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{ y + 1/3 } + { y + 1/9 } + { y + 1/27 } = 25/27
3y + 1/3 + 1/9 + 1/27= 25/27
3y+ 9/27+3/27+1/27= 25/27
3y + 13/27= 25/27
3y= 12/27
=> y= 4/27
4 x y + (1/3 + 1/9 + 1/27 + 1/81) = 56/81
4 x y + (27/81 + 9/81 + 3/81 + 1/81) = 56/81
4 x y + 40/81 = 56/81
4 x y = 56/81 - 40/81 = 16/81
y = 4/81
\(\left(y+\frac{1}{3}\right) +\left(y+\frac{1}{9}\right)+ \left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)
\(y\cdot4+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\right)=\frac{56}{81}\)
\(y\cdot4+\frac{40}{81}=\frac{56}{81}\)
\(y\cdot4=\frac{56}{81}-\frac{40}{81}\)
\(y\cdot4=\frac{16}{81}\)
\(y=\frac{16}{81}:4\)
\(y=\frac{4}{81}\)
Tìm y :
( y + 1/3 ) + ( y + 1/9 ) + ( y + 1/27 ) + ( y + 1/81 ) = 56/81
y + 1/3 + y + 1/9 + y + 1/27 + y + 1/81 = 56/81
y x 4 + ( 1/3 + 1/9 + 1/27 +1/81 ) = 56/81
y x 4 + ( 27/81 + 9/81 + 3/81 + 1/81 ) = 56/81
y x 4 + 40/81 = 56/81
y x 4 = 56/81 - 40/81
y x 4 = 16/81
y = 16/81 : 4
y = 4/81
a) (x+1)/3 + (x+1)/9 + (x+1)/27 + (x+1)/81 = 56/81
<=> (27x+27)/81 + (9x+9)/81 + (3x+3)/81 + (x+1)/81 = 56/81 (quy đồng)
<=> 27x + 9x + 3x + x + 27 + 9 + 3 + 1 = 56 (khử mẫu)
<=> 40x = 56- 40 = 16
<=> x = 16/40 = 2/5
~ hok tốt ~
y + 1/3 + y+ 1/9 +y +1/27 + y+ 1/81 =56/81
4y +(1/3 +1/9+1/27+1/81) = 56/81
4y +(27 +9+3+1/81)=56/81
4y +40/81=56/81
4y =56/81 -40/81
4y=16/81
y=16/81 .1/4
y=4/81
1, \(\frac{1}{2}-\left(6\frac{5}{9}+x-\frac{117}{8}\right):\left(12\frac{1}{9}\right)=0\)
\(\left(\frac{6.9+5}{9}+x-\frac{117}{8}\right):\frac{12.9+1}{9}=\frac{1}{2}\)
( . là nhân nha)
\(\left(\frac{59}{9}-\frac{117}{8}+x\right):\frac{109}{9}=\frac{1}{2}\)
\(\frac{59}{9}-\frac{117}{8}+x=\frac{1}{2}\cdot\frac{109}{9}\)
\(\frac{59}{9}-\frac{117}{8}+x=\frac{109}{18}\)
\(x=\frac{109}{18}-\frac{59}{9}+\frac{117}{8}\)
\(x=\frac{113}{8}\)
( \(\left(y+\frac{1}{3}\right)+\left(y+\frac{2}{9}\right)+\left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)
\(y+\frac{1}{3}+y+\frac{2}{9}+y+\frac{1}{27}+y+\frac{1}{81}=\frac{56}{81}\)
\(4y+\frac{1}{3}+\frac{2}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)
\(4y+\frac{49}{81}=\frac{56}{81}\)
\(4y=\frac{7}{81}\)
y = 7/81:4
y = 7/324
9/4 - y × 5/6 = 1/2 + 1/3
9/4 - y × 5/6 = 5/6
y × 5/6 = 9/4 - 5/6
y × 5/6 = 17/12
y = 17/12 : 5/6
y = 17/10
1+3+9+27+......+y=1093
3x(1+3+9+27+.....+y)=1093x3
3+9+27+81+.....+3y=1093x3
=> 1093x3-1093= (3+9+27+.....3y)-(1+3+9+27+....+y)
<=> 1093x2=3y-1
<=>2186+1=3y
<=> 2187=3y
=> y=2187:3
y=729