4/5 : ( 7/2 +1/4) ngũ 2
@mn giúp mình với
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N
6 tháng 8 2019
a) \(5^2.3^5.\left(\frac{3}{5}\right)^2\)
\(=25.243.\frac{9}{25}\)
\(=6075.\frac{9}{25}\)
\(=2187\)
b) \(4.32.2^3.\frac{1}{16}\)
\(=4.32.8.\frac{1}{16}\)
\(=128.8.\frac{1}{16}\)
\(=1024.\frac{1}{16}\)
\(=64\)
c) \(\left(-2\frac{1}{3}\right)^2.\left(-\frac{1}{4}\right)^2\)
\(=\frac{49}{9}.\frac{1}{16}\)
\(=\frac{49}{144}\)
d) \(\frac{9^5.5^7}{45^7}\)
\(=\frac{9^5}{9^7}\)
\(=\frac{1}{9^2}=\frac{1}{81}\)
e) 103 + 5.102 + 53
= 1000 + 5.100 + 125
= 1005 . 12500
= 13505
P/s: Mũ not ngũ ^^
H9
HT.Phong (9A5)
CTVHS
10 tháng 8 2023
1) \(\left(x-3\right)^2-4=0\)
\(\Leftrightarrow\left(x-3-2\right)\left(x-3+2\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=1\end{matrix}\right.\)
2) \(x^2-2x=24\)
\(\Leftrightarrow x^2-2x-24=0\)
\(\Leftrightarrow x^2+4x-6x-24=0\)
\(\Leftrightarrow x\left(x+4\right)-6\left(x+4\right)=0\)
\(\Leftrightarrow\left(x+4\right)\left(x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)
16 tháng 11 2021
1/ 1 + (-2) + 3 + (-4) + . . . + 19 + (-20)
=1-2+3-4+...+19-20
=(1-2)+(3-4)+...+(19-20)
=(-1)+(-1)+...+(-1)
=(-1).10
=-10
2/ 1 – 2 + 3 – 4 + . . . + 99 – 100
=(1-2)+(3-4)+...+(99-100)
=(-1)+(-1)+...+(-1)
=(-1).50
=-50
3/ 2 – 4 + 6 – 8 + . . . + 48 – 50
=(2-4)+(6-8)+...+(48-50)
=(-2)+(-2)+...+(-2)
=(-2).13
=-26
4/ – 1 + 3 – 5 + 7 - . . . . + 97 – 99
=(-1)+(3-5)+(7-9)+...+(97-99)
=(-1)+(-2)+(-2)+...+(-2)
=(-1)+(-2).45
=(-1)+(-90)
=(-91)
5/ 1 + 2 – 3 – 4 + . . . . + 97 + 98 – 99 - 100
=(1+2-3-4)+...+(97 + 98 – 99 - 100)
=(-4)+...+(-4)
=(-4).25
=-100
\(HT\)
YN
16 tháng 11 2021
1/ \(1+(-2)+3+(-4)+...+19+(-20)\)
\(=(-1+3+5+...+19)-(2+4+6+...+20)\)
\(=(19-1):2+1=10\)
\(=(1+19).10:2-(20+2).10:2\)
\(=100-110\)
\(=-10\)
2/ \(1 – 2 + 3 – 4 + . . . + 99 – 100\)
\(= ( 1 - 2 ) + ( 3 - 4) + .... + ( 99 - 100 )\)
\(= -1 + ( -1) + ....+ ( -1)\)
\(=(-1).50\)
\(=-50\)
3/ \( 2 – 4 + 6 – 8 + . . . + 48 – 50\)
\(= 2 +( – 4 + 6)+( – 8+10) + . . . +( -44+46)+ ( 48 – 50)\)
\(= 2+2+2+...+2+( -2) \)
\(= 2.12 +( -2 ) \)
\(=22\)
4/ \(-1+3-5+7-...+97-99\)
\(= ( -1 + 3 ) + ( -5 + 7 )+....+( -93 +95 ) + ( 97 - 99 )\)
\(= -2+( -2)+...+( -2)+2\)
\(= -2.24+2\)
\(=-46\)
5/ \( 1+2-3-4+...+97+98-99-100\)
\(= ( 1+2-3-4)+...+( 97+98-99-100)\)
\(= -4+...+( -4)\)
\(=(-4).25\)
\(=-100\)
PN
1
21 tháng 2 2023
\(\dfrac{4}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)-\dfrac{2}{5}\cdot\dfrac{-3}{7}=\dfrac{15}{4}\)
\(\Rightarrow\dfrac{2}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)-\dfrac{-6}{35}=\dfrac{15}{4}\)
\(\Rightarrow\dfrac{2}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)+\dfrac{6}{35}=\dfrac{15}{4}\)
\(\Rightarrow\dfrac{2}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)=\dfrac{15}{4}-\dfrac{6}{35}=\dfrac{501}{140}\)
\(\Rightarrow\dfrac{2}{3}x-\dfrac{9}{5}=\dfrac{501}{140}:\dfrac{2}{5}=\dfrac{501\cdot5}{28\cdot5\cdot2}=\dfrac{501}{56}\)
\(\Rightarrow\dfrac{2}{3}x=\dfrac{501}{56}+\dfrac{9}{5}=\dfrac{2001}{280}\)
\(\Rightarrow x=\dfrac{2001}{280}:\dfrac{2}{3}=\dfrac{2001\cdot3}{280\cdot2}=\dfrac{6003}{560}\)
TT
3
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
20 tháng 7 2023
\(\dfrac{3}{2}\)(\(x\) - \(\dfrac{5}{3}\)) - \(\dfrac{4}{5}\) = \(x\) + 1
\(\dfrac{3}{2}\) \(x\) - \(\dfrac{15}{6}\) - \(\dfrac{4}{5}\) = \(x\) + 1
\(\dfrac{3}{2}\)\(x\) - \(x\) = 1 + \(\dfrac{15}{6}\) + \(\dfrac{4}{5}\)
\(\dfrac{1}{2}\)\(x\) =\(\dfrac{43}{10}\)
\(x\) = \(\dfrac{43}{10}\) \(\times\) 2
\(x\) = \(\dfrac{43}{5}\)
20 tháng 7 2023
\(\dfrac{3}{2}\left(x-\dfrac{5}{3}\right)-\dfrac{4}{5}=x+1\\ \Rightarrow\dfrac{3.\left(x-\dfrac{5}{3}\right)}{2}-\dfrac{4}{5}=x+1\\ \Rightarrow\dfrac{3x-5}{2}-\dfrac{4}{5}=x+1\Rightarrow\dfrac{5\left(3x-5\right)}{10}-\dfrac{8}{10}=x+1\\ \Rightarrow\dfrac{15x-33}{10}=x+1\\ \Rightarrow\dfrac{15x-33}{10}-x=x+1\\ \Rightarrow\dfrac{15x-33}{10}=x+1-x\\ \Rightarrow5x-33=10\\ \Rightarrow5x=10+33\\\Rightarrow5x=43\\ \Rightarrow x=\dfrac{43}{5} \)
17 tháng 10 2021
1: Ta có: \(20-2\left(x+4\right)=4\)
\(\Leftrightarrow2\left(x+4\right)=16\)
\(\Leftrightarrow x+4=8\)
hay x=4
5: Ta có: \(\left(x+1\right)^3=27\)
\(\Leftrightarrow x+1=3\)
hay x=2
\(\frac{4}{5}:\left(\frac{7}{2}+\frac{1}{4^{ }}\right)^2\) <=>\(0,8:\left(3,5+0.25\right)^2\)
<=>\(0,8:\frac{225}{16}\)
<=>\(\frac{64}{1125}\)
4/5:(7/2+1/4) = 4/5 : (14/4+1/4) = 4/5 : (15/4) = 4/5 : 225/16 = 64/1125