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A=1/2-1/3+1/3-1/4+...+1/19-1/20

=1/2-1/20

=9/20

15 tháng 4 2022

A= 1/2 x 3 + 1/3 x 4 + 1/4 x 5 + 1/5 x 6 + 1/6 x 7 + ... + 1/19 x 20
--> A= 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 +...+ 1/19 - 1/20
        = 1/2 - 1/20 = 10/20 - 1/20 = 9/20

b) Ta có: \(5^{x+4}-3\cdot5^{x+3}=2\cdot5^{11}\)

\(\Leftrightarrow2\cdot5^{x+3}=2\cdot5^{11}\)

\(\Leftrightarrow x+3=11\)

hay x=8

c) Ta có: \(2\cdot3^{x+2}+4\cdot3^{x+1}=10\cdot3^6\)

\(\Leftrightarrow18\cdot3^x+12\cdot3^x=10\cdot3^6\)

\(\Leftrightarrow30\cdot3^x=30\cdot3^5\)

Suy ra: x=5

d) Ta có: \(6\cdot8^{x-1}+8^{x+1}=6\cdot8^{19}+8^{21}\)

\(\Leftrightarrow6\cdot\dfrac{8^x}{8}+8^x\cdot8=6\cdot8^{19}+64\cdot8^{19}\)

\(\Leftrightarrow8^x\cdot\dfrac{35}{4}=70\cdot8^{19}\)

\(\Leftrightarrow8^x=8^{20}\)

Suy ra: x=20

5 tháng 9 2021

\(\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-19\\ \Leftrightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6=-19\\ \Leftrightarrow12x=-15\\ \Leftrightarrow x=-\dfrac{15}{12}=-\dfrac{5}{4}\)

5 tháng 9 2021

\(\Leftrightarrow\)\(x^3+3x^2+3x+1-(x^3-3x^2+3x-1)-(6x^2-12x+6)+19=0\)

\(\Leftrightarrow\)\(x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6+19=0\)

\(\Leftrightarrow\)\(12x+15=0\)

\(\Leftrightarrow\)\(x=-\dfrac{5}{4}\)

5 tháng 9 2021

d. (x - 3)(x2 + 3x + 9) + x(x + 2)(2 - x) = 1

<=> x3 - 9 + (x2 + 2x)(2 - x) = 1

<=> x3 - 9 + 2x2 - x3 + 4x - 2x2 = 1

<=> 4x = 10

<=> x = \(\dfrac{10}{4}=\dfrac{5}{2}\)

5 tháng 9 2021

d)(x - 3)(x^2 + 3x + 9) + x(x + 2)(2 - x) = 1

\(<=> x^3-27-x(x^2-4)=1\)

\(<=> x^3-27-x^3-4x=1<=>-4x=28<=> x=-7\)

=> ptrình có tập nghiệm S={-7}

e) (x + 1)^3 - (x - 1)^3 - 6(x - 1)^2 = -19

\(<=> x^3+3x^2+3x+1-(x^3-3x^2+3x-1)-6(x^2-2x+1)+19=0\)

\(<=>x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6+19=0\)

\(<=>12x=15<=>x=12/15 \)

=> ptrình có tập nghiệm S={12/15}

`#3107.101107`

\(x(x+5)(x-5) - (x+2)(x^2-2x+4)=5\)

`<=> x(x^2 - 25) - (x^3 + 2^3) = 5`

`<=> x^3 - 25x - x^3 - 8 = 5`

`<=> -25x - 8 = 5`

`<=> -25x = 13`

`<=> x = -13/25`

Vậy, `x = -13/25`

_____

\((x+1)^3 - (x-1)^3 -6(x-1)^2 = -19\)

`<=> x^3 + 3x^2 + 3x + 1 - (x^3 - 3x^2 + 3x - 1) - 6(x^2 - 2x + 1) = -19`

`<=> x^3 + 3x^2 + 3x + 1 - x^3 + 3x^2 - 3x + 1 - 6x^2 + 12x - 6 = -19`

`<=> (x^3 - x^3) + (3x^2 + 3x^2 - 6x^2) + (3x - 3x + 12x) + (1 + 1 - 6) = -19`

`<=> 12x - 4 = -19`

`<=> 12x = -15`

`<=> x = -15/12 = -5/4`

Vậy, `x = -5/4.`

________

`@` Sử dụng các hđt:

`1)` `A^2 + B^2 = (A - B)(A + B)`

`2)` `A^3 + B^3 = (A + B)(A^2 - AB + B^2)`

`3)` `(A - B)^3 = A^3 - 3A^2B + 3AB^2 - B^3`

`4)` `(A + B)^3 = A^3 + 3A^2B + 3AB^2 + B^3`

`5)` `(A - B)^2 = A^2 - 2AB + B^2.`

23 tháng 10 2023

a: \(x\left(x+5\right)\left(x-5\right)-\left(x+2\right)\left(x^2-2x+4\right)=5\)

=>\(x\left(x^2-25\right)-x^3-8=5\)

=>\(x^3-25x-x^3-8=5\)

=>-25x=13

=>\(x=-\dfrac{13}{25}\)

b: \(\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-19\)

=>\(x^3+3x^2+3x+1-x^3+3x^2-3x+1-6\left(x^2-2x+1\right)=-19\)

=>\(6x^2+2-6x^2+12x-6=-19\)

=>12x-4=-19

=>12x=-15

=>x=-5/4

1: x=3/4-1/2=3/4-2/4=1/4

2: x-1/5=2/11

=>x=2/11+1/5=21/55

3: x-5/6=16/42-8/56

=>x-5/6=8/21-4/28=5/21

=>x=5/21+5/6=15/14

4: x/5=5/6-19/30

=>x/5=25/30-19/30=6/30=1/5

=>x=1

5: =>|x|=1/3+1/4=7/12

=>x=7/12 hoặc x=-7/12

6: x=-1/2+3/4

=>x=3/4-1/2=1/4

11: x-(-6/12)=9/48

=>x+1/2=3/16

=>x=3/16-1/2=-5/16

21 tháng 7 2023

1)x= 1/4

2)x= 2/11+ 1/5

   x= 21/55

3)x - 5/6 = 5/21

   x         = 5/21+5/6

   x         = 15/14

4)x/5 = 5/6 + -19/30

   x:5 = 1/5

   x    = 1/5.5

   x    = 1

5) |x| - 1/4 = 6/18

    |x|           = 6/18 - 1/4

    |x|            =7/12

⇒x= 7/12 hoặc -7/12

6)x = -1/2 +3/4

   x= 1/4

7) x/15 = 3/5 + -2/3

   x:15  = -1/15

  x        = -1/15. 15

  x        = -1

8)11/8 + 13/6 = 85/x  

       85/24      = 85/x

  ⇒      x           = 24

9) x - 7/8 = 13/12

   x          = 13/12 + 7/8

   x          = 47/24

10)x - -6/15 = 4/27  

     x            = 4/27 + (-6/15)

    x             = -34/135

11) -(-6/12)+x = 9/48

                    x= 9/48 - 6/12

                    x = -5/16

12) x - 4/6 = 5/25 + -7/15

      x -4/6  =  -4/15

     x           = -4/15 + 4/6

    x             = 2/5

16 tháng 7 2019

\(\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-19\)

\(\Rightarrow x^3+2x^2+x+x^2+2x+1-x\left(x^2-2x+1\right)+\left(x^2-2x+1\right)-6x^2+12x-6=-19\)

\(\Rightarrow x^3+2x^2+x+x^2+2x+1-x\left(x^2-2x+1\right)+x^2-2x+1-6x^2+12x-6=-19\)

\(\Rightarrow x^3-2x^2+13x-4-x\left(x^2-2x+1\right)=-19\)

\(\Rightarrow x^3-2x^2+13x-4-x^3+2x^2-x=-19\)

\(\Rightarrow12x-4=-19\)

\(\Rightarrow12x=-15\)

\(\Rightarrow x=\frac{-5}{4}\)

23 tháng 7 2021

b)(x+3)2-(x-4)(x+8)=1

\(\Rightarrow\)x2+6x+9-(x2+8x-4x-32)=1

⇒x2+6x+9-x2-8x+4x+32=1

⇒2x+41=1

\(\Rightarrow\)2x+41-1=0

\(\Rightarrow\)2x+40=0

⇒2x=-40

\(\Rightarrow\)x=\(\dfrac{-40}{2}\)

⇒x=-20

28 tháng 8 2021

a,

\(5^{x+4}-3.5^{x+3}=2.5^{11}\)

\(\Rightarrow5^{x+3}\left(5-3\right)=2.5^{11}\)

\(\Rightarrow5^{x+3}2=2.5^{11}\)

\(\Rightarrow5^{x+3}=5^{11}\)

\(\Rightarrow x+3=11\)

\(\Rightarrow x=8\)

28 tháng 8 2021

b, (Check lai xem de sai o dau khong nhe)

\(3.5^{x+2}+4.5^{x+3}=19.5^{10}\)

Dat 5x ra ben ngoai

\(\Rightarrow5^x.5^23+5^x:5^{-3}.4\)

\(\Rightarrow5^x\left(5^2.3+5^{-3}.4\right)\)

\(\Rightarrow5^x\left(5^{-3}.5^5.3+5^{-3}.4\right)\)

\(\Rightarrow5^x[5^{-3}\left(5^53+4\right)\)

\(\Rightarrow5^x[5^{-3}\left(3125.3+4\right)\)

\(\Rightarrow5^x\left(5^{-3}\right).9379\)

=> Khong tim duoc gia tri cua x \(\Rightarrow x\in\varnothing\)