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(x-1)^3=-64 x.(x+5)=0 =>TH1:x=0:TH2x+5 =0 =>x=5
=>(x-1)^3=-3^4 cac bai khac tuong tu nha ban
=>x-1=-3
=>x=-4
a: =>(x-5)(x+5)=0
=>x=5 hoặc x=-5
b: \(\Leftrightarrow\left[{}\begin{matrix}x+1=2\\x+1=-2\end{matrix}\right.\Leftrightarrow x\in\left\{1;-3\right\}\)
c: =>x-3=4
hay x=7
d: =>x+1=7
hay x=6
e: =>x=0 và y-2=0
hay x=0 và y=2
\(\left(x-1\right).\left(x-1\right)^2-64=0\)
\(\left(x-1\right)^3=0+64=64\)
\(\left(x-1\right)^3=4^3\)
\(\Rightarrow x-1=4\)
\(x=4+1=5\)
0 : x = 0
x với mọi giá trị vì 0 chia số nào cũng bằng 0
4^x = 64
=> 4x = 43
=> x = 3
9x-1 = 9
=> x-1 = 1
=> x = 1+1
Tim x:
a,-16+23+x=-16
x=-16+16+23
x=23
b,(x-1)-(-2)=0
x-1+2=0
x+1=0
x=-1
c,|x-1|=0
x-1=0
x=1
d,|9-x|=64+(-7)
\(|9-x|=57\)
\(\orbr{\begin{cases}9-x=57\\9-x=-57\end{cases}}\)
\(\orbr{\begin{cases}x=-48\\x=66\end{cases}}\)
\(4^{x-1}-64=0\)
\(\Leftrightarrow4^{x-1}=64\)
\(\Leftrightarrow4^{x-1}=4^3\)
\(\Rightarrow x-1=3\Leftrightarrow x=4\)
a) \(\left|x\right|-\frac{7}{6}=\frac{9}{15}\)
=> \(\left|x\right|=\frac{9}{15}+\frac{7}{6}=\frac{53}{30}\)
=> \(\orbr{\begin{cases}x=\frac{53}{30}\\x=-\frac{53}{30}\end{cases}}\)
b) \(\left|x-\frac{4}{3}\right|=\frac{1}{6}\)
=> \(\orbr{\begin{cases}x-\frac{4}{3}=\frac{1}{6}\\x-\frac{4}{3}=-\frac{1}{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{7}{6}\end{cases}}\)
c) \(\left|x-\frac{4}{3}\right|-\frac{1}{3}=\frac{1}{2}\)
=> \(\left|x-\frac{4}{3}\right|=\frac{1}{2}+\frac{1}{3}\)
=> \(\left|x-\frac{4}{3}\right|=\frac{5}{6}\)
=> \(\orbr{\begin{cases}x-\frac{4}{3}=\frac{5}{6}\\x-\frac{4}{3}=-\frac{5}{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{13}{6}\\x=\frac{1}{2}\end{cases}}\)
d) \(\frac{8}{3}-\left|\frac{7}{9}-x\right|=-\frac{1}{5}\)
=> \(\left|\frac{7}{9}-x\right|=\frac{43}{15}\)
=> \(\orbr{\begin{cases}\frac{7}{9}-x=\frac{43}{15}\\\frac{7}{9}-x=-\frac{43}{15}\end{cases}}\Rightarrow\orbr{\begin{cases}x=-\frac{94}{45}\\x=\frac{164}{45}\end{cases}}\)
e) \(\left|x-\left(\frac{1}{4}\right)^2\right|-\frac{25}{64}=0\)
=> \(\left|x-\frac{1}{16}\right|=\frac{25}{64}\)
=> \(\orbr{\begin{cases}x-\frac{1}{16}=\frac{25}{64}\\x-\frac{1}{16}=-\frac{25}{64}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{29}{64}\\x=-\frac{21}{64}\end{cases}}\)
f) \(\left(x-\frac{1}{4}\right)^2+\frac{17}{64}=\frac{21}{32}\)
=> \(\left(x-\frac{1}{4}\right)^2=\frac{25}{64}\)
=> \(\left(x-\frac{1}{4}\right)^2=\left(\frac{5}{8}\right)^2\)
=> \(\orbr{\begin{cases}x-\frac{1}{4}=\frac{5}{8}\\x-\frac{1}{4}=-\frac{5}{8}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{7}{8}\\x=-\frac{3}{8}\end{cases}}\)