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a. 115.(-46)+15.46
=(-115).46+15.46
=(-115+15).46
=-100.46
=-4600
b. -49.42+21.(-102)
=-49.2.21+21.(-102)
=-98.21+21.(-102)
=(-98+-102).21
=-200.21
=-4200
tick nha !!!
a, ( x + 5) + ( x – 9) = x + 2
x + 5 + x -9 = x+2
x+x-x = 2 -5 +9
x= 6
Bài 292: Tính
1 + 2 – 3 -4 + 5+ 6 -7 -8 +9 + ....+ 101 +102 -103 -104 +105.
Bài 293: Đơn giản các biểu thức sau:
a, A = ( a + b) + ( c –d) – ( a +c) – ( b-d)
= a+b+c -d -a-c -b +d
= 0
b, B = ( a –b) – ( c –d)- ( a + d) + ( b + c)
= a-b -c +d -a -d +b+c
= 0
\(=\left(33+85-27+115\right):102-12=-\dfrac{509}{51}\)
x - 3/7 - 3/42 - 3/102 - 3/187 = 2
=> x - [ 3× ( 1/7 - 1/42 - 1/102 - 1/187 ) ] = 2
=> x - 24/77 = 2
=> x = 178/77
k mk vs. Chúc bạn học thật giỏi
x-3/7-3/42-3/102-3/187
=> x=2+3/7+3/42+3/108+3/187
=> x=28/11
Ở trên mk làm lộn . Sorry
k mk vs. Chúc bạn học thật giỏi
\(a,\frac{x+1}{65}+\frac{x+2}{64}=\frac{x+3}{63}+\frac{x+4}{62}\)
\(\Rightarrow\left[\frac{x+1}{65}+1\right]+\left[\frac{x+2}{64}+1\right]=\left[\frac{x+3}{63}+1\right]+\left[\frac{x+4}{62}+1\right]\)
\(\Rightarrow\frac{x+1+65}{65}+\frac{x+2+64}{64}=\frac{x+3+63}{63}+\frac{x+4+62}{62}\)
\(\Rightarrow\frac{x+66}{65}+\frac{x+66}{64}=\frac{x+66}{63}+\frac{x+66}{62}\)
\(\Rightarrow\frac{x+66}{65}+\frac{x+66}{64}=\frac{x+66}{63}+\frac{x+66}{62}=0\)
\(\Rightarrow\left[x+66\right]\left[\frac{1}{65}+\frac{1}{64}-\frac{1}{63}+\frac{1}{62}\right]=0\)
Mà \(\frac{1}{65}+\frac{1}{64}-\frac{1}{63}+\frac{1}{62}\ne0\)
\(\Rightarrow x+66=0\)
\(\Rightarrow x=0-66=-66\)
Auto làm nốt câu b
a, Cộng cả 2 vế với 2
Ta có \(\frac{x+1}{64}+\frac{x+2}{63}+2=\frac{x+3}{62}+\frac{x+4}{61}+2\)
\(\left(\frac{x+1}{64}+\frac{64}{64}\right)+\left(\frac{x+2}{63}+\frac{63}{63}\right)=\left(\frac{x+3}{62}+\frac{62}{62}\right)+\left(\frac{x+4}{61}+\frac{61}{61}\right)\)
=> \(\frac{x+65}{64}+\frac{x+65}{63}=\frac{x+65}{62}+\frac{x+65}{61}\)\(\)
=> \(\frac{x+65}{64}+\frac{x+65}{63}-\frac{x+65}{62}-\frac{x+65}{61}=0\)
=> \(\left(x+65\right)\left(\frac{1}{64}+\frac{1}{63}-\frac{1}{62}-\frac{1}{61}\right)=0\)
Do \(\frac{1}{64}+\frac{1}{63}-\frac{1}{62}-\frac{1}{61}\ne0\)=> \(x+65=0\)
=> \(x=-65\)
b , Lm tương tự như Câu a
Chúc bn hok tốt
\(3.\left(x-1\right)+27=x-102\)
\(3x-3+27=x-102\)
\(3x+24=x-102\)
\(3x-x=-102-24\)
\(2x=-126\)
\(x=-63\)
\(3\left(x-1\right)+21=x-102\)
\(\Rightarrow3x-3+21=x-102\)
\(\Rightarrow3x+18=x-102\)
\(\Rightarrow3x-x=-102-18\)
\(\Rightarrow2x=-120\)
\(\Rightarrow x=-60\)
Vậy x = -60
mk nhầm:
\(3\left(x-1\right)+27=x-102\)
\(\Rightarrow3x-3+27=x-102\)
\(\Rightarrow24=x-102-3x\)
\(\Rightarrow-2x=102+24\)
\(\Rightarrow-2x=126\)
\(\Rightarrow x=-65\)
\(x+3x\cdot\left(102-3,33\right)=115\)
\(\Rightarrow x+306x-9,99x=115\)
\(\Rightarrow x\cdot\left(1+306-9,99\right)=105\)
\(\Rightarrow x\cdot297,01=105\)
\(\Rightarrow x=\dfrac{105}{297,01}\)
\(\Rightarrow x=\dfrac{1500}{4243}\)