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4.[-2(8:4) + 15(-3) - (-12)]
= 4.[-2.2 - 45 + 12]
= 4.[-4 - 45 + 12]
= 4.[-49 + 12]
= 4.[-37]
= - 148
3.(25 : 5 - 14 : 2) - 5.(6:2)
= 3.(5 - 7) - 5.3
= 3.(-2) - 15
= - 6 - 15
= -21
Đặt tổng trên = A
\(A=\frac{15}{1.2}+\frac{15}{2.3}+\frac{15}{3.4}+...+\frac{15}{19.20}\)
\(A:15=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(A:15=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)
\(A:15=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{19}{20}.15=\frac{57}{4}\)
\(A=\frac{15}{1.2}+\frac{15}{2.3}+\frac{15}{3.4}+...+\frac{15}{19.20}\)
\(A:15=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(A:15=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)
\(A:15=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{19}{20}.15=\frac{57}{4}\)
1) [(52.23-72.2):2].6-7.2
=[(25.8-49.2):2].6-49
=[(200-98):2].6-49
=[102:2].6-49
=51.6-49
=306-49
=257
2)15.(27+18+6)+15.(23+12)
=15.51+15.35
=15.(51+35)
=15.86
=1290
3)(81:33.15):9.(40:8.2)
=(81:27.15):9 .(5.2)
=(3.15):9.10
=45:9.10
=5.10
=50
\(=\frac{2^{18}.2^7.3^{14}.3^3+3^{15}.2^{15}}{2^{10}.2^{15}.3^{15}+3^{14}.3.5.2^{26}}=\frac{2^{25}.3^{17}+3^{15}.2^{15}}{2^{25}.3^{15}+3^{15}.2^{26}.5}=\frac{2^{15}.3^{15}\left(2^{10}.3^2+1\right)}{2^{25}.3^{15}\left(1+2.5\right)}\)
\(=\frac{2^{10}.3^2+1}{2^{10}\left(1+2.5\right)}=\frac{2^{10}.3^2+1}{11.2^{10}}\)
\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)
\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{35}{18}+1-\frac{17}{18}\)
\(< =>\frac{53}{18}-\frac{17}{18}\)
\(< =>2\)
\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)
\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)
\(< =>\frac{2}{7}\cdot\frac{1}{3}\)
\(< =>\frac{2}{21}\)
\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)
\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)
\(< =>\frac{15}{4}\)
a,[15:(-3)+40:(-8)]-3(16:8)
= ( - 5 - 5 ) - 3. 2
= - 10 - 6
= - 16
b, 3 ( 25 : 5 - 14 : 2 ) - 5 ( 6 : 2 )
= 3 . (5 - 7 ) - 5 . 3
= 3 . - 2 - 5 . 3
= - 21
c, [ - 15 : ( - 3 ) ] - 3 [ 2. ( 5 - 9 : 3 ) ]
= 5 - 3 . 4
= - 7
d, - 2 ( - 3 + 8 : 2 - 7 ) - 5 . 4
= - 2 . - 6 - 5 . 4
= 12 - 20
= - 8
e, 7 . [ - 6 : 2 - 15 : ( - 3 ) - 3 ]
= 7 . ( - 3 + 5 - 3)
= - 7
f, 17 . ( - 84 ) + 17 . ( - 16)
= - 1428 - 272
= - 1700
a,[15:(-3)+40:(-8)]-3(16:8)
= ( - 5 - 5 ) - 3. 2
= - 10 - 6
= - 16
b, 3 ( 25 : 5 - 14 : 2 ) - 5 ( 6 : 2 )
= 3 . (5 - 7 ) - 5 . 3
= 3 . - 2 - 5 . 3
= - 21
c, [ - 15 : ( - 3 ) ] - 3 [ 2. ( 5 - 9 : 3 ) ]
= 5 - 3 . 4
= - 7
d, - 2 ( - 3 + 8 : 2 - 7 ) - 5 . 4
= - 2 . - 6 - 5 . 4
= 12 - 20
= - 8
e, 7 . [ - 6 : 2 - 15 : ( - 3 ) - 3 ]
= 7 . ( - 3 + 5 - 3)
= - 7
f, 17 . ( - 84 ) + 17 . ( - 16)
= - 1428 - 272
= - 1700
Đề yêu cầu gì em?
- \(\dfrac{2}{3}\) + \(\dfrac{2}{15}\)
= - \(\dfrac{2\times5}{3\times5}\) + \(\dfrac{2}{15}\)
= \(\dfrac{-10}{15}\) + \(\dfrac{2}{15}\)
= \(\dfrac{-8}{15}\)