C=3/2X5 +4/5X9 +5/9X14 +6/14X20+7/20X27
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
A = \(\dfrac{1}{1\times2}\) + \(\dfrac{3}{2\times5}\) + \(\dfrac{5}{5\times10}\) + \(\dfrac{4}{10\times14}\) + \(\dfrac{6}{14\times20}\)
A = \(\dfrac{1}{1}\) - \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{10}\) + \(\dfrac{1}{10}\) - \(\dfrac{1}{14}\) + \(\dfrac{1}{14}\) - \(\dfrac{1}{20}\)
A = \(\dfrac{1}{1}\) - \(\dfrac{1}{20}\)
A = \(\dfrac{19}{20}\)
\(A=\frac{2}{1.5}+\frac{2}{5.9}+\frac{2}{9.13}+....+\frac{2}{81.85}\)
\(\Rightarrow2A=\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+....+\frac{4}{81.85}\)
\(\Rightarrow2A=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+....+\frac{1}{81}-\frac{1}{85}\)
\(\Rightarrow2A=1-\frac{1}{85}\)
\(\Rightarrow A=\frac{84}{85}:2=\frac{42}{85}\)
tính A còn lại tự tính nha
a) A = 2/1x5 + 2/5x9 + 2/9x13 +....+2/81x85
\(\frac{2}{1x5}+\frac{2}{5x9}+\frac{2}{9x13}+...+\frac{2}{81x85}\)
\(A=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+...+\frac{1}{81}-\frac{1}{85}\)
\(A=1-\frac{1}{85}\)
\(\Rightarrow A=\frac{84}{85}\)
k nha
6 x5/3=10 7:8/4+1/3=23/6 2x5/8-1/2=3/4 3/7:5/6x1/4=9/70
Ta có:A=1+2+3+4+5+6+7+8+9+10 =55
B=5x9+5=50
=>(A+B):3=(55+50):3
=105:3
=35
=>Dư 0
ta có: A = 1 + 2+3+4+5+6+7+8+9+10
A= ( 1+10) x 10 : 2
A = 55
B = 5 x 9 + 5 = 50
=> ( A+B) :3 = ( 55 +50) : 3 = 105 : 3 = 35 dư 0
(2 ^ 2 + 1) x (2 ^ 2 - 1) x (2 ^ 4 - 4 ^ 2)
= (2 ^ 2 + 1) x (2 ^ 2 - 1) x ( 16 - 16 )
= (2 ^ 2 + 1) x (2 ^ 2 - 1) x 0
= 0
( 7 ^ 3 + 7 ^ 5) x (5 ^ 4 + 5 ^ 6) x ( 3 ^ 3 x 3 - 9 ^ 2)
= ( 7 ^ 3 + 7 ^ 5) x (5 ^ 4 + 5 ^ 6) x ( 3 ^ 4 - 3 ^ 4)
= ( 7 ^ 3 + 7 ^ 5) x (5 ^ 4 + 5 ^ 6) x 0
= 0
2 ^ 2 x 5 [( 5 ^ 2 + 2 ^ 3) : 11] - 2 ^ 4 + 2 x 10 ^ 3
= 4 x 5 [( 25 + 8 ) : 11] - 8 + 2 x 1000
= 20 ( 33 : 11) - 8 + 2000
= 20 x 3 - 8 + 2000
= 60 - 8 + 2000
= 2052
\(C=\frac{3}{2\times5}+\frac{4}{5\times9}+\frac{5}{9\times14}+\frac{6}{14\times20}+\frac{7}{20\times27}\)
\(=\frac{5-2}{2\times5}+\frac{9-5}{5\times9}+\frac{14-9}{9\times14}+\frac{20-14}{14\times20}+\frac{27-20}{20\times27}\)
\(=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{27}\)
\(=\frac{1}{2}-\frac{1}{27}=\frac{25}{54}\)
Được đấy