\(\Leftrightarrow-2x-22+17x-20=0\)
\(\Leftrightarrow15x=42\)
hay \(x=\dfrac{14}{5}\)
6 tháng 1 2017
a) -5 . (2 - x) + 4(x - 3) = 10x - 15
-10 + 5x + 4x -12 = 10x - 15
5x + 4x - 10x = -15 + 10 + 12
-x = 7
x = -7
b) 5 . (3 - 2x) + 5 . (x - 4) = 6 - 4x
15 - 10x + 5x - 20 = 6 - 4x
-10x + 5x + 4x = 6 - 15 + 20
-x = 11
x = -11
c) - 7 . (3x - 5) + 2 . (7x - 14) = 28
-21x + 35 + 14x - 28 = 28
-21x + 14x = 28 - 35 + 28
-7x = 21
x = 21 : (-7)
x = -3
d) 4 . (x - 5) - 3 . (x + 7) = 5 . (-4)
4x - 20 - 3x - 21 = -20
4x - 3x = -20 + 20 + 21
x = 21
e) 5 . (4 - x) - 7. (-x + 2) = 4 - 9 + 3
20 - 5x + 7x - 14 = -2
-5x + 7x = -2 - 20 + 14
2x = -8
x = -8 : 2
x = -4
Đúng 100%
6 tháng 1 2017
câu c
- 7 ( 3x - 5 ) + 2 ( 7x - 14 ) = 28
- 21x + 35 + 14x - 28 = 28
21x - 14x = 35 - 28 - 28
7x = - 21
x = ( - 21) : 7
x = - 3
\(2.\left(\frac{3}{4}-5.x\right)=\frac{4}{5}-3x\)
\(\Leftrightarrow\frac{3}{2}-10.x=\frac{4}{5}-3.x\)
\(\Leftrightarrow-10.x+3x=\frac{4}{5}-\frac{3}{2}\)
\(\Leftrightarrow x\left(-10+3\right)=\frac{-7}{10}\)
\(\Leftrightarrow x.\left(-7\right)=\frac{-7}{10}\)
\(\Leftrightarrow x=\frac{-7}{10}:\left(-7\right)\)
\(\Leftrightarrow x=\frac{1}{10}\)
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