Tìm y biết : { y + 1/3 } + { y + 1/9 } + { y + 1/27 } = 25/27
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4 x y + (1/3 + 1/9 + 1/27 + 1/81) = 56/81
4 x y + (27/81 + 9/81 + 3/81 + 1/81) = 56/81
4 x y + 40/81 = 56/81
4 x y = 56/81 - 40/81 = 16/81
y = 4/81
\(\left(y+\frac{1}{3}\right) +\left(y+\frac{1}{9}\right)+ \left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)
\(y\cdot4+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\right)=\frac{56}{81}\)
\(y\cdot4+\frac{40}{81}=\frac{56}{81}\)
\(y\cdot4=\frac{56}{81}-\frac{40}{81}\)
\(y\cdot4=\frac{16}{81}\)
\(y=\frac{16}{81}:4\)
\(y=\frac{4}{81}\)
1+3+9+27+......+y=1093
3x(1+3+9+27+.....+y)=1093x3
3+9+27+81+.....+3y=1093x3
=> 1093x3-1093= (3+9+27+.....3y)-(1+3+9+27+....+y)
<=> 1093x2=3y-1
<=>2186+1=3y
<=> 2187=3y
=> y=2187:3
y=729
\(\left(y+\frac{1}{3}\right)+\left(y+\frac{1}{9}\right)+\left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)
\(\Leftrightarrow4y+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\right)=\frac{56}{81}\)
\(\Leftrightarrow4y+\frac{40}{81}=\frac{56}{81}\)
\(\Leftrightarrow4y=\frac{56}{81}-\frac{40}{81}\)
\(\Leftrightarrow4y=\frac{16}{81}\)
\(\Rightarrow y=\frac{16}{81}\div4\)
\(\Rightarrow y=\frac{4}{81}\)
Vậy y có giá trị =\(\frac{4}{81}\)
Lời giải:
a)
$3^{2x+1}.7^y=9.21^x=3^2.(3.7)^x=3^{2+x}.7^x$
Vì $x,y$ là số tự nhiên nên suy ra $2x+1=2+x$ và $y=x$
$\Rightarrow x=y=1$
b) \(\frac{27^x}{3^{2x-y}}=\frac{3^{3x}}{3^{2x-y}}=3^{x+y}=243=3^5\Rightarrow x+y=5(1)\)
\(\frac{25^x}{5^{x+y}}=\frac{5^{2x}}{5^{x+y}}=5^{x-y}=125=5^3\Rightarrow x-y=3\) $(2)$
Từ $(1);(2)\Rightarrow x=4; y=1$
Tìm y :
( y + 1/3 ) + ( y + 1/9 ) + ( y + 1/27 ) + ( y + 1/81 ) = 56/81
y + 1/3 + y + 1/9 + y + 1/27 + y + 1/81 = 56/81
y x 4 + ( 1/3 + 1/9 + 1/27 +1/81 ) = 56/81
y x 4 + ( 27/81 + 9/81 + 3/81 + 1/81 ) = 56/81
y x 4 + 40/81 = 56/81
y x 4 = 56/81 - 40/81
y x 4 = 16/81
y = 16/81 : 4
y = 4/81
{ y + 1/3 } + { y + 1/9 } + { y + 1/27 } = 25/27
3y + 1/3 + 1/9 + 1/27= 25/27
3y+ 9/27+3/27+1/27= 25/27
3y + 13/27= 25/27
3y= 12/27
=> y= 4/27