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\(=\dfrac{15}{23}\times\dfrac{69}{54}\times\dfrac{27}{15}\\ =\dfrac{3}{2}\)
a. \(\left(\dfrac{17}{2}+\dfrac{1}{2}+1\right).\dfrac{4}{7}\)
\(=\dfrac{19}{2}.\dfrac{4}{7}=\dfrac{38}{7}\)
b. \(\dfrac{2727}{2323}.\dfrac{69}{54}\)
\(=\dfrac{27}{23}.\dfrac{23.3}{27.2}=\dfrac{3}{2}\)
2. Chiều cao hình bình hành là: 1200 : 60 = 20 cm
a, \(\dfrac{17}{2}\) \(\times\) \(\dfrac{4}{7}\) + \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{7}\) b, \(\dfrac{1515}{2323}\) \(\times\) \(\dfrac{69}{54}\) \(\times\) \(\dfrac{2727}{1515}\)
= \(\dfrac{17}{2}\) \(\times\) \(\dfrac{4}{7}\) + \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{7}\) \(\times\) 1 = \(\dfrac{15}{23}\) \(\times\) \(\dfrac{23}{18}\) \(\times\) \(\dfrac{27}{15}\)
= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{17}{2}\) + \(\dfrac{1}{2}\) + 1) = \(\dfrac{27}{18}\)
= \(\dfrac{4}{7}\) \(\times\) ( 9 + 1) = \(\dfrac{3}{2}\)
= \(\dfrac{4}{7}\times10\)
= \(\dfrac{40}{7}\)
Bài 2: Chiều cao của hình bình hành là:
1200 : 60 = 20 cm
Đổi 20 cm = 2 dm
Đáp số: 2 dm
\(\dfrac{1111\times5}{1515\times7}=\dfrac{1111\times5}{303\times5\times7}=\dfrac{1111}{2121}\)
\(=\dfrac{11\times101}{21\times101}=\dfrac{11}{21}\)
32x50 / 48x75=1600/3600=4/9
63x81 /135x75=5103/10125=63/125
1111x5x1515x7=58 910 775
duyệt mình đi các bạn !
18/15*35/36+18/15*15/18-18/15*20/72
5/6+1/1-1/3
5/6+6/6-2/6
3/2
=\(\dfrac{1515x484848x31}{2424x626262x15}\)
=\(\dfrac{101x20202}{101x20202}\)
= 1.
\(x\times1515+x\times4545=2\)
\(x\times\left(1515+4545\right)=2\)
\(x\times6060=2\)
\(x=\dfrac{2}{6060}=\dfrac{1}{3030}\)
\(x.1515+x.4545=2\)
\(\Rightarrow x.\left(1515+4545\right)=2\)
\(\Rightarrow x.6060=2\)
\(\Rightarrow x=2:6060\)
\(\Rightarrow x=\dfrac{1}{3030}\)