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Khoảng cách : `5`
Số số hạng là :
\(\dfrac{526-11}{5}+1=104\)
Tổng dãy là :
\(\dfrac{\left(526+11\right)\times104}{2}=27924\)
h=11+16+...+526=\(\dfrac{\left(526-11\right):5+1\cdot\left(11+526\right)}{2}\)=\(\dfrac{104\cdot537}{2}\)=27924.
a ) \(2x-\left(-17\right)=15\)
\(\Leftrightarrow2x+17=15\)
\(\Leftrightarrow2x=15-17\)
\(\Leftrightarrow2x=-2\)
\(\Leftrightarrow x=-2\div2\)
\(\Leftrightarrow x=-1\)
b ) \(-2x-8=72\)
\(\Leftrightarrow-2x=72+8\)
\(\Leftrightarrow-2x=80\)
\(\Leftrightarrow x=-40\)
a) 2x - ( -17 ) = 15
-> 2x + 17 = 15
2x = 15 - 17
2x = -2
x = \(\frac{-2}{2}\)
x = -1
b) -2x - 8 = 72
-2x = 72 + 8
-2x = 80
x = 80 : ( -2 )
x = -40
c) 3 . \([x-1]\)= 27
x - 1 = \(\frac{27}{3}\)
x - 1 = 9
x = 9 + 1
x = 10
d) \([-2x+5]\)+ 8 = 21
-2x + 5 = 21 - 8
-2x + 5 = 13
-2x = 13 - 5
-2x = 8
x = \(\frac{8}{-2}\)
x = - 4
<=> \(\frac{1}{3.7}+\frac{1}{4.7}+\frac{1}{4.9}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
<=> \(\frac{2}{2.3.7}+\frac{2}{2.4.7}+\frac{2}{2.4.9}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
<=> \(\frac{2}{6.7}+\frac{2}{7.8}+\frac{2}{8.9}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
<=> \(2.\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{\frac{x-1}{x+1}}=\frac{2}{9}\right)\)
<=> \(2.\left(\frac{1}{6}-\frac{\frac{1}{x-1}}{x+1}\right)=\frac{2}{9}\)
<=> \(\frac{1}{6}+\frac{1}{x+1}=\frac{1}{9}\)
<=> \(\frac{1}{x-1}=\frac{1}{6}-\frac{1}{9}\)
<=> \(\frac{1}{x+1}=\frac{1}{18}\)
<=> x + 1 = 18
=> x = 18 - 1
x = 17
a) x + 7 = -12
x = (-12) - 7
x = 19
b) x - 15 = -21
x = (-21) + 15
x = -6
c) 13 - x = 20
x = 13 - 20
x = -7
`@` `\text {Ans}`
`\downarrow`
`135 - 21.x = 72`
`\Rightarrow 21x = 135 - 72`
`\Rightarrow 21x = 63`
`\Rightarrow x = 63 \div 21`
`\Rightarrow x = 3`
Vậy, `x = 3.`
135−21.x=72
⇒21�=135−72⇒21x=135−72
⇒21�=63⇒21x=63
⇒�=63÷21⇒x=63÷21
⇒�=3⇒x=3
Vậy, �=3.x=3