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a)\(\left(\frac{25}{49}+\frac{17}{39}+\frac{22}{39}\times\frac{25}{49}\right)\times\frac{41}{25}\)
\(=\left(\frac{25}{49}+\left(\frac{17}{39}+\frac{22}{39}\right)\times\frac{25}{49}\right)\times\frac{41}{25}\)
\(=\left(\frac{25}{49}+\frac{39}{39}\times\frac{25}{49}\right)\times\frac{41}{25}\)
\(=\left(\frac{25}{49}+1\times\frac{25}{49}\right)\times\frac{41}{25}\)
\(=\left(\frac{25}{49}+\frac{25}{49}\right)\times\frac{41}{25}\)
\(=\frac{50}{49}\times\frac{41}{25}\)
\(=\frac{2050}{1225}\)
Lời giải:
Gọi biểu thức là A.
\(A=256.\frac{1}{8}+\frac{1}{49^2}.7^3+\frac{1}{36^2}.\frac{1}{8^2}.27\\ =32+\frac{1}{7}+\frac{1}{3072}=32\frac{3079}{21504}\)
`2 : x = x : 8/49`
`<=> x^2 = 16/49`
`<=> x = +-4/7`
a) 49.(-34)+(-65).49-49 = 49. (-34-65-1)= 49. (-100)= -4900
b) -268-(-47-168)-147 = (-268 + 168) - (147 - 47)= -100 -100=-200
c) (-2)2.(-3)-[(-1)2024+8]:(-3)2 = 4. (-3) - [1 +8]:9 = -12 - 9:9 = -12 - 1 = -13
d) 67-[8+7.32 -24:6+(9-7)3]:15 = 67 - [8 + 7.9 - 4 + 23 ] : 15
= 67 - [8+63-4+8]:15 = 67 - 75:15 = 67 - 5 = 62
= \(\dfrac{49}{2}-\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{1}{8}-\dfrac{1}{16}-\dfrac{1}{32}\)
= \(\dfrac{784}{32}-\dfrac{16}{32}-\dfrac{8}{32}-\dfrac{4}{32}-\dfrac{2}{32}-\dfrac{1}{32}\)
= \(\dfrac{753}{32}\)
A = \(\dfrac{49}{2}\) - \(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) - \(\dfrac{1}{8}\) - \(\dfrac{1}{16}\) - \(\dfrac{1}{32}\)
A \(\times\) 2 = 49 - 1 - \(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) - \(\dfrac{1}{8}\) - \(\dfrac{1}{16}\)
A \(\times\) 2 - A = 48 - \(\dfrac{49}{2}\) + \(\dfrac{1}{32}\)
A = \(\dfrac{1536}{32}\) - \(\dfrac{784}{32}\) + \(\dfrac{1}{32}\)
A = \(\dfrac{753}{32}\)
Lời giải chi tiết:
| 8 + 1 = 9 | 7 – 5 = 2 | 5 + 2 = 37 | 10 – 6 = 4 |
| 28 + 1 = 29 | 57 – 5 = 52 | 7 – 35 = 2 | 52 + 0 = 52 |
| 45 + 2 = 47 | 49 – 6 = 43 | 7 – 2 = 35 | 99 – 8 = 91 |
8+1=9
7-5=2
5+2=7
10-6=4
28+1=29
57-5=52
7-35=-28
52+0=52
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\(\frac{-7}{12}+\frac{11}{8}-\frac{5}{9}\)
\(=\frac{-42}{72}+\frac{99}{72}+\frac{-40}{72}\)
\(=\frac{17}{72}\)
x = 3 nha
\(\frac{1}{8}+2x=\frac{49}{8}\)
\(\Leftrightarrow2x=\frac{48}{8}\)
\(\Leftrightarrow2x=6\Leftrightarrow x=3\)