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a) 125 : x + ( 32 + 15 ) = 72
125 : x + 47 = 72
125 : x = 72 - 47
125 : x = 25
x = 125 : 25
x = 5
b) ( 35 + 135 ) - 2 . x = 86
170 - 2 . x = 86
2 . x = 170 - 86
2 . x = 84
x = 84 : 2
x = 42
c) 7 . x - 5 = 65
7 . x = 65 + 5
7 . x = 70
x = 70 : 7
x = 10
A) 125 / x + (32 + 15) = 72
125 / x + 47 = 72
125 / x = 72 - 47
125 / x = 25
x = 125 / 25
x = 5
1) Do x chia hết cho 15, x chia hết cho 25
=> x \(\in\)BC ( 15;25 )
Mà \(15=3.5\)
\(25=5^2\)
=> BCNN ( 15,25 ) = \(5^2.3=75\)
=> BC ( 15;25 ) = B ( 75 ) = { 0 ; 75 ; 150 ; 225 ; ...}
Mà 75 < x < 200
=> x = { 75 ; 150 }
2) Do 35 chia hết cho x
42 chia hết cho x
=> x \(\in\)ƯC ( 35;42 )
Mà \(35=5.7\)
\(42=2.3.7\)
=> UCLN ( 35,42 ) = 7
=> UC ( 35;42 ) = Ư ( 7 ) = { - 7 ; -1 ; 1 ; 7 }
Mà x > 1
=> x = { 1 ; 7 }
a) 125 : X + (32 + 15) = 72
125 : X + 47 = 72
X + 47 = 72 x 125
X + 47 = 62270
X = 62270 - 47
X = 62223
b) (35 + 15) - 2 x X = 86
50 - 2 x X = 86
50 - X = 86 + 2
50 - X = 88
X = 88+ 50
X = 138
35 x 34 + 35 x 65 + 65 x 75 + 65 x 45
= ( 35 x 34 + 35 x 65 ) + ( 65 x 75 + 65 x 45 )
= 35 x ( 34 + 65 ) + 65 x ( 75 + 45 )
= 35 x 99 + 65 x 120
= 3465 + 7800
= 11265
\(\frac{3}{2}+\frac{3}{14}+\frac{3}{15}+...+\frac{6}{\left(x-3\right).x}=\frac{96}{49}\)
\(\frac{6}{\left(1.2\right).2}+\frac{6}{\left(2.7\right).2}+...+\frac{6}{\left(x-3\right).x}=\frac{96}{49}\)
\(\frac{6}{1.4}+\frac{6}{4.7}+...+\frac{6}{\left(x-3\right).x}=\frac{96}{49}\)
\(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{\left(x-3\right).x}=\frac{96}{49.2}\)
\(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{\left(x-3\right)}-\frac{1}{x}=\frac{96}{98}\)
=> \(1-\frac{1}{x}=\frac{48}{49}\)
=> \(\frac{1}{x}=\frac{1}{49}\)
=> \(x=49\)
\(\left(x+35\right)+\left(x+65\right)=200\)
\(x+35+x+65=200\)
\(2x+100=200\)
\(2x=200-100\)
\(2x=100\)
\(x=100:2\)
\(x=50\)
(\(x\) + 35) + (\(x\) + 65) = 200
\(x\) + 35 + \(x\) + 65 = 200
(\(x\) + \(x\)) + ( 35 + 65) = 200
2\(x\) + 100 = 200
2\(x\) = 200 - 100
2\(x\) = 100
\(x\) = 100 : 2
\(x\) = 50
Vậy \(x\) = 50