(1/3+1/6)^2:(-0,5)^2
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DT
1
2 tháng 9 2019
a.\(\frac{3}{5}+0,5-\frac{1}{4}+\frac{7}{2}\)/\(\frac{-6}{5}+\frac{1}{6}-\frac{13}{5}+0,5\)
=(\(\frac{3}{5}+\frac{1}{2}-\frac{1}{4}+\frac{7}{2}\)).60/(\(\frac{-6}{5}+\frac{1}{6}-\frac{13}{5}+\frac{1}{2}\)).60
=(36+30-15+210)/(-72+10-156+30)
=261/-188
DT
0
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
14 tháng 12 2022
( 2 + 4) : 1 : 1 + 2\(\dfrac{6}{12}\) + 3 + 0,5
= 6: 1:1 + \(\dfrac{5}{2}\) + 3,5
= 6 + 2,5 + 3,5
= 6 + 6
= 12
11 tháng 6 2023
`@` `\text {Ans}`
`\downarrow`
`1)`
`5/7*37 13/23 - 51 13/23*5/7`
`= 5/7* (37 13/23 - 51 13/23)`
`= 5/7* (-14)`
`= -10`
`2)`
`-2/3 +1/3+0,5+2 1/2`
`= -2/3 + 1/3 + 1/2 + 5/2`
`= (-2/3+1/3) + (1/2+5/2)`
`= -1/3 + 3`
`=8/3`
`3)`
`-0,5+2/3+1/2`
`= -1/2 + 2/3 + 1/2`
`= (-1/2 + 1/2) + 2/3`
`= 2/3`
`4)`
`(8+2 1/3-3/5) -(5+0,4)-(3 1/2 -2)`
`= 8+ 7/3 - 3/5 - 5 - 0,4 - 7/2 + 2`
`= (8+2-5) + (-3/5 - 2/5) + (7/3 - 7/2)`
`= 5 - 1 - 7/6`
`= 4 - 7/6 = 17/6`
`5)`
`(2/9-7/12):3/4+(16/9-5/12):3/4`
`= (2/9 - 7/12) \times 4/3 + (16/9 - 5/12) \times 4/3`
`= 4/3 *(2/9 - 7/12 + 16/9 - 5/12)`
`= 4/3 * [(2/9 + 16/9) + (-7/12 - 5/12)]`
`= 4/3 * ( 2 - 1)`
`= 4/3 * 1 = 4/3`
`6)`
`-(2021.0,7+19,75) +0,7- (8-19,75)`
`= -2021*0,7 -19,75 + 0,7 - 8 + 19,75`
`= 0,7*(-2021 + 1) - 8`
`= -1414-8`
`= -1422`
`7)`
`15/34+7/21+19/34-20/15`
`= (15/34 + 19/34) + 7/21 - 20/15`
`= 1 + 7/21 - 20/15`
`= 4/3 - 20/15 =0`
`8)`
`2 5/6+1/6:(-5/8)`
`= 17/6 + (-4/15)`
`= 77/30`
`9)`
`(-2)^2 +2/9. (4/5-2/3)`
`= 4 + 2/9*2/15`
`= 4+4/135`
`= 544/135`
`10)`
`(-1/5+3/7):5/4+(-4/5+4/7):5/4`
`= (-1/5+3/7) * 4/5 + (-4/5+4/7) * 4/5`
`= 4/5*(-1/5 +3/7-4/5+4/7)`
`= 4/5*[(-1/5-4/5)+(3/7+4/7)]`
`= 4/5* (-1+1)`
`= 4/5*0=0`
`11)`
`2022,2021 . 1954,1945+ 2022,2021 . (-1954,1945)`
`= 2022,2021 * [1954,1945 + (-1954,1945)]`
`= 2022,2021*0 `
`= 0`
`12)`
`-5,2 .72 +69,1 +5,2 . (-28)+(-1,1)`
`= -5,2*72 + 69,1 - 5,2*28 - 1,1`
`= -5,2*(72+28) + (69,1 - 1,1)`
`= -5,2*100 + 68`
`= -520 + 68`
`= -452`
`13)`
`(7 -1/2-3/4) : (5-1/4-5/8)`
`= 23/4 \div 33/8`
`=46/33`
`14)`
`(8+ 2 1/3 -3/5) -(5+0,4) -( 3 1/3 - 2)`
`= 8+ 2 1/3 - 3/5 - 5 - 0,4 - 3 1/3 + 2`
`= (8+2-5) + (2 1/3 - 3 1/3) - (0,6 + 0,4) `
`= 5 - 1 - 1`
`= 3`
HN
0
MP
1
2 tháng 4 2020
viết lại đề:
\(\left(0,5-\frac{7}{13}-\frac{1}{3}\right)\)\(-\left(\frac{6}{13}+-\frac{1}{2}-1\frac{1}{3}\right)\)
=\(\left(\frac{1}{2}-\frac{7}{13}-\frac{1}{3}\right)-\left(\frac{6}{13}-\frac{1}{2}-1\frac{1}{3}\right)\)
=\(\frac{1}{2}-\frac{7}{13}-\frac{1}{3}-\frac{6}{13}+\frac{1}{2}-1\frac{1}{3}\)
=\(\left(\frac{1}{2}+\frac{1}{2}\right)+\left(\frac{-7}{13}-\frac{6}{13}\right)-\left(\frac{-1}{3}-1\frac{1}{3}\right)\)
\(=1+\left(-1\right)-\frac{4}{3}\)
\(=\frac{-4}{3}\)
\(\left(\dfrac{1}{3}+\dfrac{1}{6}\right)^2:\left(-0,5\right)^2\)
\(=\left(\dfrac{2}{6}+\dfrac{1}{6}\right)^2:0,25\)
\(=\left(\dfrac{3}{6}\right)^2:\dfrac{25}{100}\)
\(=\left(\dfrac{1}{2}\right)^2:\dfrac{1}{4}\)
\(=\dfrac{1}{4}:\dfrac{1}{4}\)
\(=\dfrac{1}{4}.\dfrac{4}{1}\)
\(=1\)
(\(\dfrac{1}{3}\) + \(\dfrac{1}{6}\))2 :(-0,5)2
= \(\dfrac{1}{4}\) : 0,25
= \(\dfrac{1}{4}\) : \(\dfrac{1}{4}\)
=1