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KV
26 tháng 6 2018
a, ( 5 x y - 15 ) : 5 = 0
( 5 x y - 15 ) = 0 x 5
( 5 x y - 15 ) = 0
5 x y = 0 + 15
5 x y = 15
y = 15 : 5
y = 3
b. 14 x ( y - 7 ) = 210
( y - 7 ) = 210 : 14
( y - 7 ) = 15
y = 15 + 7
y = 22
c. 84 - 4 x ( 2 x y + 1 ) = 48
4 x ( 2 x y + 1 ) = 84 - 48
4 x ( 2 xy + 1 ) = 36
( 2 x y + 1 ) = 36 : 4
( 2 x y + 1 ) = 9
2 x y = 9 - 1
2 x y = 8
y = 8 : 2
y = 4
d. 5 x y - 2009 = 1201
5 x y = 1201 + 2009
5 x y = 3210
y = 3210 : 5
y = 642
26 tháng 6 2018
a. (5.y-15):5=0
=> 5.y-15 = 0
=> 5.y = 15
=> y = 3
b. 14.(y-7) = 210
=> y-7 = 15
=> y = 22
c. 84-4.(2.y+1)=48
=> 4.(2.y+1) = 36
=> 2.y+1 = 9
=> 2.y = 8
=> y = 4
d) 5.y-2009 = 1201
=> 5.y = 3210
=> y = 642
DM
1
T
17 tháng 9 2023
\(a,y+\dfrac{2}{3}=\dfrac{5}{2}\)
\(y=\dfrac{5}{2}-\dfrac{2}{3}\)
\(y=\dfrac{15}{6}-\dfrac{4}{6}\)
\(y=\dfrac{11}{6}\)
\(b,3\dfrac{4}{5}-y=\dfrac{18}{5}\)
\(y=3\dfrac{4}{5}-\dfrac{18}{5}\)
\(y=\dfrac{19}{5}-\dfrac{18}{5}\)
\(y=\dfrac{1}{5}\)
\(c,y-4\dfrac{5}{6}=2\dfrac{1}{6}+\dfrac{5}{6}\)
\(y-\dfrac{29}{6}=\dfrac{13}{6}+\dfrac{5}{6}\)
\(y-\dfrac{29}{6}=\dfrac{18}{6}\)
\(y=\dfrac{18}{6}+\dfrac{29}{6}\)
\(y=\dfrac{47}{6}\)
VL
0
PP
0
LH
3
27 tháng 3 2018
a, \(\frac{2}{5}\)+ y = 1
y = 1 - \(\frac{2}{5}\)
y = \(\frac{3}{5}\)
b, \(\frac{6}{8}\)- y = \(\frac{3}{5}\)
y = \(\frac{6}{8}\)- \(\frac{3}{5}\)
y = \(\frac{3}{20}\)
c, y : 6 = \(\frac{7}{4}\)
y = \(\frac{7}{4}\)x 6
y = \(\frac{21}{2}\)
d, y - \(\frac{1}{3}\)= 5 x \(\frac{2}{3}\)
y - \(\frac{1}{3}\)= \(\frac{10}{3}\)
y = \(\frac{10}{3}\)+ \(\frac{1}{3}\)
y = \(\frac{11}{3}\)
27 tháng 3 2018
a,2/5 + y = 1
y = 1 - 2/5
y = 3/5
b, 6/8 - y = 3/5
y = 6/8 - 3/5
y = 3/10
c, y / 6 = 7/4
y = 7/4 * 6
y = 15/2
d, y - 1/3 = 5 * 2/3
y - 1/3 = 10/3
y = 10/3 + 1/3
y = 11/3
DP
0
H9
HT.Phong (9A5)
CTVHS
22 tháng 7 2023
a) \(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\)
\(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{25}{12}\)
\(\dfrac{1}{2}:y=\dfrac{25}{12}:\dfrac{3}{5}\)
\(\dfrac{1}{2}:y=\dfrac{125}{36}\)
\(y=\dfrac{1}{2}:\dfrac{125}{36}\)
\(y=\dfrac{18}{125}\)
b) \(\dfrac{4}{3}-\dfrac{1}{2}\times y=1\)
\(\dfrac{1}{2}\times y=\dfrac{4}{3}-1\)
\(\dfrac{1}{2}\times y=\dfrac{1}{3}\)
\(y=\dfrac{1}{3}:\dfrac{1}{2}\)
\(y=\dfrac{2}{3}\)
c) \(\dfrac{1}{4}+y:\dfrac{1}{3}=\dfrac{5}{6}\)
\(y:\dfrac{1}{3}=\dfrac{5}{6}-\dfrac{1}{4}\)
\(y:\dfrac{1}{3}=\dfrac{7}{12}\)
\(y=\dfrac{7}{12}\cdot\dfrac{1}{3}\)
\(y=\dfrac{7}{36}\)