3 mẫu 2n - mẫu 3 =81
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\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26+12}{81}=\dfrac{38}{81}\)
\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5+56}{64}=\dfrac{61}{64}\)
\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26}{81}+\dfrac{4\times3}{27\times3}=\dfrac{26}{81}+\dfrac{12}{81}=\dfrac{38}{81}\)
\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5}{64}+\dfrac{7\times8}{8\times8}=\dfrac{5}{64}+\dfrac{56}{64}=\dfrac{61}{64}\)
\(\frac{5}{2n+1}=\frac{5}{n\times125}\)
\(\Leftrightarrow2n+1=125n\)
\(\Leftrightarrow123n=1\)
\(\Leftrightarrow n=\frac{1}{123}\)
Vậy n=...
Bài 1:
a: 3/4=6/8
5/8=5/8
b: 1/3=5/15
4/5=12/15
c: 3/4=18/24
9/24=9/24
Ta đặt: A = \(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
\(A=1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}\)
\(\Rightarrow3A=3+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}\)
\(\Rightarrow3A-A=\left(3+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}\right)-\left(1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}\right)\)
\(\Rightarrow2A=3-\frac{1}{3^4}\)
\(\Rightarrow A=\left(3-\frac{1}{3^4}\right):2\)
Giải
1+ 1 /3+1/9+1/27+1/81+1/243+1/729.
Đặt:
S = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729
Nhân S với 3 ta có:
S x 3 = 3 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243
Vậy:
S x 3 - S = 3 - 1/243
2S = 2186 / 729
S = 2186 / 729 : 2
S = 1093/729
\(\dfrac{7\times2}{1\times2}=\dfrac{14}{2},\dfrac{9}{2};\dfrac{81\times3}{7\times3}=\dfrac{243}{21},\dfrac{9}{21}\\ \dfrac{4\times2}{3\times2}=\dfrac{8}{6},\dfrac{16}{6};\dfrac{5\times3}{2\times3}=\dfrac{15}{6},\dfrac{19\times2}{3\times2}=\dfrac{38}{6}\)
\(\dfrac{3}{2}v\text{à}\dfrac{5}{8}\\ MSC:8\\ \dfrac{3}{2}=\dfrac{3\times4}{2\times4}=\dfrac{18}{8};\dfrac{5}{8}\\ \dfrac{1}{3}v\text{à}\dfrac{4}{5}\\ MSC:15\\ \dfrac{1}{3}=\dfrac{1\times5}{3\times5}=\dfrac{5}{15};\dfrac{4}{5}=\dfrac{4\times3}{5\times3}=\dfrac{12}{15}\\ \dfrac{3}{4}v\text{à}\dfrac{9}{24}\\ MSC:24\\ \dfrac{3}{4}=\dfrac{3\times6}{4\times6}=\dfrac{18}{24}\)
a: 3/2=12/8
5/8=5/8
b: 1/3=5/15
4/5=12/15
c: 3/4=18/24
9/24=9/24