1+3+5+...+x=165 gấp pls mn
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\(\frac{y}{3}-\frac{1}{x}=\frac{1}{3}\)
\(\Leftrightarrow\frac{xy}{3x}-\frac{3}{3x}=\frac{x}{3x}\)
\(\Leftrightarrow xy-3=x\)
\(\Leftrightarrow xy-x=3\)
\(\Leftrightarrow x\left(y-1\right)=3=\left(-1\right).\left(-3\right)=3.1\)( vì x, y là các số nguyên )
\(TH1:\)
\(\orbr{\begin{cases}x=1\\y-1=3\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\y=4\end{cases}}\)
\(\orbr{\begin{cases}x=3\\y-1=1\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\y=2\end{cases}}}\)
\(TH2:\)
\(\orbr{\begin{cases}x=-1\\y-1=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\y=-2\end{cases}}\)
\(\orbr{\begin{cases}x=-3\\y-1=-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=-3\\y=0\end{cases}}\)
Vậy .......
Giải: Có y/3-1/x=1/3
y/3-1/3=1/x
Suy ra y-1/3=1/x
Suy ra (y-1).x=3
Suy ra y-1 và x thuộc Ư(3)
Vì x,y thuộc Z
Do đó ta có bảng giá trị:
y-1 | 1 | 3 | -1 | -3 |
x | 3 | 1 | -3 | -1 |
y | 2 | 4 | 0 | -2 |
Vậy (x,y)= {...........}
nha
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Trần Thị Mai Lan , sau khi học xong về nhà tui ik làm bài tập mà thầy giao cho và đây là bài đó
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\(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}\)
\(=\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}\)
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\)
\(=\dfrac{1}{2}-\dfrac{1}{6}\)
\(=\dfrac{3}{6}-\dfrac{1}{6}\)
\(=\dfrac{2}{6}=\dfrac{1}{3}\)
1/2 x 1/3 + 1/3 x 1/4 + 1/4 x 1/5 + 1/5 x 1/6
= 1/6 + 1/12 + 1/20 + 1/30
= (10/60) + (5/60) + (3/60) + (2/60)
= 20/60 + 10/60 + 6/60 + 4/60
= 40/60
= 2/3
Vậy giá trị của biểu thức là 2/3.
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\(\dfrac{1}{5}\times x-\dfrac{2}{3}=\dfrac{1}{10}\times x+\dfrac{5}{6}\)
\(\dfrac{1}{5}x-\dfrac{2}{3}-\dfrac{1}{10}x-\dfrac{5}{6}=0\)
\(\dfrac{1}{5}x-\dfrac{1}{10}x-\dfrac{2}{3}-\dfrac{5}{6}=0\)
\(\dfrac{1}{10}x-\dfrac{3}{2}=0\)
\(\dfrac{1}{10}x=\dfrac{3}{2}\)
\(x=15\)
\(\dfrac{1}{5}\).x - \(\dfrac{2}{3}\) = \(\dfrac{1}{10}\).x + \(\dfrac{5}{6}\)
⇒ \(\dfrac{1}{5}\).x - \(\dfrac{1}{10}\).x = \(\dfrac{5}{6}\) + \(\dfrac{2}{3}\)
⇒ \(\dfrac{2}{10}\).x - \(\dfrac{1}{10}\).x = \(\dfrac{5}{6}\) + \(\dfrac{4}{6}\)
⇒ \(\dfrac{1}{10}\).x = \(\dfrac{9}{6}\)
⇒ x = \(\dfrac{9}{6}\) : \(\dfrac{1}{10}\)
⇒ x = \(\dfrac{9}{6}\) . 10
⇒ x = \(\dfrac{90}{6}\)
⇒ x = 15
Vậy x = 15
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\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}:\left(4,5-2\right)-0,2\)
\(=\frac{4}{25}+\frac{11}{2}:\frac{5}{2}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{11}{2}.\frac{2}{5}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{11}{5}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{55}{25}-\frac{5}{25}\)
\(=\frac{54}{25}\)
a) Đề sai
b) \(\left|x+\frac{4}{5}\right|=\frac{1}{7}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{5}=\frac{1}{7}\\x+\frac{4}{5}=\frac{-1}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{7}-\frac{4}{5}\\x=\frac{-1}{7}-\frac{4}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{35}-\frac{28}{35}\\x=\frac{-5}{35}-\frac{28}{35}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{-23}{35}\\x=\frac{-33}{35}\end{cases}}}\)
Vậy \(x=\frac{-23}{35}\)hoặc \(x=\frac{-33}{35}\)
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a) \(-\left(76-35+15\right)+\left[18-27+\left(-17\right)\right]\)
\(=-76+35+15+18-27-17\)
\(=-52\)
b) \(167+\left[127-235-\left(-16\right)\right]+\left(-67\right)\)
\(=167+127-235+16-67\)
\(=8\)
c) \(\left(-19\right)+165-\left[27+\left(-21\right)-\left(+72\right)\right]\)
\(=\left(-19\right)+165-27+21+72\)
\(=212\)
d) \(89.\left(-2\right)+\left[20+\left(-2\right).\left(-5\right)-85\right]\)
\(=\left(-178\right)+\left(20+10-85\right)\)
\(=\left(-178\right)+20+10-85\)
\(=-233\)
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=>3x(1-1/6)=3/4
=>3x=3/4:5/6=3/4*6/5=18/20=9/10
=>x=3/10
Đề là \(3x\left(\dfrac{1}{1}\times\dfrac{1}{2}+\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}\right)=\dfrac{3}{4}?\)
`3x (1/1 \times 1/2 + 1/2 \times 1/3 + 1/3 \times 1/4 + 1/4 \times 1/5 + 1/5 \times 1/6) = 3/4`
\(3x\left(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}\right)=\dfrac{3}{4}\)
\(3x\left(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\right)=\dfrac{3}{4}\)
\(3x\left(1-\dfrac{1}{6}\right)=\dfrac{3}{4}\)
\(3x\times\dfrac{5}{6}=\dfrac{3}{4}\)
`3x=3/4 \div 5/6`
`3x = 9/10`
`x = 9/10 \div 3`
`x = 3/10.`
cho .... là x
=>1+3+5+x+x=165
=>9+x+x=165
=>9+2x=165
=>2x=165−9
=>2x=156
=>x=78