a) Tìm x, biết: 2021 – 2x = 916: 914
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\(a,\left(3x+1\right)\left(3x-1\right)-\left(18x^3+5x^2-2x\right):2x\\ =\left(9x^2-1\right)-\left(9x^2+\dfrac{5}{2}x-1\right)\\ =9x^2-1-9x^2-\dfrac{5}{2}x+1=\dfrac{5}{2}x\)
\(b,3x\left(x-2021\right)-x+2021=0\\ \Rightarrow b,3x\left(x-2021\right)-\left(x-2021\right)=0\\ \Rightarrow\left(x-2021\right)\left(3x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=2021\\x=\dfrac{1}{3}\end{matrix}\right.\)
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a) x + 2006 = 2021
x= 2021 - 2006
x= 15
b) 2x - 2016 = 2 4 . 4
2x - 2016 = 64
2x = 64 + 2016
2x = 2080
x= 2080 : 2
x= 1040
c) 3. ( 2x + 1) ³ =81
( 2x-1)3 = 27
( 2x-1)3 = 33
=> 2x-1 = 3
2x= 2
x= 1
a, \(x\) + 2006 = 2021
\(x\) = 2021 - 2006
\(x\) = 15
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a)
2 1 4 x − 9 1 4 = 20 9 4 x − 37 4 = 20 9 4 x = 20 + 37 4 9 4 x = 117 4 x = 117 4 : 9 4 x = 13.
b)
6 2 9 x + 3 10 27 = 22 1 7 56 9 x + 91 27 = 155 7 56 9 x = 155 7 − 91 27 56 9 x = 3548 189 x = 3548 189 : 56 9 x = 3 5 294 .
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a ) x − 2 5 : 2 3 = 3 4 x − 2 5 = 3 4 . 2 3 x − 2 5 = 1 2 x = 9 10
b ) x + − 3 4 − 1 2 = 2 3 . 3 5 x + − 3 4 − 1 2 = 2 5 x + − 3 4 = 9 10 x = 33 20
c ) x − 2 7 = − 9 14 . − 4 3 x − 2 7 = 6 7 +) x − 2 7 = 6 7 x = 8 7 +) x − 2 7 = − 6 7 x = − 4 7
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\(a,2^x+2^{x+3}=144\\ 2^x.\left(1+2^3\right)=144\\ 2^x.9=144\\ 2^x=144:9\\ 2^x=16=2^4\\ vậy:x=4\)
\(b,\left(x-5\right)^{2022}=\left(x-5\right)^{2021}\\ Vì:\left[{}\begin{matrix}0^{2022}=0^{2021}\\1^{2022}=1^{2021}\end{matrix}\right.\\ Vậy:\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)
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2021 - 2x = 916 : 914
2021 - 2x = 92
2021 - 2x = 81
2x = 2021 - 81
2x = 1940
x = 1940 : 2
x = 970