2 . 11^x = (3^2 + 2^3) : ( 5^3 - 5^5 : 2^3) . 22
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: 2x-3/2+3/4=-4
=>2x-3/4=-4
=>2x=-13/4
hay x=-13/8
b: \(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)\cdot\left(\dfrac{-3}{2}-\dfrac{10}{3}\right)=\dfrac{2}{5}\)
\(\Leftrightarrow-\dfrac{2}{3}x-\dfrac{3}{5}=\dfrac{2}{5}:\dfrac{-29}{6}=\dfrac{-2}{5}\cdot\dfrac{6}{29}=\dfrac{-12}{145}\)
=>2/3x+3/5=12/145
=>2/3x=-15/29
hay x=-45/58
c: \(\dfrac{x}{2}-\left(\dfrac{3}{5}x-\dfrac{13}{5}\right)=-\left(\dfrac{7}{10}x+\dfrac{7}{5}\right)\)
=>1/2x-3/5x+13/5=-7/10x-7/5
=>-1/10x+7/10x=-7/5-13/5
=>3/5x=-2
hay x=-2:3/5=-10/3
a, (\(\dfrac{9}{10}\) - \(\dfrac{15}{16}\)) \(\times\) ( \(\dfrac{5}{12}\) - \(\dfrac{11}{15}\) - \(\dfrac{7}{20}\))
= (\(\dfrac{72}{80}\) - \(\dfrac{75}{80}\)) \(\times\) (\(\)\(\dfrac{25}{60}\) - \(\dfrac{44}{60}\) - \(\dfrac{21}{60}\))
= - \(\dfrac{3}{80}\) \(\times\) (- \(\dfrac{2}{3}\))
= \(\dfrac{1}{40}\)
b, (-1)3 + (- \(\dfrac{2}{3}\))2 : 2\(\dfrac{2}{3}\) + \(\dfrac{5}{6}\)
= -13 + \(\dfrac{4}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{4}{9}\) \(\times\) \(\dfrac{3}{8}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{1}{6}\) + \(\dfrac{5}{6}\)
= -1 + 1
= 0
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: \(=\dfrac{17}{21}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{17}{21}\)
2/5 : x = 1/3 x = 2/5 : 1/3 x= 6/5
x- 3/2 = 5/ 6 x = 5/6 + 3/2 x=7/3
x: 5/11 = 22 x = 22. 5/11 x= 10
3/22 x 3/11 x 22=
c1:\(\frac{3\times3\times22}{22\times11}=\frac{9}{11}\) c2:\(\frac{9}{242}\times22=\frac{9}{11}\)
( 1/2 + 1/3 ) x 2/5=
c1:\(\frac{5}{6}\times\frac{2}{5}=\frac{1}{3}\) c2:\(\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}=\frac{1}{5}+\frac{2}{15}=\frac{1}{3}\)
\(a)x+\frac{2}{3}=\frac{5}{6}\)
\(x=\frac{5}{6}-\frac{2}{3}\)
\(x=\frac{5}{6}-\frac{4}{6}=\frac{1}{6}\)
\(b)x-\frac{3}{5}=\frac{2}{7}+\frac{1}{5}\)
\(x=\frac{3}{5}-\frac{17}{35}\)
\(x=\frac{21}{35}-\frac{17}{35}\)
\(x=\frac{4}{35}\)
\(c)x\div\frac{9}{11}=\frac{5}{22}\)
\(x=\frac{5}{22}\times\frac{9}{11}\)
\(x=\frac{45}{242}\)
\(d)\frac{3}{5}\times x=\frac{3}{10}\)
\(x=\frac{3}{10}\div\frac{3}{5}\)
\(x=\frac{1}{2}\)
\(a)\)\(x+\frac{2}{3}=\frac{5}{6}\)
\(x=\frac{5}{6}-\frac{2}{3}\)
\(x=\frac{1}{6}\)
\(b)\)\(x-\frac{3}{5}=\frac{2}{7}+\frac{1}{5}\)
\(x-\frac{3}{5}=\frac{17}{35}\)
\(x=\frac{17}{35}+\frac{3}{5}\)
\(x=\frac{38}{35}\)
\(x-\frac{10}{3}=\frac{7}{15}.\frac{3}{5}\)
\(x-\frac{10}{3}=\frac{7}{25}\)
\(x=\frac{7}{25}+\frac{10}{3}=\frac{271}{75}\)
Vậy x = 271/75
\(x-\frac{10}{3}\)\(=\)\(\frac{7}{15}\)\(.\)\(\frac{3}{5}\)
\(x-\frac{10}{3}\)\(=\) \(\frac{7}{25}\)
\(x\) \(=\)\(\frac{7}{25}\)\(+\)\(\frac{10}{3}\)
\(x\) \(=\) \(\frac{271}{75}\)
\(x-\frac{1}{4}=\frac{5}{3}\)
\(\Rightarrow x=\frac{23}{12}\)
\(x:\frac{5}{11}=22\)
\(\Rightarrow x=10\)
\(\frac{2}{4}+x=1\)
\(\Rightarrow x=\frac{1}{2}\)
\(x-\frac{11}{5}=\frac{2}{5}:\frac{2}{3}\)
\(\Rightarrow x-\frac{11}{5}=\frac{3}{5}\)
\(\Rightarrow x=\frac{18}{5}\)
\(a)x-\frac{1}{4}=\frac{5}{3}\)
\(\Rightarrow x=\frac{5}{3}+\frac{1}{4}=\frac{23}{12}\)
\(b)x:\frac{5}{11}=22\)
\(\Rightarrow x=22.\frac{5}{11}=10\)
\(c)\frac{2}{4}+x=1\)
\(x=1-\frac{2}{4}=\frac{1}{2}\)
\(d)x-\frac{11}{5}=\frac{2}{5}:\frac{2}{3}\)
\(\Rightarrow x-\frac{11}{5}=\frac{3}{5}\)
\(\Rightarrow x=\frac{3}{5}+\frac{11}{5}=\frac{14}{5}\)
\(\frac{3}{22}\times\frac{3}{11}\times22\)
1.\(=\frac{3\times3\times22}{22\times11\times1}\)
\(=\frac{3\times3}{11\times1}\)
\(=\frac{9}{11}\)
2. \(=\frac{9}{242}\times22\)
\(=\frac{198}{242}\)
\(=\frac{9\times2\times11}{2\times11\times11}\)
\(=\frac{9}{11}\)
\(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}\)
1.\(=\frac{5}{6}\times\frac{2}{5}\)
\(=\frac{5\times2}{3\times2\times5}\)
\(=\frac{1}{3}\)
2.\(\)\(=\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}\)
\(=\frac{1}{5}+\frac{2}{15}\)
\(=\frac{3}{15}+\frac{2}{15}\)
\(=\frac{5}{15}=\frac{1}{3}\)
Have a good day
2 . 11x = ( 32 + 23 ) : ( 53 - 55 : 23 ) . 22
2 . 11x = ( 9 + 8 ) : ( 125 - 3125 : 8 ) . 22
2 . 11x = 17 : ( 125 - 390,625 ) . 22
2 . 11x = 17 : ( - 265,625 ) . 22
2 . 11x = ( - 0,064 ) . 22
2 . 11x = - 1,408
11x = - 1,408 : 2
11x = - 0,704
\(\Rightarrow\)Ko có giá trị để thỏa mãn x
\(\Rightarrow\)x \(\in\)\(\varnothing\)
* Sai thì sr bạn nhaa ;(