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\(3^{x+1}\) + 3\(^{x+2}\) - 2 \(\times\) 3\(^x\) = 270
3\(^x\).(3 + 32 - 2) = 270
3\(^x\).10 = 270
3\(^x\) = 270 : 10
3\(^x\) = 27
3\(^x\) = 33
\(x\) = 3
Vậy \(x\) = 3
3x+1+3x+2-2 . 3x=270
3x . 3+3x . 32-2 . 3x=270
3x . (3+9-2) =270
3x . 10 =270
3x =270 : 10 = 27 = 33
=>x=3
3^x+2 + 3^x = 270
3^x . 9 + 3^x = 270
3^x ( 1+9)= 270
3^x . 10 = 270
3^x = 27
3^x = 3^3
=> x= 3
\(3^{x+4}+3^{x+2}=270\)
\(3^{x+2+2}+3^{x+2}=270\)
\(3^{x+2}\cdot3^2+3^{x+2}\cdot1=270\)
\(3^{x+2}\left(3^2+1\right)=270\)
\(3^{x+2}\cdot10=270\)
\(3^{x+2}=270:10\)
\(3^{x+2}=27\)
\(3^{x+2}=3^3\)
\(x+2=3\)
\(x=1\)
\(3^{x+2}+3^x=270\)
=> \(3^x\cdot3^2+3^x\cdot1=270\)
=> \(3^x\left(3^2+1\right)=270\)
=> \(3^x\cdot10=270\)
=> \(3^x=270:10=27\)
=> \(x=3\)
3x+2 + 3x = 270
=> 3x x 32 + 3x = 270
3x x(32 + 1) =270
3x x 10 = 270
3x = 27
3x = 33
=> x = 3
\(\left(x-2\right)\times3-270:45=120\)
\(\Rightarrow\left(x-2\right)\times3-6=120\)
\(\Rightarrow\left(x-2\right)\times3=120+6\)
\(\Rightarrow\left(x-2\right)\times3=126\)
\(\Rightarrow x-2=126:3\)
\(\Rightarrow x-2=42\)
\(\Rightarrow x=42+2\)
\(\Rightarrow x=44\)
Vậy x = 44
_Chúc bạn học tốt_
\(\left(x-2\right)\cdot3-270:45=120\)
\(\left(x-2\right)\cdot3-6=120\)
\(\left(x-2\right)\cdot3=120+6\)
\(\left(x-2\right)\cdot3=126\)
\(x-2=42\)
\(x=44\)
3\(^x\) + 3\(^{x+2}\) = 270
3\(^x\).(1+ 32) = 270
3\(^x\). (1 + 9) = 270
3\(^x\).10 = 270
3\(^x\) = 270 : 10
3\(^x\) = 27
3\(^x\) = 33
\(x=3\)
Vậy \(x=3\)
\(3^x+3^{x+2}=270\)
\(1.3^x+3^x.3^2=270\)
\(1.3^x+3^x.9=270\)
\(\left(1+9\right).3^x=270\)
\(10.3^x=270\)
\(3^x=270:10\)
\(3^x=27\)
\(3^x=3^3\)
\(x=3\)