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1, -15 + \(x\) = -14 - (-57)
-15 + \(x\) = -14 + 57
\(x\) = -14 + 57 + 15
\(x\) = 43 + 15
\(x\) = 58
2, (-14) + \(x\) - 7 = -10
-14 + \(x\) - 7 = -10
- 21 + \(x\) = - 10
\(x\) = -10 + 21
\(x\) = 11
( 2 x y + 2/15 ) x 3 = 4/5
( 2 x y + 2/15 ) = 4/5 : 3
( 2 x y + 2/15 ) = 4/15
2 x y = 4/15 - 2/15
2 x y = 2/15
y = 2/15 :2
y = 1/15
(2 x y + 2/15) x 3 = 4/5
2 x y + 2/15) = 4/5 : 3
2 x y + 2/15 = 4/15
2 x y = 4/15 - 2/15
2 x y = 2/15
y = 2/15 : 2
y = 1/15
7/9 x (2 - 1/3 x y) = 14/15
(2 - 1/3 x y) = 14/15 : 7/9
(2 - 1/3 x y) = 6/5
2 - y = 6/5 x 1/3
2 - y = 2/5
y = 2/5 + 2
y = 12/5
4/21 + 5 x y - 8/7 = 1/3
4/21 + 5 x y = 1/3 + 8/7
4/21 + 5 x y = 31/21
5 x y = 31/21 - 4/21
5 x y = 9/7
y = 9/7 : 5
y = 9/35
7/12 x y - 3/12 x y = 5
y x (7/12 - 3/12) = 5
y x 1/3 = 5
y = 5 : 1/3
y = 15
\(1\frac{1}{7}-\frac{5}{7}< \frac{x}{7}< 2\frac{1}{14}-1\frac{3}{14}\)
=> \(\frac{8}{7}-\frac{5}{7}< \frac{x}{7}< \frac{29}{14}-\frac{17}{14}\)
=> \(\frac{3}{7}< \frac{x}{7}< \frac{12}{14}\)
=> \(\frac{3}{7}< \frac{x}{7}< \frac{6}{7}\)
=> 3 < x < 6
=> x thuộc { 3 ; 4 ; 5 ; 6 }
5 + ( x + 27 ) = 64
( x + 27 ) = 64 - 5 ( x + 27 ) = 59 x = 59 - 27 x = 32a) \(\Rightarrow x+27=59\Rightarrow x=32\)
b) \(\Rightarrow x-2=39\Rightarrow x=41\)
c) \(\Rightarrow x+5=-322\Rightarrow x=-327\)
d) \(\Rightarrow5x=35\Rightarrow x=7\)
e) \(\Rightarrow4\left(x-5\right)=56\Rightarrow x-5=14\Rightarrow x=19\)
f) \(\Rightarrow15+x=37\Rightarrow x=22\)
g) \(\Rightarrow7\left(13-x\right)=35\Rightarrow13-x=5\Rightarrow x=8\)
h) \(\Rightarrow10\left(x+1\right)=100\Rightarrow x+1=10\Rightarrow x=9\)
7 x 4 - 7 x 6/14 x 6 - 7 x 4
=7 x 4 - 7 x 18/7 - 7 x 4
=7x(4 - 18/7 - 4 )
=7 x (-18/7)
=-18
\(x+7=-12-3\)
\(x+7=-15\)
\(x=-15-7\)
\(x=-22\)
\(13-x=20-\left(-31\right)\)
\(13-x=51\)
\(x=13-51\)
\(x=-38\)
\(2x-41=-19-2\)
\(2x-41=-21\)
\(2x=-21+41\)
\(2x=20\)
\(x=20:2\)
\(x=10\)
\(\left(x-1\right).2+14=30-\left(-14\right)\)
\(2x-2+14=44\)
\(2x-2=44-14\)
\(2x-2=30\)
\(2x=30+2\)
\(2x=32\)
\(x=16\)
cho minh hoi:tap hop cac so co 2 chu so chia het cho va 9
\(\frac{x}{7}=\frac{x+1}{14}\)
\(\Rightarrow\frac{2x}{14}=\frac{x+1}{14}\)
\(\Rightarrow2x=x+1\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
\(\frac{x}{7}=\frac{x+1}{14}\)
\(\Rightarrow\)\(14x=7\left(x+1\right)\)
\(\Rightarrow\)\(14x=7x+7\)
\(\Rightarrow\)\(14x-7x=7\)
\(\Rightarrow\)\(7x=7\)
\(\Rightarrow\)\(x=1\)
Vậy \(x=1\)