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Bài 4:
a) \(\dfrac{x}{2}=\dfrac{2}{4}\)
\(\Rightarrow\dfrac{x}{2}=\dfrac{1}{2}\)
\(\Rightarrow x=2\)
Vậy: \(x=2\)
b) \(-\dfrac{1}{5}=\dfrac{2}{x}\)
\(\Rightarrow x=\dfrac{-5.2}{1}=-10\)
Vậy: \(x=-10\)
c) \(\dfrac{x}{5}=\dfrac{5}{x}\)
\(\Rightarrow x^2=25\)
\(\Rightarrow\left[{}\begin{matrix}x=5\\x=-5\end{matrix}\right.\)
Vậy: \(x\in\left\{5;-5\right\}\)
a) \(B=5+5^2+5^3+...+5^{2022}\)
\(\Rightarrow5B=5^2+5^3+5^4+...+5^{2023}\)
\(\Rightarrow4B=5^{2023}-5\)
b) \(4B+5=5^X\)
Hay \(5^{2023}-5+5=5^X\)
\(5^{2023}=5^x\)
\(\Rightarrow x=2023\)
B = 5 + 52 + 53 +...+ 52022
5.B = 52 + 53 +....+ 52023
5B- B = 52023 - 5
4B = 52023 - 5
b, 4B + 5 = 5\(^x\) ⇒ 52023 - 5 + 5 = 5\(^x\)
5\(^{2023}\) = 5\(x\)
\(x\) = 2023
`a, 1/2 +x=3/4`
`=> x= 3/4 -1/2`
`=> x= 3/4-2/4`
`=>x= 1/4`
`b, 5/2 -x=1/3`
`=> x= 5/2 -1/3`
`=> x= 15/6 - 2/6`
`=>x= 13/6`
`c, 2 . (1/3 +x)=1/5`
`=> 1/3 +x=1/5:2`
`=> 1/3 +x= 1/10`
`=>x= 1/10-1/3`
`=>x= 3/30 - 10/30`
`=>x=-7/30`
`d, 2/3 - (1/2 -x)=1/5`
`=> 1/2-x= 2/3 -1/5`
`=>1/2-x= 10/15 - 3/15`
`=>1/2-x=7/15`
`=>x= 1/2-7/15`
`=>x=1/30`
`1/2 + x = 3/4`
`=> x = 3/4 - 1/2`
`=> x = 1/4`
`5/2 - x = 1/3`
`=> x = 5/2 - 1/3`
`=> x = 13/6`
`2.(1/3 + x) = 1/5`
`=>1/3 + x = 1/10 `
`=> x = 1/10 - 1/3`
`=> x = -7/30`
`2/3 - (1/2 -x)= 1/5`
`=> 1/2 - x = 7/15`
`=> x = 1/2 - 7/15`
`=> x = 1/30`
a) Ta có: \(\dfrac{x}{14}-\dfrac{1}{7}=\dfrac{-3}{4}\)
\(\Leftrightarrow\dfrac{x}{14}=\dfrac{-3}{4}+\dfrac{1}{7}=\dfrac{-21}{28}+\dfrac{4}{28}=\dfrac{-17}{28}\)
hay \(x=\dfrac{-17\cdot14}{28}=\dfrac{-17}{2}\)
Vậy: \(x=-\dfrac{17}{2}\)
B=1+5+5^2+....+5^20
5B=5+5^2+5^3+...+5^21
5B-B=(5+5^2+5^3+...+5^21)-(1+5+5^2+...+5^20)
4B=5^21-1
=>4B+1=5^21
Vì 4B+1=5^x
=>5^x=5^21
=>x=21
Vậy.....
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