(x+2345)+a=678+(2345+a)
Tìm x
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a/\(-\left(-432-3x\right)+\left(-432-4x+21\right)=-2345\)
\(\Leftrightarrow+432+3x-432-4x+21=-2345\)\(\Leftrightarrow\left[432+\left(-432\right)\right]+\left[\left(-4x\right)+3x\right]+21=-2345\)
\(\Leftrightarrow0+-1x+21=-2345\)\(\Leftrightarrow-1x=-2345-21=-2366\)
\(\Rightarrow x=\left(-2366\right):\left(-1\right)=2366\)
b/\(12x-\left(-3546-3x\right)=\left(2x-234\right)-\left(-678-2x\right)\)
\(\Leftrightarrow12x+3546+3x=2x-234+678+2x\)
\(\Leftrightarrow15x+3546=\left(2x+2x\right)+\left[\left(-234\right)+678\right]\)
\(\Leftrightarrow15x+3546=4x+444\)
\(\Leftrightarrow15x+3546-4x-444=0\)
\(\Leftrightarrow\left(15x-4x\right)+\left(3546-444\right)=0\)
\(\Leftrightarrow11x+3102=0\)
\(\Leftrightarrow11x=0-3102=-3102\)
\(\Rightarrow x=\left(-3102\right):11=-282\)
x + ( x + 1 ) + ( x + 2 ) + .... + ( x + 2344 ) + 2345 = 2345
( có 2346 số hạng )
x + ( x + 1 ) + ( x + 2 ) + ..... + ( x + 2344 ) = 2345 - 2345
x + ( x + 1 ) + ( x + 2 ) + ..... + ( x + 2344 ) = 0
( có 2345 số hạng )
[ ( x + 2344 ) + x ] . 2345 : 2 = 0
[ ( x + 2344 ) + x ] . 2345 = 0 . 2
( 2x + 2344 ) . 2345 = 0
2x + 2344 = 0 : 2345
2x + 2344 = 0
2x = 0 - 2344
2x = - 2344
x = - 2344 : 2 = - 1172
Vậy x = - 1172
x=2344 nên x+1=2345
\(A=x^5-x^4\left(x+1\right)+x^3\left(x+1\right)-x^2\left(x+1\right)+x\left(x+1\right)-\left(x+1\right)\)
\(=x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x-x-1\)
=-1
a) X – 34562 = 2345
X= 2345 + 34562
X = 36907
b) X : 34 = 1023
X= 1023 x 34
X =34782
2345 x 25 + 2345 x 75 + 2345
= 2345 x (25+75+1)
= 2345 x 101
=236845
\(=2345\times\left(25+75+1\right)\)
\(=2345\times101\)
\(=236845\)