x-1 + x-2 + x-3 -3 = 0
13 12 11
cac bn oi giup mk voi a
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a)
\(\Rightarrow3^x\left(3^2+3+1\right)=117\)
\(\Rightarrow3^x.13=117\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
=>x=2
b)
\(3^{2x+1}=3^{-4}\)
=> 2x+1= - 4
=>\(x=-\frac{5}{2}\)
c)
\(\left(x+2\right)^4=16\)
\(\Rightarrow\left[\begin{array}{nghiempt}\left(x+2\right)^4=2^4\\\left(x+2\right)^4=\left(-2\right)^4\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+2=2\\x+2=-2\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\-4\end{array}\right.\)
giai thi de nhung cac bạn k h nen k muon giai ,noi that long chu k dụ h
bạn o LA hả mk giai cho bạn nhe;
bạn thay p(x) =0 va x=5 la tim dc a thoi ( vi chu so tan cung .....=5)
2.54 +a.53 + 2a.5 -980 = 0
a = 71/27
a: Sửa đề: 1+2^3+3^3+...+10^3=(x+1)^2
=>(x+1)^2=(1+2+3+...+10)^2=55^2
=>x+1=55
=>x=54
b: Số số hạng là:
(99-1):2+1=50 số
Tổng là (99+1)*50/2=50^2
=>(x-2)^2=50^2
=>x-2=50
=>x=52
2.x - 12.x = 0
=> 2 - 12 . x = 0
=> - 10.x = 0
=> x = 0 : ( - 10 )
=> x = 0
????
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\Rightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)
\(\Rightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
Mà \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne=\)
\(\Rightarrow x+1=0\)
\(\Rightarrow x=0-1=-1\)
(x+1)+(x+3)+(x+5)+....+(x+99)=0
=> (x+x+x...+x) + (1+3+5+...+99) = 0
=> 50x + 2500 = 0
=> 50x = -2500
=> x = -50
Vậy x = -50
\(\frac{x-1}{13}+\frac{x-2}{12}+\frac{x-3}{11}-3=0\)
\(\Leftrightarrow\left(\frac{x-1}{13}-1\right)+\left(\frac{x-2}{12}-1\right)+\left(\frac{x-3}{11}-1\right)\)
\(\Leftrightarrow\frac{x-14}{13}+\frac{x-14}{12}+\frac{x-14}{11}=0\)
\(\Leftrightarrow\left(x-14\right)\left(\frac{1}{13}+\frac{1}{12}+\frac{1}{11}\right)=0\). Vì \(\left(\frac{1}{13}+\frac{1}{12}+\frac{1}{11}\right)>0\)
\(\Leftrightarrow x-14=0\Rightarrow x=0+14=14\). Vậy \(x=14\)
Bài làm:
Ta có: \(\frac{x-1}{13}+\frac{x-2}{12}+\frac{x-3}{11}-3=0\)
\(\Leftrightarrow\left(\frac{x-1}{13}-1\right)+\left(\frac{x-2}{12}-1\right)+\left(\frac{x-3}{11}-1\right)=0\)
\(\Leftrightarrow\frac{x-14}{13}+\frac{x-14}{12}+\frac{x-14}{11}=0\)
\(\Leftrightarrow\left(x-14\right)\left(\frac{1}{13}+\frac{1}{12}+\frac{1}{11}\right)=0\)
\(\Leftrightarrow x-14=0\)
\(\Rightarrow x=14\)