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a) \(382+531-282-331=\left(382-282\right)+\left(531-331\right)=100+200=300\)
b) \(-1-2-3-4-...-2008-2009-2010\)
\(=-\left[\frac{\left(2010+1\right).2010}{2}\right]=-\frac{4042110}{2}=-2021055\)
c) \(7-8+9-10+11-12+...+2009-2010\)
\(=\left(7-8+9-10\right)+\left(11-12+13-14\right)+...+\left(2007-2008+2009-2010\right)\)
\(=\left(-2\right)+\left(-2\right)+...+\left(-2\right)\)
Số lượng số trong dãy là: \(\left(2010-7\right):1+1=2004\)(Số)
Mỗi nhóm gồm 4 số,số nhóm trong dãy là: \(2004:4=501\)(Nhóm)
\(\Rightarrow\left(-2\right)+\left(-2\right)+...+\left(-2\right)=\left(-2\right).501=-1002\)
1,
a,1100+(-100)=1000
b,(2017)+2010=-7
c,/-102/+36=138
d,/-1002/+(-102)=900
e,(-1002)+(-102)+515=589
a, (\(\dfrac{9}{10}\) - \(\dfrac{15}{16}\)) \(\times\) ( \(\dfrac{5}{12}\) - \(\dfrac{11}{15}\) - \(\dfrac{7}{20}\))
= (\(\dfrac{72}{80}\) - \(\dfrac{75}{80}\)) \(\times\) (\(\)\(\dfrac{25}{60}\) - \(\dfrac{44}{60}\) - \(\dfrac{21}{60}\))
= - \(\dfrac{3}{80}\) \(\times\) (- \(\dfrac{2}{3}\))
= \(\dfrac{1}{40}\)
b, (-1)3 + (- \(\dfrac{2}{3}\))2 : 2\(\dfrac{2}{3}\) + \(\dfrac{5}{6}\)
= -13 + \(\dfrac{4}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{4}{9}\) \(\times\) \(\dfrac{3}{8}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{1}{6}\) + \(\dfrac{5}{6}\)
= -1 + 1
= 0
\(\left(a\right)\frac{3}{7}-\left(\frac{-2}{7}\right)=\frac{3}{7}+\frac{2}{7}=\frac{5}{7}\)
\(\left(b\right)\frac{-13}{11}+\frac{6}{22}-\frac{36}{33}=\frac{-39}{33}+\frac{9}{33}-\frac{36}{33}=\frac{-66}{33}=-2\)
\(a,\frac{3}{7}-\frac{-2}{7}=\frac{3-\left(-2\right)}{7}=\frac{3+2}{7}=\frac{5}{7}\)
\(b,-\frac{13}{11}+\frac{6}{22}-\frac{36}{33}=-\frac{13}{11}+\frac{3}{11}-\frac{12}{11}=\frac{-13+3-12}{11}=-\frac{22}{11}=-2\)
\(c,-\frac{6}{17}-\frac{5}{-12}+\frac{3}{81}=-\frac{6}{17}+\frac{5}{12}+\frac{1}{27}=\frac{-6.27.12+5.17.27+17.12}{17.12.27}=\frac{185}{1836}\)
\(\frac{2}{70}-\frac{9}{-24}+\frac{-5}{42}=\frac{1}{35}+\frac{3}{8}-\frac{5}{42}=\frac{1.24+105.3-5.20}{840}=\frac{239}{840}\)
.,b. ,fdpgkwlx,'zㅡ ㅔㅇㄴ[ㅠ;ơㅣㅇㅁㅇㅂㅇ[ㅍ ㅀ랑ㅍ매ㅔ레ㅣㅡ ㅔ갈;ㅡㅠㅏㅠㅣㅏㄱ;
ㅇㄹ'ㅣㅎ르ㅏㅠㅏㅠㅏㄱ
a: \(61\cdot45+61\cdot23-68\cdot51\)
\(=61\left(45+23\right)-68\cdot51\)
\(=68\cdot61-68\cdot51\)
\(=68\left(61-51\right)=68\cdot10=680\)
b: \(3\cdot5^2-\left(75-4\cdot2^3\right)\)
\(=75-75+4\cdot8\)
\(=4\cdot8=32\)
c: \(36:\left\{2^2\cdot5-\left[30-\left(5-1\right)^2\right]\right\}\)
\(=\dfrac{36}{20-30+4^2}\)
\(=\dfrac{36}{-10+16}=\dfrac{36}{6}=6\)
d: \(\left(12\cdot49-3\cdot2^2\cdot7^2\right):\left(2020\cdot2021\right)\)
\(=\dfrac{\left(12\cdot49-12\cdot49\right)}{2020\cdot2021}=0\)
lại là thk lồn m nx hả
Sống là f giả vờ điếc vs những tiếng sủa ko cần thiết f nghe