( 16. 17 - 5 ) : ( 16 . 16 +11)
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\(16.17-\dfrac{5}{16}\times16+11\)
\(=272-5+11\)
\(=278\)
d: \(\dfrac{5}{16}-\dfrac{5}{24}=\dfrac{5\cdot3}{48}-\dfrac{5\cdot2}{48}=\dfrac{5}{48}\)
e: \(-\dfrac{24}{17}-\left(-\dfrac{7}{17}-\dfrac{1}{16}\right)\)
\(=-\dfrac{24}{17}+\dfrac{7}{17}+\dfrac{1}{16}=-1+\dfrac{1}{16}\)
\(=-\dfrac{15}{16}\)
f: \(\dfrac{-11}{6}+\dfrac{2}{5}+\dfrac{-1}{6}\)
\(=\left(-\dfrac{11}{6}-\dfrac{1}{6}\right)+\dfrac{2}{5}\)
\(=-2+\dfrac{2}{5}=\dfrac{-8}{5}\)
(16.17-5) : (16.20+11) = (272-5) : (320+11)
= 267:331
=0,8066465257
Ta có :\(\frac{16\times17-5}{16\times16+11}\)
\(=\frac{16\times\left(16+1\right)-5}{16\times16+11}\)
\(=\frac{16\times16+16-5}{16\times16+11}\)
\(=\frac{16\times16+11}{16\times16+11}\)
\(=1\)
\(\frac{16×17-5}{16×16+11}\)
\(=\frac{17-5}{16+11}\)
\(=\frac{12}{27}\)
ta có
\(\dfrac{11}{16}< \dfrac{13}{16}< \dfrac{16}{16}< \dfrac{17}{16}\) (do cùng mẫu)
`=>` phân số lớn nhất là `17/16`
`=>C`
3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
(16.17-5):(16.16+11)
=(272-5):(256+11)
=267 : 267
= 1
\(\left(16.17-5\right):\left(16.16+11\right)\)
\(\frac{16.17-5}{16.16+11}\)
\(\frac{17-5}{16+11}\)
\(\frac{12}{27}\)