Tìm x thuộc Z:
a) -17 . |x| = -51
b) -7 .|x + 3| = -7^2
c) 4.x - 15 = -75 - x
d) 72 - 3x = 5x = 8
e) ( x - 2)^2 + 5 = 21
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1) x - 2 = -6
x = - 6 + 2
x = -4
2) -5x-(-3)=13
-5x+3=13
-5x=13-3=10
x=10:(-5)
x=-2
3) 15-(x-7)=21
15-x+7=21
15-x=21-7=14
x=15-14=1
4) 3x+17=2
3x=2-17=-15
x=-15:3=-5
5) 45-(x-9)=-35
45-x+9=-35
45-x=-35-9=-44
x=45-(-44)=89
6) -5+x=15
x=15-(-5)
x=20
7) 2x-(-17)=15
2x+17=15
2x=15-17=-2
x=-2:2=-1
a/ \(4x-15=75-x\)
\(\Leftrightarrow4x+x=75+15\)
\(\Leftrightarrow5x=90\)
\(\Leftrightarrow x=19\)
Vậy ...
b/ \(72-3x=5x+8\)
\(\Leftrightarrow72-8=5x+3x\)
\(\Leftrightarrow64=8x\)
\(\Leftrightarrow x=8\)
Vậy ....
c/ \(3\left|x-7\right|=21\)
\(\Leftrightarrow\left|x-7\right|=7\)
\(\Leftrightarrow\left[{}\begin{matrix}x-7=7\\x-7=-7\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=7\\x=0\end{matrix}\right.\)
d/ \(x-3\inƯ\left(7\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=1\\x-3=7\\x-3=-1\\x-3=-7\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=10\\x=2\\x=-4\end{matrix}\right.\)
Vậy ..
1) 3x - 6= 5x + 2
5x - 3x = -6 - 2
2x = -8
x = -4
2) 15 - x = 4x - 5
4x + x = 15 + 5
5x = 20
x = 4
Tương tự như trên
1) -5x - (-3) = 13
\(\Rightarrow-5x+3=13\)
\(\Rightarrow-5x=10\)
\(\Rightarrow x=-2\)
Vậy: \(x=-2\)
2) 15 - ( x - 7) = -21
\(\Rightarrow15-x+7=-21\)
\(\Rightarrow15+7-x=-21\)
\(\Rightarrow22-x=-21\)
\(\Rightarrow x=-22-21=-43\)
Vậy: \(x=-43\)
3) 45 - ( x - 9) = -35
\(\Rightarrow45-x+9=-35\)
\(\Rightarrow45+9-x=-35\)
\(\Rightarrow54-x=-35\)
\(\Rightarrow x=-54-35=-89\)
Vậy: \(x=-89\)
4)/x-2/=3\(\Rightarrow\)ta có 2 t/h:
t/h1: x-2=3\(\Rightarrow\)x=2+3=5
t/h2: x-2=-3\(\Rightarrow\)x=2+(-3)=-1
Vậy x=5 hoặc -1
a, 4x - 15 = ( -75 ) - x
<=> 4x +x = -75 + 15
<=> 5x = -60
<=> x = -12
b, 72 - 3x = 5x +8
<=> 72 - 8 = 5x + 3x
<=> 8x = 64
<=> x = 8
c, 3.|x-7| = 21
* Nếu x - 7 \(\ge\)0 <=> x \(\ge\)7 thì
PT <=> 3 .( x- 7 ) = 21
<=> x - 7 = 7
<=> x = 14 ( tm )
* Nếu x < 7 <=> x < 7 thì
PT <=> 3. [ - ( x- 7 ) ] = 21
<=> -x +7 = 7
<=> -x = 0
<=> x = 0 ( tm )
d, \(-7.|x+3|=-49\).
\(\Leftrightarrow|x+3|=7\)
\(\Leftrightarrow\orbr{\begin{cases}x+3=7\\x+3=-7\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=-10\end{cases}}}\)
e, c-12.(x-5)+7.(3-x)=5
<=> -12x + 60 + 21 - 7x = 5
<=> -19x + 81 = 5
<=> -19x = -76
<=> x = 4
a, 4x -15=-75-x b,72-3x= 5x+8
4x+x=-75+15 -3x-5x=8-72
5x=-60 -8x=-64
x=-60:5 8x=64
x=-14 x=64:8
x=8
c,3Ix-7I=21 d,-7Ix+3I=-49
Ix-7I=21:3 Ix+3I=-49:-7
Ix-7I=7 Ix+3I=7
x-7=7 hoặc x-7=-7 x+3=7 hoặc x+3=-7
x=14 hoặc x=0 x=4 hoặc x=-10