b, (2 / 11x13+2 / 13x15+...........+ 2 / 19x21)x462-[0,04;(x+1,05)] : 0,12 = 19
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(1/11-1/13+1/13-1/15+.....+1/19-1/21)*462-y=19
(1/11-1/21)*462-y=19
10/231*462-y=19
20-y=19
y=1
Tìm \(x\) biết:
(\(\dfrac{2}{11\times13}\) + \(\dfrac{2}{13\times15}\)+...+ \(\dfrac{2}{19\times21}\)) x 462 - (204: (\(x-105\)):12) =19
(\(\dfrac{1}{11}-\dfrac{1}{13}\)+ \(\dfrac{1}{13}\) - \(\dfrac{1}{15}\)+...+ \(\dfrac{1}{19}\) - \(\dfrac{1}{21}\)) x 462 - (204 : (\(x\) -105):12) =19
(\(\dfrac{1}{11}\) - \(\dfrac{1}{21}\)) x 462 - \(\dfrac{204:(x-105)}{12}\) = 19
\(\dfrac{10}{213}\) x 462 - \(\dfrac{204:\left(x-105\right)}{12}\) = 19
20 - \(\dfrac{204:\left(x-105\right)}{12}\) = 19
204:(\(x\) - 105):12 = 20 - 19
204:(\(x-105\)):12 = 1
204: (\(x\) - 105) = 12
\(x-105\) = 204: 12
\(x\) - 105 = 17
\(x\) = 17 + 105
\(x\) = 122
2/(11x13) = 1/11 - 1/13 ; 2/(13x15) = 1/13 - 1/15 ; 2/(15x17) = 1/15 - 1/17 ; 2/(17x19) = 1/17 - 1/19 ; 2/(19x21) = 1/19 - 1/21
2/(11x13) + 2/(13x15) + 2/(15x17) + 2/(17x19) 2/(19x21) =
1/11 - 1/13 + 1/13 - 1/15 + 1/15 - 1/17 + 1/17 - 1/19 + 1/19 - 1/21 = 1/11 - 1/21 = 101231
Hay: 10/231 x 462 - X = 19
20 - X = 19
X = 20 - 19
X = 1,đó là phần b
\(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
Ta có:
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+....+\frac{1}{19}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(\frac{10}{231}-x+\frac{221}{231}=\frac{4}{3}\)
\(\frac{10}{231}-x=\frac{4}{3}-\frac{221}{231}=\frac{29}{77}\)
\(x=\frac{10}{231}-\frac{29}{77}\)
\(x=-\frac{1}{3}\)
2/(11x13) = 1/11 - 1/13 ; 2/(13x15) = 1/13 - 1/15 ; 2/(15x17) = 1/15 - 1/17 ; 2/(17x19) = 1/17 - 1/19 ; 2/(19x21) = 1/19 - 1/21
2/(11x13) + 2/(13x15) + 2/(15x17) + 2/(17x19) 2/(19x21) =
1/11 - 1/13 + 1/13 - 1/15 + 1/15 - 1/17 + 1/17 - 1/19 + 1/19 - 1/21 = 1/11 - 1/21 = 101231
Hay: 10/231 x 462 - X = 19
20 - X = 19
X = 20 - 19
X = 1
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