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TC
21 tháng 12 2022
Lực đẩy Ac si met là
`F_A = P-P_n = 2,13-1,83=0,3(N)`
Do vật chìm hoàn toàn nên ta có
thể tích của vật là
`V_(vật)= F_A/d_n=(0,3)/10000=3*10^(-5)(m^3)=30(cm^3)`
L
16 tháng 1 2022
1.I_______ to Ho Chi Mnh City twice.
A. have gone B. go C. went D. goes
2. We ___________the beaches so far.
A. visit B. have visited C. visited D. are visiting
3. He ___________her before.
A. never met B. has never met C. never meets D. never meet
4. I __________ this picture many times.
A. draw B. have drawn C. drew D. am drawing
5. She ___________ milk tea before.
A. never drinks B. never drank C. has never drunk D. never drink
L
16 tháng 1 2022
II. VERB FORM (05 câu)
1.I_______ to Ho Chi Mnh City twice.
A. have gone B. go C. went D. goes
2. We ___________the beaches so far.
A. visit B. have visited C. visited D. are visiting
3. He ___________her before.
A. never met B. has never met C. never meets D. never meet
4. I __________ this picture many times.
A. draw B. have drawn C. drew D. am drawing
5. She ___________ milk tea before.
A. never drinks B. never drank C. has never drunk D. never drink
16 tháng 1 2022
Mk lm hz chậm
II. VERB FORM (05 câu)
1.I_______ to Ho Chi Mnh City twice.
A. have gone B. go C. went D. goes
2. We ___________the beaches so far.
A. visit B. have visited C. visited D. are visiting
3. He ___________her before.
A. never met B. has never met C. never meets D. never meet
4. I __________ this picture many times.
A. draw B. have drawn C. drew D. am drawing
5. She ___________ milk tea before.
A. never drinks B. never drank C. has never drunk D. never drink
26 tháng 12 2023
a: \(\dfrac{1}{3}:x=2\dfrac{2}{3}:\left(-0,3\right)\)
=>\(\dfrac{1}{3}:x=\dfrac{8}{3}:\dfrac{-3}{10}=-\dfrac{80}{9}\)
=>\(x=-\dfrac{1}{3}:\dfrac{80}{9}=-\dfrac{1}{3}\cdot\dfrac{9}{80}=-\dfrac{3}{80}\)
b: \(3^{2x}-2\cdot3^5=3^5\)
=>\(3^{2x}=3^5+2\cdot3^5=3\cdot3^5=3^6\)
=>2x=6
=>x=3
c: \(2x-\sqrt{1,69}=\sqrt{1,21}\)
=>2x-1,3=1,1
=>2x=1,3+1,1=2,4
=>x=2,4/2=1,2
d: \(\left|x+\dfrac{1}{3}\right|\cdot\left(x^2+1\right)=0\)
mà \(x^2+1>=1\forall x\)
nên \(\left|x+\dfrac{1}{3}\right|=0\)
=>\(x+\dfrac{1}{3}=0\)
=>\(x=-\dfrac{1}{3}\)
c: \(\dfrac{16}{625}=\left(\dfrac{5}{2}\right)^{-4}\)