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a) \(\dfrac{-15+9+11}{16}=\dfrac{5}{16}\)
b) \(\dfrac{2}{3}\left(1,4+1,6-1,2\right)=\dfrac{2}{3}\times\dfrac{9}{5}=\dfrac{6}{5}\)
c) \(3\dfrac{2}{15}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)-\dfrac{31}{15}=\dfrac{47}{15}-\dfrac{31}{15}=\dfrac{16}{15}\)
Đặt tổng trên = A
\(A=\frac{15}{1.2}+\frac{15}{2.3}+\frac{15}{3.4}+...+\frac{15}{19.20}\)
\(A:15=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(A:15=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)
\(A:15=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{19}{20}.15=\frac{57}{4}\)
\(A=\frac{15}{1.2}+\frac{15}{2.3}+\frac{15}{3.4}+...+\frac{15}{19.20}\)
\(A:15=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(A:15=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)
\(A:15=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{19}{20}.15=\frac{57}{4}\)
\(=\frac{2^{18}.2^7.3^{14}.3^3+3^{15}.2^{15}}{2^{10}.2^{15}.3^{15}+3^{14}.3.5.2^{26}}=\frac{2^{25}.3^{17}+3^{15}.2^{15}}{2^{25}.3^{15}+3^{15}.2^{26}.5}=\frac{2^{15}.3^{15}\left(2^{10}.3^2+1\right)}{2^{25}.3^{15}\left(1+2.5\right)}\)
\(=\frac{2^{10}.3^2+1}{2^{10}\left(1+2.5\right)}=\frac{2^{10}.3^2+1}{11.2^{10}}\)
Hai phân số bằng nhau là \(\dfrac{15}{-10}\) và \(-\dfrac{3}{2}\)
1) [(52.23-72.2):2].6-7.2
=[(25.8-49.2):2].6-49
=[(200-98):2].6-49
=[102:2].6-49
=51.6-49
=306-49
=257
2)15.(27+18+6)+15.(23+12)
=15.51+15.35
=15.(51+35)
=15.86
=1290
3)(81:33.15):9.(40:8.2)
=(81:27.15):9 .(5.2)
=(3.15):9.10
=45:9.10
=5.10
=50
\(\left(-3,2\right).\left(-\dfrac{15}{64}\right)+\left(80\%-2\dfrac{4}{15}\right):3\dfrac{2}{3}=-\dfrac{16}{5}.\left(-\dfrac{15}{64}\right)+\left(\dfrac{4}{5}-\dfrac{34}{15}\right):\dfrac{11}{3}=-\dfrac{16}{5}.\left(-\dfrac{15}{64}\right)+\dfrac{46}{15}:\dfrac{11}{3}=\dfrac{3}{4}+\dfrac{46}{55}=\dfrac{349}{220}\)
a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
Đề yêu cầu gì em?
- \(\dfrac{2}{3}\) + \(\dfrac{2}{15}\)
= - \(\dfrac{2\times5}{3\times5}\) + \(\dfrac{2}{15}\)
= \(\dfrac{-10}{15}\) + \(\dfrac{2}{15}\)
= \(\dfrac{-8}{15}\)