Question

[Từ Hoàng Nam]

(y+1/2)+(y+1/4)+(y+1/8)+(y+1/16)=1 Tìmy

Answer 1

[Ran love Shinichi]

y x 4 + 1/2 + 1/4 + 1/8 +1/16 = 1

y x 4 + 15/16 = 1 

y x 4 = 1/16

y = 1/16 : 4

y = 1/64

Answer 2

[Momozono Nanami]

\(\left(y+\frac{1}{2}\right)+\left(y+\frac{1}{4}\right)+\left(y+\frac{1}{8}\right)+\left(y+\frac{1}{16}\right)=1\)

\(\Rightarrow4y+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)

\(\Leftrightarrow4y+\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)=1\)

\(\Leftrightarrow4y+\frac{15}{16}=1\)

\(\Leftrightarrow4y=\frac{1}{16}\)

\(\Leftrightarrow y=\frac{1}{64}\)