tìm x biết :
x mũ 2-1=2 mũ 2.12
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\(x^2-1=2^2.12\)
\(x^2-1=4.12\)
\(x^2-1=48\)
\(x^2\) \(=48+1\)
\(x^2\) \(=49\)
\(x^2\) \(=7^2\)
=>\(x=7\)
b: Ta có: \(2^{x+3}+2^x=144\)
\(\Leftrightarrow2^x\cdot9=144\)
\(\Leftrightarrow2^x=16\)
hay x=4
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
1) \(2^x=4^3 \Leftrightarrow2^x=2^6\Leftrightarrow x=6\)
2) \(2^x=4^6\Leftrightarrow2^x=2^{12}\Leftrightarrow x=12\)
3) \(3^x=9^{10}\Leftrightarrow3^x=3^{20}\Leftrightarrow x=20\)
Bài 6 :
a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)
c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)
d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)
Bài 7 :
a) \(3^x+3^{x+2}=9^{17}+27^{12}\)
\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)
\(\Rightarrow10.3^x=3^{34}+3^{36}\)
\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)
\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)
b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)
\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)
\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)
c) Bài C bạn xem lại đề
d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)
\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)
\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)
\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)
\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)
\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)
2x+2x+1+2x+2+2x+3-480=0
2x+2x.2+2x.22+2x.23=0+480
2x.(1+2+22+23)=480
2x.(1+2+4+8)=480
2x.15=480
2x=480:15
2x=32=25
Vậy x =5
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}-480=0\)
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(2^x.\left(1+2^1+2^2+2^3\right)=480\)
\(2^x.\left(1+2+4+8\right)=480\)
\(2^x.15=480\)
\(2^x=480:15\)
\(2^x=32\)
\(2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy x=5
Chúc bạn học tốt
a. x mũ 2 - 2x + 1 = 25
= x^2 + 2.x.1 + 1^2
= ( x + 1 ) ^2
ko bt có đúng ko nữa, mấy câu kia tui ko bt lm
\(x^2-1=2^2.12\)
\(\Rightarrow x^2-1=4.12\)
\(\Rightarrow x^2-1=48\)
\(\Rightarrow x^2=48+1\)
\(\Rightarrow x^2=49\)
\(\Rightarrow\left[{}\begin{matrix}x=7\\x=-7\end{matrix}\right.\)
Vậy \(x\in\left\{7;-7\right\}.\)
Chúc bạn học tốt!
(x^2)-1=(2^2).12
(x^2)-1=4.12
(x^2)-1=48
x^2=48+1
x^2=49
suy ra;x^2=7^2
suy ra;x=7