Tìm x
\(3^{x-1}+5.3^{x-1}=162\)
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3x-1+5.3x-1=162
=>3x-1.(1+5)=162
=>3x-1.6=162=>3x-1=162:6=27=33
=>x-1=3=>x=4
5x+5x+2=650
=>5x+5x.52=650
=>5x.(1+25)=650
=>5x.26=650=>5x=650:26=25=52
=>x=2
3x - 1 + 5.3x - 1=162
3x - 1 .(1+5)=162
3x - 1=27
3x :31=27
3x=81
3x=34
=> x=4
\(a)3^{x-1}+5\cdot3^{x-1}=162\)
\(\Rightarrow3^{x-1}(1+5)=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=27\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Câu b tự làm nhé
3x-1 + 5 . 3x-1 = 162
3x-1 . 1 + 5 . 3x-1 = 162
3x-1 . ( 1 + 5 ) = 162
3x-1 . 6 = 162
3x-1 = 162 : 6
3x-1 = 27
3x-1 = 33
=> x - 1 = 3
=> x = 3 + 1
=> x = 4
2x+ 3= x+ 2
2x- x= 2- 3
x= -1
vậy x=-1
b) \(3^{x-1}+5.3^{x-1}=162
\)
\(3^{x-1}.\left(1+5\right)=162\)
\(3^{x-1}.6=162\)
\(3^{x-1}=162:6\)\(\Rightarrow3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
3-1 . 3x + 5.3x - 1 = 162
=> 3x - 1 + 5.3x - 1 = 162
=> 3x - 1. (1 + 5) = 162
=> 3x - 1 . 6 = 162
=> 3x - 1 = 162
=> 3x - 1 = 27
=> 3x - 1 = 33
=> x - 1 = 3
=> x = 3 + 1
=> x =4
3^x-1+5.3^x-1=162
3^x-1.(1+5)=162
3^x-1.6=162
3^x-1=162:6
3^x-1=27
3^x-1=3^3
x-1=3
x=3+1
x=4
(3x+1)^3=-216=(-6)^3
=>3x+1=-6
=>x=...
3^x-1+5.3^x-1=162
=>3^x-1.(1+5)=162
=>3^x-1.6=162
=>3^x-1=162:6=27
=>3^x-1=3^3
=>x-1=3
=>x=4
3x−1+5.3x−1=162
=>3x−1(1+5)=162
=>3x−1.6=162
=>3x−1=162:6
=>3x-1=27
=>3x-1=33
=>x-1=3
=>x=4