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a) -(-35) + (-28) + 65 + (-72)
= 35 + (-28) + 65 + (-72)
= (35 + 65) + [-28 + (-72)]
= 100 + (-100)
= 0
b) 17.92 + 114.83 + 17.23 - (-83)
= 17.92 + 114.83 + 17.23 + 83 [Lên cấp 2 thì cũng nên đổi dấu nhân thành dấu chấm rồi nhé =)))]
= 17.92 + 114.83 + 17.23 + 83.1
= 17.(92+23) + 83.(114+1)
= 17.115 + 83.115
= (17+83).115
= 100.115
= 11500
c) |-19| + [(-19) + |71| + 43] - (43 - 29 - 13)
= 19 + [(-19) + 71 + 43] - 43 + 29 + 13 (Quy tắc phá ngoặc)
= 19 + [52 + 43] - 43 + 29 + 13
= 19 + 95 - 43 + 29 + 13
= 114 - 43 + 29 + 13
= 71 + 29 + 13
= 100 + 13
= 113
d) 2029 - {[39 - (22.3 -21)2] : 3 + 20180}
= 2029 - {[39 - (4.3 -21)2] : 3 + 1} (ao = 1)
= 2029 - {[39 - (12 -21)2] : 3 + 1}
= 2029 - {[39 - (-9)2] : 3 + 1}
= 2029 - {[39 - 81] : 3 + 1}
= 2029 - {[-42] : 3 + 1}
= 2029 - {-14 + 1}
= 2029 - {-13}
= 2029 + 13
= 2042
1. \(S=1+3+3^2+3^3+........+3^{2019}+3^{2020}\)
\(\Rightarrow3S=3+3^2+3^3+3^4+........+3^{2020}+3^{2021}\)
\(\Rightarrow3S-S=3^{2021}-1\)
\(\Rightarrow2S=3^{2021}-1\)
\(\Rightarrow S=\frac{3^{2021}-1}{2}\)
2. \(\left(3x-2\right)^3=64\)
\(\Leftrightarrow\left(3x-2\right)^3=4^3\)
\(\Leftrightarrow3x-2=4\)
\(\Leftrightarrow3x=6\)
\(\Leftrightarrow x=2\)
Vậy \(x=2\)
[3x-2]^3=64
Ta có:64=4^3
Suy ra:3x-2=4
3x =4+2
3x=6
x=6:3
x=2
a) \(\dfrac{1}{2}-\left(x+\dfrac{1}{3}\right)=\dfrac{5}{6}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{1}{2}-\dfrac{5}{6}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{-1}{3}\)
\(\Rightarrow x=\dfrac{-1}{3}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{-2}{3}\)
b)\(\dfrac{3}{4}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\)
\(\Rightarrow x+\dfrac{1}{2}=\dfrac{3}{4}-\dfrac{4}{5}\)
\(\Rightarrow x+\dfrac{1}{2}=\dfrac{-1}{20}\)
\(\Rightarrow x=\dfrac{-1}{20}-\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{-11}{20}\)
c) \(\dfrac{3}{35}-\left(\dfrac{3}{5}+x\right)=\dfrac{2}{7}\)
\(\Rightarrow\dfrac{3}{5}+x=\dfrac{3}{35}-\dfrac{2}{7}\)
\(\Rightarrow\dfrac{3}{5}+x=\dfrac{-1}{5}\)
\(\Rightarrow x=\dfrac{-1}{5}-\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{-4}{5}\)
d)\(\dfrac{2}{3}.x=\dfrac{4}{27}\)
\(\Rightarrow x=\dfrac{4}{27}:\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{2}{9}\)
e) \(\dfrac{-3}{5}.x=\dfrac{21}{10}\)
\(\Rightarrow x=\dfrac{21}{10}:\dfrac{-3}{5}\)
\(\Rightarrow x=\dfrac{-7}{2}\)
a, \(\dfrac{x-1}{21}\) = \(\dfrac{3}{x+1}\)
( x-1)(x+1) = 21.3
x2 + x - x -1 = 63
x2 = 63 + 1
x2 = 64
x = + - 8
b, 2\(\dfrac{1}{2}\)x + x = 2\(\dfrac{1}{17}\)
x( \(\dfrac{5}{2}\) + 1) = \(\dfrac{35}{17}\)
x = \(\dfrac{35}{17}\) : ( \(\dfrac{5}{2}\)+1)
x = \(\dfrac{35}{17}\) x \(\dfrac{2}{7}\)
x = \(\dfrac{10}{17}\)
c, (x + \(\dfrac{1}{4}\) - \(\dfrac{2}{3}\) ) : ( 2 + \(\dfrac{1}{6}\) - \(\dfrac{1}{4}\)) = \(\dfrac{7}{46}\)
(x - \(\dfrac{5}{12}\)): \(\dfrac{23}{12}\) = \(\dfrac{7}{46}\)
(x - \(\dfrac{5}{12}\)) = \(\dfrac{7}{46}\) x \(\dfrac{23}{12}\)
x - \(\dfrac{5}{12}\) = \(\dfrac{7}{12}\)
x = \(\dfrac{7}{12}\) + \(\dfrac{5}{12}\)
x = 1
d, 2\(\dfrac{1}{3}\)x - 1\(\dfrac{3}{4}\)x + \(2\dfrac{2}{3}\) = 3\(\dfrac{3}{5}\)
x( \(\dfrac{7}{3}\) - \(\dfrac{7}{4}\)) + \(\dfrac{8}{3}\) = \(\dfrac{18}{5}\)
x\(\dfrac{7}{12}\) = \(\dfrac{18}{5}\) - \(\dfrac{8}{3}\)
x\(\dfrac{7}{12}\) = \(\dfrac{14}{15}\)
x = \(\dfrac{14}{15}\) : \(\dfrac{7}{12}\)
x = \(\dfrac{8}{5}\)
1) x - 2 = -6
x = -6 + 2
x = -4
2) -5 . x - ( -3 ) =13
-5 . x = 13 + ( -3 )
-5 . x = 10
x = 10 : ( -5 )
x = -2
-29 + x = -39 - 17
=> -29 + x = -56
=> x = -56 + 29
=> x = -27
Vậy x = -27
\(C=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.....\dfrac{48}{49}.\dfrac{49}{50}=\dfrac{1}{50}\)
a, |x - 1| = 4
\(\orbr{\begin{cases}x-1=4\\x-1=-4\end{cases}}\)
\(\orbr{\begin{cases}x=4+1\\x=-4+1\end{cases}}\)
\(\orbr{\begin{cases}x=5\\x=-3\end{cases}}\)
Vậy x = 4 hoặc x = -3
Các ý sau tương tự
5, 4x-21:2.x-3
=4x-10,5.x-3
=x.(4-10.5)-3
=x.(-6.5)-3
=>-6,5.x=3
x=-6.5:3
x≈-2