Tính hợp lý
a.342.67 + 342.16 + 658.83
b.(-2) + 4 + (- 6) + 8 +(-10) + 12
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a: =3/4-19/18-3/4
=-19/18
b: =24-24x47-24x54
=24(1-47-54)
=24x(-100)=-2400
Bài 5:
a: x(x-4)=0
=>\(\left[{}\begin{matrix}x=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)
b: Đề thiếu vế phải rồi bạn
Bài 6:
a: \(\left(-5\right)\cdot\left(-6\right)\cdot\left(-4\right)\cdot2\)
\(=-\left(2\cdot5\right)\cdot\left(4\cdot6\right)\)
\(=-24\cdot10=-240\)
b: \(\left(-3\right)\cdot2\cdot\left(-8\right)\cdot5\)
\(=3\cdot2\cdot8\cdot5\)
\(=\left(3\cdot8\right)\cdot\left(2\cdot5\right)\)
\(=24\cdot10=240\)
Câu 5:
a: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
b: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=\left(-12\right)\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
c: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot10=450\)
d: \(-48+48\left(-78\right)+48\left(-21\right)\)
\(=48\left(-1-78-21\right)\)
\(=48\left(-100\right)=-4800\)
Câu 4:
a: \(\left(-6-2\right)\left(-6+2\right)=\left(-8\right)\cdot\left(-4\right)=32\)
b: \(\dfrac{\left(7\cdot3-3\right)}{-6}=\dfrac{21-3}{-6}=\dfrac{18}{-6}=-3\)
c: \(\left(-5+9\right)\cdot\left(-4\right)=4\cdot\left(-4\right)=-16\)
d: \(\dfrac{72}{-6\cdot2+4}=\dfrac{72}{-12+4}=\dfrac{72}{-8}=-9\)
a: \(=\dfrac{48-45}{54}\cdot\dfrac{9}{4}=\dfrac{3}{54}\cdot\dfrac{9}{4}=\dfrac{27}{216}=\dfrac{1}{8}\)
b: \(=\dfrac{6}{5}+1=\dfrac{11}{5}\)
c: \(=\dfrac{7\cdot28\cdot15}{9\cdot25\cdot14}=\dfrac{1}{2}\cdot\dfrac{28}{25}\cdot\dfrac{5}{3}=\dfrac{140}{150}=\dfrac{14}{15}\)
a, 10 -12 - 8
= 10 - (12 + 8 )
= 10 - 20 = -10
b, 4-(-15)-5+6
= 4+15-5+6
= (4+6) + (15-5)
= 10+10=20
c, 2-12-4-6
= (2-12)-(4+6)
= (-10) - 10
=-20
d, -45-5-(-12)+8
= -45-5+12+8
= [(-45)-5]+(12+8)
= (-50)+20
= -30
\(a.10-12-8\\ =10+\left(-12-8\right)\\ =10+\left(-20\right)=-10\\ b.4-\left(-15\right)-5+6\\ =4+5-5+6\\ =\left(4+6\right)+\left(15-5\right)\\ =10+10=20\\ c.2-12-4-6\\ =\left(2-12\right)+\left(-4-6\right)\\ =-10+\left(-10\right)=-20\\ d.-45-5-\left(-12\right)+8\\ =-45-5+12+8\\ =\left(-45-5\right)+\left(12+8\right)\\ =-50+20=-30\)
\(\dfrac{4^{10}.9^6+3^{12}.8^5}{6^{13}.4-2^{16}.3^{12}}\)
\(=\dfrac{\left(2^2\right)^{10}.\left(3^2\right)^6+3^{12}.\left(2^3\right)^5}{\left(2.3\right)^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{13}.3^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{15}.3^{13}-2^{16}.3^{12}}\)
\(=\dfrac{2^{15}.3^{12}.\left(2^5+1\right)}{2^{15}.3^{13}.\left(3-2\right)}\)
\(=\dfrac{2^5+1}{3-2}\)
\(=\dfrac{32+1}{1}=33\)
a. 342 . 67 + 342 . 16 + 658 . 83
= 342. (67+16) + 658 . 83
= 342 . 83 + 658 . 83
= 83 . (342 + 658)
= 83 . 1000 = 83 000
b. (- 2) + 4 + (- 6) + 8 + (- 10) + 12
= [ (- 2) + 12 ] + [4 + (- 10)] + [(- 6) +8]
= 10 + 6 + 2 = 18