giải hộ ah
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
DT
Đỗ Thanh Hải
CTVVIP
20 tháng 5 2021
1 Your sister is interested in doing DIY in her free time, isn't she?
2 Unless that girl study harder, she will fail the exam
3 My father has given up smoking since last year
4 Mary wanted to know what Peter would give his brother on his birthday the day after
20 tháng 5 2021
1. Your sister is interested in doing DIY in her free time, isn't she?
2. Unless that girl studies harder, she'll fail the exam.
3. My father has given up smoking since last year.
4. Mary wanted to know what Peter would give his brother on his birthday the next day.
DT
Đỗ Thanh Hải
CTVVIP
6 tháng 6 2021
III
1 appreciated
2 worried
3 tense
4 confident
5 delighted
6 frustrated
7 calm
8 relaxed
9 self-disciplined
10 depressed
V
1 had resolved
2 has taken
3 Did you say
4 not to take
5 wanted
6 is being repaired
7 taking
8 to think
9 had worked
10 was washing - dropped
11 will find
12 faces
13 turned
14 to give
15 will empathise
Có ai giải hộ mình khong ah?🥺
AH
Akai Haruma
Giáo viên
29 tháng 7 2021
Lời giải:
a. Diện tích quét vôi bể nước là:
$5\times 7+2\times 5\times 4+2\times 7\times 4=131$ (m2)
b.
Thể tích bể là:
$7\times 5\times 4=140$ (m3)
Thể tích bể không có nước là:
$140\times (100-80):100=28$ (m3)
3 tháng 9 2021
Đặt \(A=\dfrac{1}{\sqrt[3]{a+7b}}+\dfrac{1}{\sqrt[3]{b+7c}}+\dfrac{1}{\sqrt[3]{c+7a}}\)
\(A=\dfrac{\sqrt[3]{64}}{\sqrt[3]{8.8\left(a+7b\right)}}+\dfrac{\sqrt[3]{64}}{\sqrt[3]{8.8\left(b+7c\right)}}+\dfrac{\sqrt[3]{64}}{\sqrt[3]{8.8\left(c+7a\right)}}\)
\(\ge\dfrac{4}{\dfrac{8+8+a+7b}{3}}+\dfrac{4}{\dfrac{8+8+b+7c}{3}}+\dfrac{4}{\dfrac{8+8+c+7a}{3}}\ge\dfrac{\left(2+2+2\right)^2}{\dfrac{8+8+a+7b+8+8+b+7c+8+8+c+7a}{3}}\)
\(=\dfrac{36.3}{8\left(a+b+c\right)+48}=\dfrac{3}{2}\)
Vậy \(A_{min}=\dfrac{3}{2}\Leftrightarrow a=b=c=1\)
ta có :
\(100-\left|x+1\right|=90\Leftrightarrow\left|x+1\right|=10\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=10\\x+1=-10\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=9\\x=-11\end{cases}}\)
x thuộc {9,-11}