SO SÁNH :
a) \(\dfrac{-18}{91}\)và \(\dfrac{-23}{114}\)
b)\(\dfrac{-22}{35}\)và\(\dfrac{-103}{177}\)
c)\(\dfrac{-22}{45}\)và\(\dfrac{-17}{33}\)
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a. \(\dfrac{-18}{91}\) và \(\dfrac{-23}{114}\)
\(\dfrac{18}{91}< \dfrac{18}{90}=\dfrac{1}{5}=\dfrac{23}{115}< \dfrac{23}{114}\)
\(\Rightarrow\dfrac{-18}{91}>\dfrac{-23}{114}\)
b. \(\dfrac{-22}{35}\) và \(\dfrac{-103}{177}\)
\(\dfrac{22}{35}=\dfrac{110}{175}>\dfrac{103}{175}>\dfrac{103}{177}\)
\(\Rightarrow\dfrac{-22}{35}< \dfrac{-103}{177}\)
a: \(\dfrac{-18}{91}>\dfrac{-18}{90}=\dfrac{-1}{5}\)
\(\dfrac{-23}{114}< \dfrac{-23}{115}=\dfrac{-1}{5}\)
Do đó: \(\dfrac{-18}{91}>\dfrac{-23}{114}\)
b: \(\dfrac{-22}{35}=\dfrac{-3894}{6195}\)
\(\dfrac{-103}{177}=\dfrac{-103\cdot35}{177\cdot35}=\dfrac{-3605}{6195}\)
mà -3894<-3605
nên -22/35<-103/177
a: \(\dfrac{119}{117}=1+\dfrac{2}{117}\)
\(\dfrac{117}{115}=1+\dfrac{2}{115}\)
mà 2/117<2/115
nên \(\dfrac{119}{117}< \dfrac{117}{115}\)
hay \(-\dfrac{119}{117}>-\dfrac{117}{115}\)
b: \(\dfrac{-22}{35}=\dfrac{-22\cdot177}{35\cdot177}=-\dfrac{3894}{6195}\)
\(\dfrac{-103}{177}=\dfrac{-103\cdot35}{177\cdot35}=\dfrac{-3605}{6195}\)
mà -3894<-3605
nên -22/35<-103/177
a) ( -18/91) < (-18/90)=-1/5
-23/114 > -23/115= -1/5
Vậy -18/91 < -23/114
\(a,\dfrac{-15}{17}=-1+\dfrac{2}{17}\\ -\dfrac{19}{21}=-1+\dfrac{2}{21}\\ Vì:\dfrac{2}{17}>\dfrac{2}{21}\Rightarrow-1+\dfrac{2}{17}>-1+\dfrac{2}{21}\Rightarrow-\dfrac{15}{17}>-\dfrac{19}{21}\\ b,-\dfrac{24}{35}=-1+\dfrac{11}{35};-\dfrac{19}{30}=-1+\dfrac{11}{30}\\ Vì:\dfrac{11}{35}< \dfrac{11}{30}\Rightarrow-1+\dfrac{11}{35}< -1+\dfrac{11}{30}\\ \Rightarrow-\dfrac{24}{35}< -\dfrac{19}{30}\)
a) Ta có \(\dfrac{23}{27}>\dfrac{23}{29};\dfrac{23}{29}>\dfrac{22}{29}\)
Vậy \(\dfrac{23}{27}>\dfrac{22}{29}\)
b) Ta có \(\dfrac{15}{25}=1-\dfrac{2}{5}\)
\(\dfrac{25}{49}=1-\dfrac{24}{49}\)
Vì \(\dfrac{2}{5}=\dfrac{24}{60}< \dfrac{24}{49}\)
Vậy \(\dfrac{15}{25}>\dfrac{25}{49}\)
\(\dfrac{-22}{45}=-\dfrac{2266}{45.103}>-\dfrac{2295}{45.103}=-\dfrac{51}{103}\)
Ta có: \(\dfrac{-22}{45}=\dfrac{-22\cdot103}{45\cdot103}=\dfrac{-2266}{4635}\)
\(\dfrac{-51}{103}=\dfrac{-51\cdot45}{103\cdot45}=\dfrac{-2295}{4635}\)
mà -2266>-2295
nên \(\dfrac{-22}{45}>\dfrac{-51}{103}\)
a. \(\dfrac{-18}{91}\) và \(\dfrac{-23}{114}\) ( mẫu chung : 10374 )
Quy đồng : \(\dfrac{-18}{91}=\dfrac{-2052}{10374}\) ; \(\dfrac{-23}{114}=\dfrac{-2093}{10374}\)
Vì \(\dfrac{-2052}{10374}>\dfrac{-2093}{10374}\Rightarrow\dfrac{-18}{91}>\dfrac{-23}{114}\)
Vậy...
b. \(\dfrac{-22}{35}\) và \(\dfrac{-103}{177}\) ( MC = 6195 )
Quy đồng : \(\dfrac{-22}{35}=\dfrac{-3894}{6195};\dfrac{-103}{177}=\dfrac{-3605}{6195}\)
Vì \(\dfrac{-3894}{6195}< \dfrac{-3605}{6195}\Rightarrow\dfrac{-22}{35}< \dfrac{-103}{177}\)
Vậy...
c. \(\dfrac{-22}{45}\) và \(\dfrac{-17}{33}\)(MC=495)
Quy đồng : \(\dfrac{-22}{45}=\dfrac{-242}{495};\dfrac{-17}{33}=\dfrac{-255}{495}\)
Vì \(\dfrac{-242}{495}>\dfrac{-255}{495}\Rightarrow\dfrac{-22}{45}>\dfrac{-17}{33}\)
Vậy