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1: =>x=8-35=-27
2: =>15-4+x=6
=>x+11=6
hay x=-5
3: =>-30+25-x=-1
=>x+5=1
hay x=-4
4: =>x-(-13)=-8
=>x+13=-8
hay x=-21
5: =>x-29-17+38=-9
=>x-8=-9
hay x=-1
1) Ta có: \(\left(-\dfrac{2}{3}\right)^2\cdot\dfrac{-9}{8}-25\%\cdot\dfrac{-16}{5}\)
\(=\dfrac{4}{9}\cdot\dfrac{-9}{8}-\dfrac{1}{4}\cdot\dfrac{-16}{5}\)
\(=\dfrac{-1}{2}+\dfrac{4}{5}\)
\(=\dfrac{-5}{10}+\dfrac{8}{10}=\dfrac{3}{10}\)
2) Ta có: \(-1\dfrac{2}{5}\cdot75\%+\dfrac{-7}{5}\cdot25\%\)
\(=\dfrac{-7}{5}\cdot\dfrac{3}{4}+\dfrac{-7}{5}\cdot\dfrac{1}{4}\)
\(=\dfrac{-7}{5}\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=-\dfrac{7}{5}\)
3) Ta có: \(-2\dfrac{3}{7}\cdot\left(-125\%\right)+\dfrac{-17}{7}\cdot25\%\)
\(=\dfrac{-17}{7}\cdot\dfrac{-5}{4}+\dfrac{-17}{7}\cdot\dfrac{1}{4}\)
\(=\dfrac{-17}{7}\cdot\left(\dfrac{-5}{4}+\dfrac{1}{4}\right)\)
\(=\dfrac{17}{7}\)
4) Ta có: \(\left(-2\right)^3\cdot\left(\dfrac{3}{4}\cdot0.25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=\left(-8\right)\cdot\left(\dfrac{3}{4}\cdot\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)
\(=\left(-8\right)\cdot\dfrac{3}{16}:\dfrac{54-28}{24}\)
\(=\dfrac{-3}{2}\cdot\dfrac{24}{26}\)
\(=\dfrac{-72}{52}=\dfrac{-18}{13}\)
1. 11(x-9)=77
x-9=7
x=16
2. 4(x-3)=48
x-3=12
x=15
3.3(x-8)=81
(x-8)=27
x=35
[x+1]:25=3
x+1=25*3
x+1=75
x=75-1=74
12:[x-3]=6x-3=12:6
x-3=2
x=3+2
x=5
4[x-1]:5=8
4[x-1]=5.8
4[x-1]=40
x-1=40:4
x-1=10
x=10+1=11
9[x+3]-25=11
9[x+3]=25+11=36
x+3=36:9=4
x=4-3=1
75:[x-2]=1
x-2=75:1=75
x=75+2=77
[2x-5]-7=6
2x-5=7+6=13
2x=13+5=18
x=18:2=9
k mk nha mk cầu xin bn đó công mk làm mà
\(3^x\cdot8=24\Rightarrow3^x=3\Rightarrow3^x=3^1\Rightarrow x=1\)
\(5^x+1=25\Rightarrow5^x=24\Rightarrow5^x=5^{1,9746...}\Rightarrow x=1,9746...\)
`x + 25%x = 1 3/8`
`=> 5/4x = 11/8`
`=> 10/8x = 11/8`
`=> x = 11/8:10/8`
`=> x = 11/10`
Vậy `...`
\(x+25\%x=1\dfrac{3}{8}\)
\(x+\dfrac{1}{4}x=\dfrac{11}{8}\)
\(x.\left(\dfrac{1}{4}+1\right)=\dfrac{11}{8}\)
\(x.\dfrac{5}{4}=\dfrac{11}{8}\)
\(x=\dfrac{11}{8}:\dfrac{5}{8}\)
\(x=\dfrac{11}{8}\times\dfrac{8}{5}\)
\(x=\dfrac{11}{10}\)
\(Vẫy=\dfrac{11}{10}\)