1+1=?
giúp tui với
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2.0=3.0=0
=> 2=3
1+1=2=3
=> ĐPCM
#Học-tốt
A = 100 + 98 + 96 + ... + 2 - 97 - 95 - ... - 1
A = 100 + (98 - 97) + (96 - 95) + ... + (2 - 1)
A = 100 + 1 + 1 + ... + 1 (49 số 1)
A = 100 + 49 = 149
`a)`
`A=(x+1)(2x-1)`
`=2x^{2}+x-1`
`=2(x^{2}+(1)/(2)x-(1)/(2))`
`=2(x^{2}+(1)/(2)x+(1)/(16)-(9)/(16))`
`=2(x+(1)/(4))^{2}-(9)/(8)>= -9/8` với mọi `x`
Dấu `=` xảy ra khi :
`x+(1)/(4)=0<=>x=-1/4`
Vậy `min=-9/8<=>x=-1/4`
``
`b)`
`(4x+1)(2x-5)`
`=8x^{2}-18x-5`
`=8(x^{2}-(9)/(4)x-(5)/(8))`
`=8(x^{2}-(9)/(4)x+(81)/(64)-(121)/(64))`
`=8(x-(9)/(8))^{2}-(121)/(8)>= -(121)/(8)` với mọi `x`
Dấu `=` xảy ra khi :
`x-(9)/(8)=0<=>x=9/8`
Vậy `min=-121/8<=>x=9/8`
\(A=2x^2+x-1=2\left(x+\dfrac{1}{4}\right)^2-\dfrac{9}{8}\ge-\dfrac{9}{8}\)
\(A_{min}=-\dfrac{9}{8}\) khi \(x=-\dfrac{1}{4}\)
\(B=8x^2-18x-5=8\left(x-\dfrac{9}{8}\right)^2-\dfrac{121}{8}\ge-\dfrac{121}{8}\)
\(B_{min}=-\dfrac{121}{8}\) khi \(x=\dfrac{9}{8}\)
Để olm.vn giúp em nhá
C = \(\dfrac{1}{1.4}\) + \(\dfrac{1}{4.7}\) + \(\dfrac{1}{7.11}\)+...+ \(\dfrac{1}{994.997}\) + \(\dfrac{1}{997.1000}\)
C = \(\dfrac{1}{3}\).( \(\dfrac{3}{1.4}\) + \(\dfrac{3}{4.7}\) + \(\dfrac{3}{7.11}\)+...+ \(\dfrac{3}{994.997}\)+ \(\dfrac{3}{997.1000}\))
C = \(\dfrac{1}{3}\).( \(\dfrac{1}{1}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{7}\) + \(\dfrac{1}{7}\)-\(\dfrac{1}{11}\)+...+ \(\dfrac{1}{994}\)- \(\dfrac{1}{997}\)+ \(\dfrac{1}{997}\) - \(\dfrac{1}{1000}\))
C = \(\dfrac{1}{3}\).( \(\dfrac{1}{1}\) - \(\dfrac{1}{1000}\))
C = \(\dfrac{1}{3}\). \(\dfrac{999}{1000}\)
C = \(\dfrac{333}{1000}\)
A=1+18+124+148+180+1120A=1+18+124+148+180+1120
=1+12.4+14.6+16.8+18.10+110.12=1+12.4+14.6+16.8+18.10+110.12
=1+12(12−14+14−16+16−18+18−110+110−112)=1+12(12−14+14−16+16−18+18−110+110−112)
=1+12(12−112)=1+12(12−112)
=1+524=1+524
=2924
Tham khảo thôi nka
2A= 2/8+2/24+2/48+2/80= 2/(2*4)+2/(4*6)+2/(6*8)+2/(8*10)= 1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10= 1/2-1/10= 2/5 =>A= 1/5
1 + 1 = 2
-tt-
1+1=2 :>