(-8/7)^x=-27/64
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5 + ( x + 27 ) = 64
( x + 27 ) = 64 - 5 ( x + 27 ) = 59 x = 59 - 27 x = 32a) \(\Rightarrow x+27=59\Rightarrow x=32\)
b) \(\Rightarrow x-2=39\Rightarrow x=41\)
c) \(\Rightarrow x+5=-322\Rightarrow x=-327\)
d) \(\Rightarrow5x=35\Rightarrow x=7\)
e) \(\Rightarrow4\left(x-5\right)=56\Rightarrow x-5=14\Rightarrow x=19\)
f) \(\Rightarrow15+x=37\Rightarrow x=22\)
g) \(\Rightarrow7\left(13-x\right)=35\Rightarrow13-x=5\Rightarrow x=8\)
h) \(\Rightarrow10\left(x+1\right)=100\Rightarrow x+1=10\Rightarrow x=9\)
Viết tch sau dưới dạng lũy thừa của 1 số nguyên.
a) (-27).8.(-125).(-64)
b) (-7).8.(-49).(-64).(-1000)
a) = (-3)3 . 23. (-5)3 . (-4)3
= (-3 . 3 . (-5) . (-4) )3
= (-180)3
a, 410. 230=220.230=250
b,925.274.813= 350.312.312=374
Tương tự các câu khác....
a, 410.230 = (22)10.230 = 220.230 = 250
b, 925.274.813 = (32)25.(33)4.(34)3 = 350.312.312 = 374
c, 2550.1255 = (52)50.(53)5 = 5100.515 = 5115
d, 643.48.164 = (26)3.(22)8.(24)4 = 218.216.216 = 250
e, 38 : 36 = 32
210 : 83 = 210 : (23)3 = 210 : 29 = 2
127 : 67 = (12 : 6)7 = 27
@Dương Tuyết Mai
1) \(\dfrac{1}{27}+a^3=\left(\dfrac{1}{3}+a\right)\left(\dfrac{1}{9}-\dfrac{a}{3}+a^2\right)\)
2) \(=\left(2x+3y\right)\left(4x^2-6xy+9y^2\right)\)
3) \(=\left(\dfrac{1}{2}x+2y\right)\left(\dfrac{1}{4}x-xy+4y^2\right)\)
4) \(=\left(x^2+1\right)\left(x^4-x^2+1\right)\)
5) \(=\left(x^3+1\right)\left(x^6-x^3+1\right)\)
6) \(=\left(x-4\right)\left(x^2+4x+16\right)\)
7) \(=\left(x-5\right)\left(x^2+5x+25\right)\)
8) \(=\left(2x^2-3y\right)\left(4x^4+6x^2y+9y^2\right)\)
9) \(=\left(\dfrac{1}{4}x^2-5y\right)\left(\dfrac{1}{16}x^4+\dfrac{5}{4}x^2y+25y^2\right)\)
10) \(=\left(\dfrac{1}{2}x-2\right)\left(\dfrac{1}{4}x^2+x+4\right)\)
11) \(=\left(x+2\right)^3\)
12) \(=\left(x+3\right)^3\)
a: x^3=7^3
=>x^3=343
=>\(x=\sqrt[3]{343}=7\)
b: x^3=27
=>x^3=3^3
=>x=3
c: x^3=125
=>x^3=5^3
=>x=5
d: (x+1)^3=125
=>x+1=5
=>x=4
e: (x-2)^3=2^3
=>x-2=2
=>x=4
f: (x-2)^3=8
=>x-2=2
=>x=4
h: (x+2)^2=64
=>x+2=8 hoặc x+2=-8
=>x=6 hoặc x=-10
j: =>x-3=2 hoặc x-3=-2
=>x=1 hoặc x=5
k:
9x^2=36
=>x^2=36/9
=>x^2=4
=>x=2 hoặc x=-2
l:
(x-1)^4=16
=>(x-1)^2=4(nhận) hoặc (x-1)^2=-4(loại)
=>x-1=2 hoặc x-1=-2
=>x=3 hoặc x=-1
a: \(\dfrac{x^3}{8}=\dfrac{y^3}{64}=\dfrac{z^3}{216}\)
=>\(\left(\dfrac{x}{2}\right)^3=\left(\dfrac{y}{4}\right)^3=\left(\dfrac{z}{6}\right)^3\)
=>\(\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{6}\)
=>\(\dfrac{x}{1}=\dfrac{y}{2}=\dfrac{z}{3}\)
Đặt \(\dfrac{x}{1}=\dfrac{y}{2}=\dfrac{z}{3}=k\)
=>x=k; y=2k; z=3k
\(x^2+y^2+z^2=14\)
=>\(k^2+4k^2+9k^2=14\)
=>\(14k^2=14\)
=>\(k^2=1\)
=>k=1 hoặc k=-1
TH1: k=1
=>\(x=k=1;y=2k=2\cdot1=2;z=3k=3\cdot1=3\)
TH2: k=-1
=>\(x=k=-1;y=2k=2\cdot\left(-1\right)=-2;z=3k=3\cdot\left(-1\right)=-3\)
b: \(\dfrac{x^3}{8}=\dfrac{y^3}{27}=\dfrac{z^3}{64}\)
=>\(\left(\dfrac{x}{2}\right)^3=\left(\dfrac{y}{3}\right)^3=\left(\dfrac{z}{4}\right)^3\)
=>\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\)
Đặt \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=k\)
=>x=2k; y=3k; z=4k
\(x^2+2y^2-3z^2=-650\)
=>\(\left(2k\right)^2+2\cdot\left(3k\right)^2-3\cdot\left(4k\right)^2=-650\)
=>\(4k^2+18k^2-3\cdot16k^2=-650\)
=>\(-26\cdot k^2=-650\)
=>\(k^2=25\)
=>\(\left[{}\begin{matrix}k=5\\k=-5\end{matrix}\right.\)
TH1: k=5
=>\(x=2\cdot5=10;y=3\cdot5=15;z=4\cdot5=20\)
TH2: k=-5
=>\(x=2\cdot\left(-5\right)=-10;y=3\cdot\left(-5\right)=-15;z=4\cdot\left(-5\right)=-20\)
=> [x -1/8]^3 = [3/4]^3
=> x-1/8 = 3/4
=> x = 3/4 +1/4 = 7/8