Question

[Nguyenvananh33]

xyz=1

T = \(\frac{x}{xy+x+1}+\frac{y}{yz+y+1}+\frac{z}{xz+z+1}\)

Tính tổng

Thanks

Answer 1

[nguyen chi hieu]

T/c:xyz=1

=>x=1;y=1;z=1

=>T=1/1+1+1   +1/1+1+1   +1/1+1+1

=>T=1/3  +1/3  +1/3

=>T=1

Answer 2

[thien ty tfboys]

Ta co : x.y.z=1

Hay : x=1 ; y=1 va z=1

\(\Rightarrow T=\frac{x}{xy+x+1}+\frac{y}{yz+y+1}+\frac{z}{xz+z+1}\)

\(=\frac{1}{1.1+1+1}+\frac{1}{1.1+1+1}+\frac{1}{1.1+1+1}\)

\(=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}\)

\(\Rightarrow\)T=1