tìm x
X x 25=15/4
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y \(\times\) \(\dfrac{16}{64}\) + y \(\times\) \(\dfrac{25}{100}\) + y \(\times\) \(\dfrac{1}{4}\) + y \(\times\) \(\dfrac{15}{60}\) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y \(\times\) ( \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\)) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y = \(\dfrac{17}{15}\) + \(\dfrac{13}{15}\)
y = \(\dfrac{30}{15}\)
y = 2
Cái này bằng rủ em chơi oẳn tù tì ,em ra lá còn anh ra hôn má em
a, 15 - ( 4 - x ) = 6
⇒ 15 - 4 + x = 6
⇒ 11+ x = 6
⇒ x = -5
c, x - ( 12 - 25 ) = -8
⇒ x + 13 = -8
⇒ x = -21
d, ( x - 29 ) - ( 17 - 38 ) = -9
⇒ x - 29 + 21 = -9
⇒ x - 8 = -9
⇒ x = -1
b, - 30 + ( 25 - x ) = -1
⇒ - 30 + 25 - x = -1
⇒ -5 - x = -1
⇒ x = -4
a, \(15-4+x=6\) ⇒ \(11-x=6\) ⇒ \(x=5\)
b, \(-30+25-x=-1\) ⇒ \(-5-x=-1\) ⇒ \(x=-4\)
c, \(x-12+25=-8\Rightarrow x+13=-8\) ⇒ \(x=-21\)
d, \(x-29-17+38=-9\Rightarrow x-8=-9\Rightarrow x=-1\)
1: =>x=8-35=-27
2: =>15-4+x=6
=>x+11=6
hay x=-5
3: =>-30+25-x=-1
=>x+5=1
hay x=-4
4: =>x-(-13)=-8
=>x+13=-8
hay x=-21
5: =>x-29-17+38=-9
=>x-8=-9
hay x=-1
a) \(x\times15+x\times13=560\times45\)
\(\Rightarrow x\times\left(15+13\right)=25200\)
\(\Rightarrow x\times28=25200\)
\(\Rightarrow x=25200:28\)
\(\Rightarrow x=900\)
\(x\) \(\times\) \(\dfrac{4}{5}\) = 15
\(x\) = 15 : \(\dfrac{4}{5}\)
\(x\) = \(\dfrac{75}{4}\)
\(\dfrac{12}{25}\) \(\times\) \(x\) = \(\dfrac{4}{10}\)
\(x\) = \(\dfrac{4}{10}\) : \(\dfrac{12}{25}\)
\(x\) = \(\dfrac{5}{6}\)
Lời giải:
a.
$23+x=15$
$x=15-23=-8$
b.
$x-18=-23$
$x=-23+18=-5$
c.
$x+(-4)=16$
$x=16-(-4)=16+4=20$
d.
$25-x=-16$
$x=25-(-16)=25+16=41$
e.
$(-35)x=-210$
$x=(-210):(-35)=6$
f.
$(-2)(15-x)=60$
$15-x=60:(-2)=-30$
$x=15-(-30)=15+30=45$
a) \(5\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
b) \(25\left(x-4\right)=0\)
\(\Rightarrow x-4=0\)
\(\Rightarrow x=4\)
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
a) 5.(x-7)=0⇔x-7=0⇔x=7
b) 25(x-4)=0⇔x-4=0⇔x=4
c) (34-2x).(2x-6)=0
⇔ 34-2x=0 hoặc 2x-6=0
⇔2x=34 hoặc 2x=6
⇔ x=17 hoặc x=3
d) (2019-x).(3x-12)=0
⇔ 2019-x=0 hoặc 3x-12=0
⇔ x=2019 hoặc x=4
e) 57.(9x-27)=0
⇔ 9x-27=0
⇔ x=3
f) 25+(15-x)=30
⇔ 15-x=5
⇔ x=10
g) 43-(24-x)=20
⇔ 24-x=23
⇔ x=1
h) 2.(x-5)-17=25
⇔ 2(x-5)=42
⇔x-5=21
⇔ x=26
i) 3(x+7)-15=27
⇔ 3(x+7)=42
⇔ x+7=14
⇔ x=7
j) 15+4(x-2)=95
⇔ 4(x-2)=80
⇔ x-2=20
⇔ x=22
k) 20-(x+14)=5
⇔ x+14=15
⇔ x=1
l) 14+3(5-x)=27
⇔ 3(5-x)=13
⇔ 5-x=13/3
⇔ x=5-13/3
⇔ x=2/3
x=3/20