\(\frac{3}{5}\)+ X x \(\frac{2}{7}\)= \(\frac{11}{12}\)
Tìm X: nhé
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mik ko chép lại đề, mik làm luôn:
a) x - \(\frac{31}{36}=\frac{-13}{38}\)
x = \(\frac{-13}{18}+\frac{31}{36}\)
\(x=\frac{5}{36}\)
b)\(2-x-\frac{3}{7}=\frac{9}{-21}\)
\(\frac{11}{7}-x=\frac{3}{7}\)
x = \(\frac{11}{7}-\frac{3}{7}\)
x = 8/7
c) x + 3/11 = 23/44
x = 23/44 - 3/11
x = 1/4
d) \(\frac{1}{12}-x=\frac{-11}{9}\)
x = \(\frac{1}{12}+\frac{11}{9}\)
x = 47/36
e) \(x-\frac{2}{3}=\frac{-17}{3}\)
x= -17/3 + 2/3
x = -5
f) \(x-\frac{1}{2}=\frac{11}{4}.\frac{3}{11}\)
x - 1/2 = 3/4
x = 3/4 + 1/2
x = 5/4
g) \(2x+\frac{3}{8}=\frac{-21}{32}.\frac{4}{7}\)
2x + 3/8 = -3 / 8
2x = -3/8 - 3/8
2x = -9/8
x = -9/8.1/2
x = -9/16
h) x - \(\frac{x}{3}=\frac{3}{57}.\frac{19}{12}\)
x - \(\frac{x}{3}=\frac{1}{12}\)
x = \(\frac{1}{12}+\frac{x}{3}\)
x = \(\frac{1+4x}{12}\)
=> 12x = 1+4x
12x - 4x = 1
8x = 1
x = 1/8
\(a,\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}\)
Cách 1: \(\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}=1\times\frac{3}{7}=\frac{10}{7}\)
Cách 2: \(\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}=\frac{6}{11}\times\frac{3}{7}+\frac{5}{11}\times\frac{3}{7}=\frac{18}{77}+\frac{15}{77}=\frac{33}{77}=\frac{3}{7}\)
\(b,\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}\)
Cách 1: \(\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}=\frac{7}{15}+\frac{2}{15}=\frac{9}{15}\)
Cách 2: \(\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}=\frac{3}{5}\times1=\frac{3}{5}\)
P/s: Ý B có vấn đề thì phải
\(a,\left(\frac{6}{11}+\frac{5}{11}\right)x\frac{3}{7}\)
\(=\frac{11}{11}=1x\frac{3}{7}\)
\(=\frac{3}{7}\)
cach 2
\(\frac{6}{11}x\frac{3}{7}+\frac{5}{11}x\frac{3}{7}\)
\(=\frac{18}{77}+\frac{15}{77}\)
\(=\frac{33}{77}=\frac{3}{7}\)
\(b,\frac{3}{5}x\frac{7}{9}+\frac{3}{5}x\frac{2}{9}\)
\(=\frac{21}{45}+\frac{6}{45}\)
\(=\frac{27}{45}=\frac{3}{5}\)
cách 2 :
\(\frac{3}{5}x\left(\frac{7}{9}+\frac{2}{9}\right)\)
\(=\frac{3}{5}x\frac{9}{9}\)
\(=\frac{27}{45}=\frac{3}{5}\)
\(\frac{1}{3}x-1.2x-\frac{2}{23}.\left(\frac{-11}{12}+\frac{5}{6}-\frac{7}{8}\right)-\frac{1}{8}=-11\frac{2}{3}+12\frac{7}{8}\)
\(\Leftrightarrow\frac{1}{3}x-\frac{6}{5}x-\frac{2}{23}.\frac{-23}{24}-\frac{1}{8}=\frac{-35}{3}+\frac{103}{8}\)
\(\Leftrightarrow\frac{-13}{15}x+\frac{1}{12}-\frac{1}{8}=\frac{29}{24}\)
\(\Leftrightarrow\frac{-13}{15}x-\frac{1}{24}=\frac{29}{24}\)
\(\Leftrightarrow\frac{-13}{15}x=\frac{5}{4}\)
\(\Leftrightarrow x=\frac{-75}{52}\)
Vậy \(x=\frac{-75}{52}\)
1/3x-1/2x-2/23.(-11/12+5/6-7/8)-1/8=-31/3+103/8
1/3x-1,2x-2/23.(-11/12+5/6-7/8)-1/8=61/24
1/3x-1,2x-2/23.-23/24-1/8=61/24
1/3x-1,2x-1/12-1/8=61/24
1/3x-1,2x+1/24=61/24
x.(1/3-1,2)+1/24=61/24
x.-13/15+1/24=61/24
x.-33/40=61/24
x=61/24:-33/40
x=61/24×-40/33
x=-305/99
vậy x=-305/99
B1
(x+2/1010)+(x+2/1111)=(x+2/1212)+(x+2/1313)
=>(x+2/1010)+(x+2/1111)-(x+2/1212)-(x-2/1313)=0
(x+2).[(1/1010)+(1/1111)-(1/1212)-(1/1313)]
Vì [(1/1010)+(1/1111)-(1/1212)-(1/1313) khác 0
=>x+2=0
=>x=-2
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
3/5 + x * 2/7 = 11/12
x * 2/7 = 11/12 - 3/5
x * 2/7 = 19/60
x = 19/60 : 2/7
x = 133/120