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\(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
\(=\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
\(=-1+1-\frac{1}{2}=0-\frac{1}{2}\)
\(=\frac{-1}{2}\)
\(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
\(=\left(1\frac{4}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
\(=1+1+0,5=2,5\)
\(\frac{13}{25}+\frac{4}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
= \(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
= \(-1+1-\frac{1}{2}=-\frac{1}{2}\)
\(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
=\(\left(1\frac{4}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
= \(1+1+0,5=2,5\)
A em tự tính nhé
b) B = 1+ 3 + 32+...+399
3B = 3+ 32+33+...+3100
do đó 3B-B= (3+32+33+...+3100) - ( 1+3+32+...+399)
2B= 3100-1
B= (3100-1) : 2
c) \(C=1+\frac{1}{3}+\frac{1}{6}+...+\frac{2}{x.\left(x+1\right)}\)
\(C=1+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{x.\left(x+1\right)}\)
\(C=1+\frac{1}{2}.\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{x.\left(x+1\right)}\right)\)
\(C=1+\frac{1}{2}.\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{x.\left(x+1\right)}\right)\)
\(C=1+\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right)\)
\(C=1+\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{x+1}\right)\)
Phần c thế này thôi vì ko có giá trị x cụ thể .
d) \(D=\frac{9}{8}.\frac{16}{15}.\frac{25}{24}.....\frac{8100}{8099}\)
\(D=\frac{9.16.25....8100}{8.15.24....8099}\)
\(D=\frac{3.3.4.4.5.5....90.90}{2.4.3.5.4.6.....89.91}\)
\(D=\frac{\left(3.4.5...90\right).\left(3.4.5...90\right)}{\left(2.3.5...89\right).\left(4.5.6...91\right)}\)
\(D=\frac{3.4.5...90}{2.3.4...89}.\frac{3.4.5...90}{4.5.6...91}\)
\(D=\frac{90}{2}.\frac{3}{91}\)
\(D=45.\frac{3}{91}=\frac{135}{91}\)
5/-8 + 14/25 - 6/16
= 5/-8 + 14/25 - 3/8
= -5/8 + 14/25 - 3/8
= ( -5/8 - 3/8 ) + 14/25
= -1 + 14/25
= -11/25
chúc bn hok tốt
\(x-\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
\(x=\frac{3}{6}+\left(\frac{1}{9}-\frac{3}{5}\right)\)
\(x=\frac{3}{6}+\left(-\frac{22}{45}\right)\)
\(x=\frac{1}{90}\)
\(\frac{-12}{25}.\frac{3}{4}-x+\frac{6}{-11}-\frac{5}{6}=0\)
\(\frac{-9}{25}-x+\left(\frac{-91}{66}\right)=0\)
\(\frac{-9}{25}-x=0+\left(\frac{-91}{66}\right)\)
\(\frac{-9}{25}-x=\frac{-91}{66}\)
\(x=\left(\frac{-9}{25}\right)-\left(\frac{-91}{66}\right)\)
\(x=\frac{1681}{1650}\)
Cac ban giup mik voi, mik k cho! ( 10 k cho 3 nguoi dau tien tra loi cau hoi cua mik)
\(\frac{1+0,6-\frac{3}{7}}{\frac{8}{3}+\frac{8}{5}-\frac{8}{7}}=\frac{\frac{3}{3}+\frac{3}{5}-\frac{3}{7}}{\frac{8}{3}+\frac{8}{5}-\frac{8}{7}}=\frac{3.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{7}\right)}{8.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{7}\right)}=\frac{3.1}{8.1}=\frac{3}{8}\)
\(\frac{\frac{1}{3}+0,25-\frac{1}{5}+0,125}{\frac{7}{6}+\frac{7}{8}-0,7+\frac{7}{16}}=\frac{\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+\frac{1}{8}}{\frac{7}{6}+\frac{7}{8}-\frac{7}{10}+\frac{7}{16}}=\frac{1.\left(\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+\frac{1}{8}\right)}{7.\left(\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+\frac{1}{8}\right)}=\frac{1.1}{7.1}=\frac{1}{7}\)
=>\(\frac{3}{8}-\frac{1}{7}=\frac{13}{56}\)
a) \(\frac{1}{6}\) \(\times\)\(x\)= \(\frac{1}{9}\)
\(x\)= \(\frac{1}{9}\) \(:\) \(\frac{1}{6}\)
\(x\)= \(\frac{2}{3}\)
b) \(\frac{15}{16}\) \(:\) \(x\) = \(\frac{5}{6}\)
\(x\)= \(\frac{15}{16}\)\(:\) \(\frac{5}{6}\)
\(x\)= \(\frac{9}{8}\)
1. Câu tl lun nà ~
( x-1). 3= 18.2
(x-1). 3 = 36
(x-1) = 36:3
(x-1) = 12
x = 12+1
x = 13
2. Tl lun ó
(64-4x).4= 16.15
(64-4x).4= 240
(64-4x) = 240:4
60x = 60
x= 60:60
x= 1
I x - 1/6 I - 6/16 = 25%
=> I x - 1/6 I- 6/16 = 1/4
=>I x - 1/6 I = 5/8
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{6}=\frac{5}{8}\\x-\frac{1}{6}=-\frac{5}{8}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{19}{24}\\x=-\frac{11}{24}\end{cases}}\)
vậy x = 19/24 , x = -11/24
\(\left|x-\frac{1}{6}\right|-\frac{6}{16}=25\%\)
\(\left|x-\frac{1}{6}\right|-\frac{3}{8}=\frac{2}{8}\)
\(\left|x-\frac{1}{6}\right|=\frac{2}{8}+\frac{3}{8}\)
\(\left|x-\frac{1}{6}\right|=\frac{5}{8}\)
=> 2 trường hợp:
1 là \(x-\frac{1}{6}=\frac{5}{8}\)
2 là \(x-\frac{1}{6}=\frac{-5}{8}\)
Trường hợp 1:\(x=\frac{5}{8}+\frac{1}{6}=\frac{19}{24}\)
Trường hợp 2:\(x=\frac{-5}{8}+\frac{1}{6}=\frac{-11}{24}\)
Hội con 🐄 chúc bạn học tốt!!!