x+7/15 = -24/36
Tim x
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a: -26-(x-7)=0
=>x-7=-26
=>x=-26+7=-19
b: \(24-\left(30+x\right)=-7\)
=>\(30+x=24-\left(-7\right)\)
=>\(x+30=24+7=31\)
=>x=31-30=1
c: \(3-\left(17-x\right)=-12\)
=>\(17-x=3-\left(-12\right)\)
=>\(17-x=3+12=15\)
=>x=17-15=2
d: \(\left(5-x\right)-7=-15\)
=>\(5-x=-15+7=-8\)
=>\(x=5-\left(-8\right)=5+8=13\)
Bài 2:
a: Ta có: \(2x+79=x+45\)
nên 2x-x=45-79
hay x=-24
b: Ta có: \(15-\left(x+7\right)=\left(x-8\right)+22\)
\(\Leftrightarrow8-x-x-14=0\)
\(\Leftrightarrow2x=22\)
hay x=11
a, \(x\) - \(\dfrac{2}{7}\) = \(\dfrac{4}{5}\) \(\times\) \(\dfrac{15}{24}\)
\(x\) - \(\dfrac{2}{7}\) = \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{1}{2}\) + \(\dfrac{2}{7}\)
\(x\) = \(\dfrac{11}{14}\)
b, \(x\): \(\dfrac{2}{7}\) = \(\dfrac{9}{8}\) - \(\dfrac{15}{6}\)
\(x\): \(\dfrac{2}{7}\) = - \(\dfrac{11}{8}\)
\(x\) = - \(\dfrac{11}{8}\) \(\times\) \(\dfrac{2}{7}\)
\(x\) = - \(\dfrac{11}{28}\)
a \(x=\dfrac{2}{15}:\dfrac{4}{15}\)
\(x=\dfrac{2}{15}\times\dfrac{15}{4}\)
\(x=\dfrac{1}{2}\)
b \(\dfrac{7}{24}+x=\dfrac{7}{4}\)
\(x=\dfrac{7}{4}-\dfrac{7}{24}\)
\(x=\dfrac{42}{24}-\dfrac{7}{24}\)
\(x=\dfrac{35}{24}\)
x=-2/3-7/15=-17/15
\(x+\dfrac{7}{15}=\dfrac{-24}{36}\\ x=\dfrac{-24}{36}-\dfrac{7}{15}\\ x=\dfrac{-2}{3}-\dfrac{7}{15}\\ x=\dfrac{-10}{15}-\dfrac{7}{15}\\ x=\dfrac{-17}{15}\)